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Bicycle Pedal Arm The length of a bicycle pedal arm is \(0.152 \mathrm{~m}\), and a downward force of \(111 \mathrm{~N}\) is applied to the pedal by the rider's foot. What is the magnitude of the torque about the pedal arm's pivot point when the arm makes an angle of (a) \(30^{\circ}\), (b) \(90^{\circ}\). and (c) \(180^{\circ}\) with the vertical?

Short Answer

Expert verified
(30^\text{circ}): 8.436 \text{ N}\text{m}; (90^\text{circ}): 16.872 \text{ N}\text{m}; (180^\text{circ}): 0 \text{ N}\text{m}

Step by step solution

01

- Understand Torque

Torque (\tau) is given by the formula \(\tau = r \times F \times \text{sin}(\theta)\), where \(r\) is the length of the lever arm, \(F\) is the force applied, and \(\theta\) is the angle between the force and the lever arm.
02

- Identify Given Values

We have the length of the pedal arm \(r = 0.152 \text{ m}\), the downward force \(F = 111 \text{ N}\), and different angles \(\theta = 30^\text{circ}, 90^\text{circ}, 180^\text{circ}\).
03

- Calculate Torque for \(30^\text{circ}\)

Substitute into the torque formula: \(\tau = 0.152 \text{ m} \times 111 \text{ N} \times \text{sin}(30^\text{circ})\). Since \(\text{sin}(30^\text{circ}) = 0.5\), \(\tau = 0.152 \text{ m} \times 111 \text{ N} \times 0.5 = 8.436 \text{ N}\text{m}\).
04

- Calculate Torque for \(90^\text{circ}\)

Substitute into the torque formula: \(\tau = 0.152 \text{ m} \times 111 \text{ N} \times \text{sin}(90^\text{circ})\). Since \(\text{sin}(90^\text{circ}) = 1\), \(\tau = 0.152 \text{ m} \times 111 \text{ N} = 16.872 \text{ N}\text{m}\).
05

- Calculate Torque for \(180^\text{circ}\)

Substitute into the torque formula: \(\tau = 0.152 \text{ m} \times 111 \text{ N} \times \text{sin}(180^\text{circ})\). Since \(\text{sin}(180^\text{circ}) = 0\), \(\tau = 0 \text{ N}\text{m}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Torque Calculation
Torque, often represented by the Greek letter \( \tau \), is essentially a measure of the rotational force applied to an object. When you push a door, you're applying torque to the door's hinges. The formula for torque is \( \tau = r \times F \times \sin(\theta) \). Here, \( r \) stands for the length of the lever arm, \( F \) is the force applied, and \( \theta \) is the angle between the force and the lever arm. A key point to note: torque is maximized when the force is applied perpendicular to the lever arm, which happens when the angle \( \theta \) is \( 90^\text{circ} \). In this case, the downward force on the pedal arm varies based on its orientation relative to vertical.
Lever Arm and Its Importance
The lever arm is a crucial part of understanding torque. In our case, it's the length from the pedal to its pivot point, which is \( 0.152 \mathrm{ m} \). The longer the lever arm, the more torque you can exert with the same amount of force. Imagine trying to pry open a can of paint with a long screwdriver versus a short one; the long screwdriver makes it easier because the lever arm is longer. This principle applies similarly to the bicycle pedal arm. It's easier to apply torque when the lever arm is sufficiently long.
Force Angle and Its Impact
The angle \( \theta \) plays a significant role in torque calculation. The impact of the angle shows up as the sine function in the torque formula. To see how different angles affect torque, consider our specific scenarios:
\( \30^\text{circ} \): \( \sin(30^\text{circ}) = 0.5 \), meaning the torque reduces to half of what it would be if the angle were \( \90^\text{circ} \).
\( \90^\text{circ} \): \( \sin(90^\text{circ}) = 1\), so the torque is at its maximum.
\( \180^\text{circ} \): \( \sin(180^\text{circ}) = 0 \), thus no torque is generated because the force is aligned with the lever arm.
These varying torques show why the angle at which force is applied is so critical. Applying force at different angles can either maximize, reduce, or nullify the torque produced.

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