/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 20 Determine the weight of a mass o... [FREE SOLUTION] | 91Ó°ÊÓ

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Determine the weight of a mass of \(10 \mathrm{~kg}\) at a location where the acceleration of gravity is \(9.77 \mathrm{~m} / \mathrm{s}^{2}\).

Short Answer

Expert verified
The weight is \( 97.7 \, \mathrm{N} \).

Step by step solution

01

Understand the Problem

To determine the weight of an object, use the formula for weight: \( W = m \times g \), where \( W \) is the weight, \( m \) is the mass, and \( g \) is the acceleration due to gravity.
02

Identify Given Values

From the problem, the mass \( m \) is given as \( 10 \, \mathrm{kg} \) and the acceleration due to gravity \( g \) is given as \( 9.77 \, \mathrm{m/s^2} \).
03

Substitute Values Into the Formula

Substitute the given values into the formula \( W = m \times g \):\[ W = 10 \, \mathrm{kg} \times 9.77 \, \mathrm{m/s^2} \]
04

Calculate the Weight

Perform the multiplication to find the weight: \[ W = 10 \times 9.77 = 97.7 \, \mathrm{N} \]. Thus, the weight is \( 97.7 \, \mathrm{N} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

mass and weight
In physics, mass and weight are two distinct concepts, although they are often used interchangeably in everyday language. Understanding the difference between them is essential.

Mass refers to the amount of matter in an object. It is measured in kilograms (kg). Mass is an intrinsic property of matter, meaning it does not change regardless of location.

Weight, on the other hand, is the force exerted on an object due to gravity. It is a vector quantity and is measured in newtons (N). Weight can change depending on the gravitational pull at the object's location.

The formula to calculate weight is:

\( W = m \times g \)

Where, \( W \) is the weight, \( m \) is the mass, and \( g \) is the acceleration due to gravity. In summary, while mass is a measure of how much matter an object contains, weight is the gravitational force acting on that mass.

Never forget: weight depends on both mass and gravity.
acceleration due to gravity
The acceleration due to gravity, commonly denoted as \( g \), is the rate at which an object accelerates when dropped in a gravitational field. On Earth, the average value of \( g \) is approximately \( 9.81 \, \mathrm{m/s^2} \) but it can vary slightly depending on location.

This variation occurs due to several factors including altitude, latitude, and the Earth's geological structure. For example, gravity is slightly weaker at higher altitudes and at the equator compared to the poles.

Here are some key points about gravity:
  • The value of \( g \) will differ on other celestial bodies. For instance, on the Moon, \( g \) is roughly \( 1.63 \, \mathrm{m/s^2} \).
  • Gravity is always attractive, pulling objects toward the center of the mass that is creating the gravitational field.


In the given exercise, the acceleration due to gravity \( g \) is provided as \( 9.77 \, \mathrm{m/s^2} \), showcasing one of the small variations in Earth's gravity. Understanding \( g \) helps in solving many problems related to motion, force, and energy.
basic physics formulas
Mastering basic physics formulas is crucial for solving a wide array of problems. These formulas often serve as foundational tools for understanding more complex concepts. The formula used in the weight calculation problem is a perfect example of a fundamental physics equation.

Here are a few essential formulas to remember:
  • Weight: \( W = m \times g \)
  • Kinetic Energy: \( KE = \frac{1}{2} m v^2 \)
  • Potential Energy: \( PE = m g h \)
  • Newton's Second Law: \( F = m a \)


All these formulas are interconnected and serve various purposes in different scenarios:
  • The weight formula ties mass to gravity, giving the force due to gravity on an object.
  • Kinetic energy calculates the energy an object has due to its motion.
  • Potential energy computes the energy stored in an object due to its height.
  • Newton's second law connects force, mass, and acceleration, showing how objects move under different conditions.


Remember, understanding these basic formulas will equip you with the tools needed to tackle more complex problems in physics. Always refer back to the fundamentals whenever you feel stuck or unsure.

