/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 26 (a) If one photon has 10 times t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

(a) If one photon has 10 times the frequency of another photon, which photon is the more energetic, and by what factor? (b) Answer the same question for the case where the first photon has twice the wavelength of the second photon.

Short Answer

Expert verified
(a) The photon with higher frequency is more energetic by a factor of 10. (b) The photon with shorter wavelength is more energetic by a factor of 2.

Step by step solution

01

Understand Photon Energy Relation with Frequency

The energy of a photon is given by the equation \( E = h u \), where \( E \) is the energy, \( h \) is Planck's constant, and \( u \) is the frequency of the photon. A photon with a higher frequency will have more energy.
02

Calculate Energy Ratio for Different Frequencies

If photon A has 10 times the frequency of photon B, then \( u_A = 10 u_B \). The energy of photon A is \( E_A = h \cdot 10 u_B \) and the energy of photon B is \( E_B = h u_B \). Therefore, the energy ratio \( \frac{E_A}{E_B} = 10 \). Photon A has 10 times the energy of photon B.
03

Understand Photon Energy Relation with Wavelength

The energy of a photon can also be expressed as \( E = \frac{hc}{\lambda} \), where \( \lambda \) is the wavelength and \( c \) is the speed of light. A photon with a shorter wavelength will have more energy.
04

Calculate Energy Ratio for Different Wavelengths

If photon C has twice the wavelength of photon D, then \( \lambda_C = 2 \lambda_D \). The energy of photon C is \( E_C = \frac{hc}{2 \lambda_D} \) and the energy of photon D is \( E_D = \frac{hc}{\lambda_D} \). Therefore, the energy ratio \( \frac{E_C}{E_D} = \frac{1}{2} \). Photon D has twice the energy of photon C.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency and Energy Relation
The relationship between frequency and energy for a photon is an important concept in quantum physics. When we talk about the energy of a photon, we often refer to it in terms of its frequency. The energy is calculated using the formula:
  • E = h \( u \)
Here, E is the energy of the photon, \( u \) is its frequency, and \( h \) is Planck's constant, a fundamental constant in physics with a value of approximately \( 6.626 \times 10^{-34} \) Joule seconds.

This equation tells us that a photon with a higher frequency will have more energy. Consider a scenario where one photon has 10 times the frequency of another. Using our formula, if photon A has a frequency of \( 10 u_B \), then its energy will be:
  • E_A = h \times 10 u_B = 10 h u_B
While photon B has an energy of:
  • E_B = h u_B
Thus, photon A is 10 times more energetic than photon B.
Wavelength and Energy Relation
Wavelength and energy share an inverse relationship in the context of photon energy. A photon's energy can be expressed in terms of its wavelength via the equation:
  • E = \( \frac{hc}{\lambda} \)
In this formula, E is the energy, c is the speed of light (approximately \(3.00 \times 10^8 \) m/s), and \( \lambda \) represents the wavelength of the photon.

Since the speed of light and Planck's constant are attached to specific values, the shorter the wavelength, the higher the photon's energy will be. This inverse relationship means that when a photon has twice the wavelength of another, it will have half of the energy.

For example, if photon C has a wavelength that is twice that of photon D (\( \lambda_C = 2 \lambda_D \)), the energies are calculated as follows:
  • E_C = \( \frac{hc}{2 \lambda_D} \)
  • E_D = \( \frac{hc}{\lambda_D} \)
It shows us that in this scenario, photon D is twice as energetic as photon C.
Planck's Constant
Planck's constant is a pivotal number in the world of quantum mechanics. Symbolized as h, its value is \(6.626 \times 10^{-34}\) Joule seconds. This constant helps bridge the gap between the familiar classical physics and the less intuitive quantum mechanics.

Planck's constant is essential in equations that connect energy with frequency and wavelength, such as:
  • The energy-frequency relation: E = h \( u \)
  • and, the energy-wavelength relation: E = \( \frac{hc}{\lambda} \)

By using Planck's constant, scientists can accurately measure the energy levels of photons in detail. This understanding is crucial for describing phenomena at microscopic scales, such as the behavior of electrons and the emission of light from atomic particles. Without this constant, the calculations of quantum mechanics would lack precision and clarity, making it harder to comprehend the dual nature of light and matter.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If the surface of a star were increasing in temperature as you went outward, would you see absorption lines or emission lines in its spectrum? Explain how this case differs from what we see in normal stars, which decrease in temperature as you go outward in the region from which they give off most of their light.

Sketch an atom, showing its nucleus and its electrons.

True or false? When we see other people, our eyes are detecting the visible light that each of us radiates as an approximate "black body" (thermal emitter).

Which one of the following statements about atoms is false ? (a) Electrons have discrete energy levels. (b) Each element produces a unique pattern of spectral lines, like a fingerprint. (c) Photon emission occurs randomly, in any direction. (d) An electron in an atom may absorb either part or all of the energy of a photon. (e) Absorption occurs when an electron in an atom jumps from a lower energy level to a higher energy level.

Multiple choice: Which one of the following statements about electromagnetic waves is false? (a) Human eyes are able to detect only a tiny fraction of all possible electromagnetic waves. (b) If electromagnetic wave Zoe has twice the wavelength of electromagnetic wave Simon, then Zoe also has twice the frequency of Simon. (c) "White light" such as sunlight actually consists of many electromagnetic waves, having different wavelengths, mixed together. (d) An electromagnetic wave consists of oscillating electric and magnetic fields that are perpendicular to each other and perpendicular to the direction of motion. (e) The measured speed of an electromagnetic wave is independent of the speed of its source relative to the observer.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.