/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 18 In the United States, a doll hou... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In the United States, a doll house has the scale of \(1: 12\) of a real house (that is, each length of the doll house is \(\frac{1}{12}\) that of the real house) and a miniature house (a doll house to fit within a doll house) has the scale of \(1: 144\) of a real house. Suppose a real house (Fig. \(1-18\) ) has a front length of \(20 \mathrm{~m}\), a depth of \(12 \mathrm{~m}\), a height of \(6.0 \mathrm{~m}\), and a standard sloped roof (vertical triangular faces on the ends) of height \(3.0 \mathrm{~m}\). In cubic meters, what are the volumes of the corresponding (a) doll house and (b) miniature house?

Short Answer

Expert verified
Volume of the doll house: 1.04 \text{ m}^3. Volume of the miniature house: 0.000602 \text{ m}^3.

Step by step solution

01

Understand the Scaling Factor

The scaling factor of the doll house is 1:12, which means each dimension of the doll house is \(\frac{1}{12}\) that of the real house. The scaling factor of the miniature house is 1:144, meaning each dimension of the miniature house is \(\frac{1}{144}\) that of the real house.
02

Calculate Volume of the Real House

The volume of the real house consists of two parts: the rectangular prism and the triangular prism (roof).\- Volume of the rectangular part: \(\text{Volume} = \text{length} \times \text{depth} \times \text{height} = 20 \text{ m} \times 12 \text{ m} \times 6 \text{ m} = 1440 \text{ m}^3\)\- Volume of the triangular prism (roof): The base area of the triangular face is \(\frac{1}{2} \times \text{base length} \times \text{height} = \frac{1}{2} \times 20 \text{ m} \times 3 \text{ m} = 30 \text{ m}^2 \); the volume of the roof is \(\text{Base Area} \times \text{depth} = 30 \text{ m}^2 \times 12 \text{ m} = 360 \text{ m}^3\).\- Total volume of the real house is \(\text{Rectangular volume} + \text{Roof volume} = 1440 \text{ m}^3 + 360 \text{ m}^3 = 1800 \text{ m}^3\).
03

Calculate Volume of the Doll House

Since volumes scale as the cube of linear dimensions, the volume of the doll house is: \(\text{Volume}_{doll} = \frac{1}{12^3} \times \text{Volume}_{real} = \frac{1}{1728} \times 1800 \text{ m}^3 \approx 1.04 \text{ m}^3\)
04

Calculate Volume of the Miniature House

Similarly, the volume of the miniature house can be calculated as: \(\text{Volume}_{miniature} = \frac{1}{144^3} \times \text{Volume}_{real} = \frac{1}{2985984} \times 1800 \text{ m}^3 \approx 0.000602 \text{ m}^3\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

volume calculation
Volume calculation is a crucial concept in physics and geometry. It involves determining the amount of space a 3D object occupies. In our example, we calculate the volume of a real house by breaking it down into two distinct geometric shapes: a rectangular prism for the main structure and a triangular prism for the roof. The volume of the rectangular prism is found using the formula \(\text{Volume} = \text{length} \times \text{depth} \times \text{height}\). For the triangular prism (the roof), we first find the base area with \( \text{Area} = \frac{1}{2} \times \text{base length} \times \text{height}\) and then multiply it by the depth to get the volume. Summing these two parts gives us the total volume of the house. Understanding how to calculate volumes of different shapes is foundational for solving complex problems in physics and engineering.
scaling factor
The scaling factor in physics helps us understand how sizes of similar geometric shapes compare when proportionally resized. When talking about a doll house at a scale of \(\frac{1}{12}\) or a miniature house at \(\frac{1}{144}\), each dimension is proportionally reduced by these factors. This reduction affects all measurements of the object. For volumes, the scaling factor has to be cubed (raised to the third power) because volume involves three dimensions. For our calculations, the volume of the doll house is found by applying the cube of the scaling factor \( \frac{1}{12^3} \) to the real house's volume. Similarly, for the miniature house, we use \( \frac{1}{144^3} \). Recognizing how scaling impacts different dimensions and subsequently volumes is key to applying these concepts correctly in physics.
geometric shapes in physics
In physics, understanding geometric shapes and their properties is essential. Geometric shapes like rectangular prisms and triangular prisms help us to simplify and solve problems more easily. A rectangular prism has straightforward calculations using length, width, and height. A triangular prism, such as the roof of a house, requires an understanding of both triangular area and depth. Knowing these geometrical properties allows us to break down complex shapes into simpler components. This decomposition makes calculating various physical properties, such as volume, more manageable. By mastering these basic shapes, students can tackle more complicated physical structures and phenomena, which are often tested in various fields such as engineering, architecture, and even natural sciences.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Here are two related problems - one precise, one an estimation. (a) A sculptor builds model for a statue 0 . a terrapin to replace Testudo." She discov. ers that to cast her small scale model she needs \(2 \mathrm{~kg}\) of bronze When she is done, she finds that she can give it two coats of finish. ing polyurethane varnish using exactly one small can of varnish. The final statue is supposed to be 5 times as large as the model in cach dimension. How much bronze will she need? How much varnish should she buy? (Hint: If this seems difficult, you might start by writing a simpler question that is easier to work on before tackling this one.) (b) The human brain has 1000 times the surface area of a mouse's brain. The human brain is convoluted, the mouse's is not. How much of this factor is due just to size (the human brain is bigger)? How sensitive is your result to your estimations of the approximate dimensions of a human brain and a mouse brain?

Measures in Spain You can easily convert common units and measures electronically, but you still should be able to use a conversion table, such as those in Appendix D. Table \(1-3\) is part of a conversion table for a system of volume measures once common in Spain; a volume of 1 fanega is equivalent to \(55.501 \mathrm{dm}^{3}\) (cubic decimeters). (a) Complete the table, using three significant figures. Then express \(7.00\) almude in terms of (b) medio, (c) cahiz, and (d) cubic centimeters \(\left(\mathrm{cm}^{3}\right)\).

Two types of barrel units were in use in the 1920 s in the United States. The apple barrel had a legally set volume of 7056 cubic inches; the cranberry barrel, 5826 cubic inches. If a merchant sells 20 cranberry barrels of goods to a customer who thinks he is receiving apple barrels, what is the discrepancy in the shipment volume in liters?

For about 10 years after the French revolution, the French government attempted to base measures of time on multiples of ten: One week consisted of 10 days, 1 day consisted of 10 hours, 1 hour consisted of 100 minutes, and 1 minute consisted of 100 seconds. What are the ratios of (a) the French decimal week to the standard week and (b) the French decimal second to the standard second?

You are to fix dinners for 400 people at a convention of Mexican food fans. Your recipe calls for 2 jalapeño peppers per serving (one serving per person). However, you have only habanero peppers on hand. The spiciness of peppers is measured in terms of the scoville heat unit (SHU). On average, one jalapeño pepper has a spiciness of \(4000 \mathrm{SHU}\) and one habanero pepper has a spiciness of 300000 SHU. To salvage the situation, how many (total) habanero peppers should you substitute for the jalapeño peppers in the recipe for the convention?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.