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Most popular questions from this chapter

Calculate the density, specific weight, mass, and weight of a body that occupies \(200 \mathrm{ft}^{3}\) if its specific volume is \(10 \mathrm{ft}^{3} / \mathrm{lbm}\). The quantities will not be calculated in the order asked for. The mass is $$ m=\frac{V}{v}=\frac{200 \mathrm{ft}^{3}}{10 \mathrm{ft}^{3} / \mathrm{lbm}}=20 \mathrm{lbm} $$ The density is $$ \rho=\frac{1}{v}=\frac{1}{10}=0.1 \mathrm{lbm} / \mathrm{ft}^{3} $$ The weight is, using \(g=32.2 \mathrm{ft} / \mathrm{s}^{2}\), $$ W=\frac{m}{g_{c}} g=\frac{20 \mathrm{lbm}}{32.2 \mathrm{lbm}-\mathrm{ft} / \mathrm{s}^{2}-\mathrm{lbf}}\left(32.2 \frac{\mathrm{ft}}{\mathrm{s}^{2}}\right)=20 \mathrm{lbf} $$ Finally, the specific weight is calculated to be $$ w=\frac{W}{V}=\frac{20}{200}=0.1 \mathrm{lbf} / \mathrm{ft}^{3} $$ Note that using English units, (1.6) would be written as $$ \gamma=\frac{\rho}{g_{c}} g=\left(\frac{0.1 \mathrm{lbm} / \mathrm{ft}^{3}}{32.2 \mathrm{lbm}-\mathrm{ft} / \mathrm{s}^{2}-\mathrm{lbf}}\right)\left(32.2 \mathrm{ft} / \mathrm{s}^{2}\right)=0.1 \mathrm{lbf} / \mathrm{ft}^{3} $$

A supercooled liquid is a liquid which is cooled to a temperature below that at which it ordinarily solidifies. Is this system in thermodynamic equilibrium? Why or why not?

A 1500-kg vehicle traveling at \(60 \mathrm{kph}\) collides head-on with a \(1000-\mathrm{kg}\) vehicle traveling at \(90 \mathrm{kph}\). If they come to rest immediately after impact, determine the increase in internal energy, taking both vehicles as the system.

The acceleration of gravity is given as a function of elevation above sea level by the relation \(g=9.81-3.32 \times 10^{-6} h \mathrm{~m} / \mathrm{s}^{2}\), with \(h\) measured in meters. What is the weight of an airplane at \(10 \mathrm{~km}\) elevation when its weight at sea level is \(40 \mathrm{kN}\) ?

Identify which of the following are extensive properties and which are intensive properties: \((a)\) a \(10-\mathrm{m}^{3}\) volume, \((b) 30 \mathrm{~J}\) of kinetic energy, \((c)\) a pressure of \(90 \mathrm{kPa},(d)\) a stress of \(1000 \mathrm{kPa},(e)\) a mass of \(75 \mathrm{~kg}\), and \((f)\) a velocity of \(60 \mathrm{~m} / \mathrm{s}\). \((g)\) Convert all extensive properties to intensive properties assuming \(m=75 \mathrm{~kg}\). (a) Extensive. If the mass is doubled, the volume doubles. (b) Extensive. If the mass doubles, the kinetic energy doubles. (c) Intensive. Pressure is independent of mass. (d) Intensive. Stress is independent of mass. (e) Extensive. If the mass doubles, the mass doubles. ( \(f\) ) Intensive. Velocity is independent of mass. (g) \(\frac{V}{m}=\frac{10}{75}=0.1333 \mathrm{~m}^{3} / \mathrm{kg} \quad \frac{E}{m}=\frac{30}{75}=0.40 \mathrm{~J} / \mathrm{kg} \quad \frac{m}{m}=\frac{75}{75}=1.0 \mathrm{~kg} / \mathrm{kg}\)

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