/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 38 Draw block diagram representatio... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Draw block diagram representations for causal LTI systems described by the following difference equations: (a) \(y(n)=\frac{1}{3} y[n-1]+\frac{1}{2} x[n]\) (b) \(y[n]=\frac{1}{3} y[n-1]+x[n-1]\)

Short Answer

Expert verified
The block diagrams show the dependencies of \(y[n]\) on \(x[n]\), \(x[n-1]\), \(y[n-1]\) using delay and scaling blocks for causal LTI systems.

Step by step solution

01

Understanding the given equations

For both equations, identify the structure of the difference equations where the output \(y[n]\) is expressed in terms of past outputs and current or past inputs.
02

Break down equation (a)

Equation (a) is given by \(y(n) = \frac{1}{3} y[n-1] + \frac{1}{2} x[n]\). This indicates that the current output \(y[n]\) depends on the previous output \(y[n-1]\) scaled by \(\frac{1}{3}\), and the current input \(x[n]\) scaled by \(\frac{1}{2}\).
03

Draw block diagram for equation (a)

In the block diagram, represent the delay of one past output as a delay block (\(z^{-1}\)), a multiplier block for \(\frac{1}{3}\), and another multiplier block for \(\frac{1}{2}\). Combine these contributions through summation to give \(y[n]\).
04

Break down equation (b)

Equation (b) is given by \(y[n] = \frac{1}{3} y[n-1] + x[n-1]\). This indicates that the output \(y[n]\) depends on the previous output \(y[n-1]\) scaled by \(\frac{1}{3}\), and the previous input \(x[n-1]\).
05

Draw block diagram for equation (b)

For this block diagram, use delay blocks for both \(y[n-1]\) and \(x[n-1]\), a multiplier block for \(\frac{1}{3}\) on \(y[n-1]\), and then sum these contributions to produce \(y[n]\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Block Diagram
A block diagram is an essential tool in understanding the flow and processing of signals in Linear Time-Invariant (LTI) systems. These diagrams help us visualize how inputs are transformed into outputs, step by step.
In the block diagram representation of an LTI system, the various components such as adders, multipliers, and delays are represented as blocks. For example, when dealing with the difference equation such as (a) and (b) from the exercise, every part of the equation corresponds to an element in the block diagram.
  • Adder blocks sum up signals. In both equations, the incoming signals that make up the output are combined by adding them together.
  • Multiplier blocks scale signals. They multiply a signal by a constant, which is reflected in components like \(\frac{1}{3} y[n-1]\) or \(\frac{1}{2} x[n]\).
  • Delay blocks introduce a time shift. They represent a delay operation and are labeled as \(z^{-1}\), used to indicate the shift to prior moments like \(y[n-1]\) or \(x[n-1]\).
Using this approach, each part of a differential equation is easily depicted, illustrating the process needed to obtain the system's output from its input through visual means.
Causal Systems
A causal system is one where the output at any time relies solely on the past and present inputs, not the future. This is a pivotal concept in systems analysis, especially for students learning about LTI systems, as it simplifies real-world applications.
Causal systems allow predictions and reactions based on current or past observations, making them practical and implementable. For instance, in the given difference equations (a) and (b), both are causal systems because their outputs are determined by current and past inputs/outputs.
  • Equation (a): Here, \(y[n]\) depends on \(y[n-1]\) and \(x[n]\). Therefore, nothing in the equation makes use of future inputs or outputs.
  • Equation (b): It similarly depends on \(y[n-1]\) and \(x[n-1]\), again emphasizing its reliance on the past.
Understanding causal systems is crucial because they reflect how systems operate in reality. They also ensure stability and predictability, important features that maintain the functionality of LTI systems.
Difference Equations
Difference equations are mathematical expressions that relate the sequence of outputs of a system to its inputs. They are the discrete-time counterparts of differential equations and are common in digital signal processing.
In the exercise, each difference equation outlines relations between current and past values of both inputs and outputs.
  • Equation (a): \(y[n] = \ rac{1}{3} y[n-1] + \ rac{1}{2} x[n]\) establishes a framework where each output is built from previous output, \(y[n-1]\), and the current input, \(x[n]\).
  • Equation (b): \(y[n] = \ rac{1}{3} y[n-1] + x[n-1]\) structures the output using past output, \(y[n-1]\), and past input, \(x[n-1]\).
Understanding difference equations is vital as they give a step-by-step procedure for computing a sequence of outputs based on known inputs. They are the fundamental building blocks for designing systems that operate on sampled data, and hence, are indispensable for both control systems and digital signal processing.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A linear system \(S\) has the relationship $$y[n]=\sum_{k=-\infty}^{\infty} x[k] g[n-2 k]$$ between its input \(x[n]\) and its output \(y[n],\) where \(g[n]=u[n]-u[n-4]\) (a) Determine \(y[n]\) when \(x[n]=\delta[n-1]\) (b) Determine \(y[n]\) when \(x[n]=\delta\\{n-2]\) (c) Is \(S\) LTI? (d) Determine \(y\\{n]\) when \(x[n]=u[n]\)

Draw block diagram representations for causal LTI systems described by the follwing differential equations: (a) \(y(t)=-\left(\frac{1}{2}\right) d y(t) / d t+4 x(t)\) (b) \(d y(t) / d t+3 y(t)=x(t)\)

Which of the following impulse responses correspond(s) to stable \(\&\) T stems? (a) \(\left.h_{1} | n\right]=n \cos \left(\frac{\pi}{4} n\right) u[n]\) (b) \(h_{2}[n]=3^{n} u[-n+10]\)

One important use of inverse systems is in situations in which one wishes to remove distortions of some type. A good example of this is the problem of removing echoes from acoustic signals. For example. if an auditorium has a perceptible echo, then an initial acoustic impulse will be followed by attenuated versions of the sound at regularly spaced intervals. Consequently, an often-used model for this phenomenon is an LTI system with an impulse response consisting of a train of impulses, is... $$h(t)=\sum_{k=0}^{x} h_{k} \delta(t-k T)$$ Here the echoes occur \(T\) seconds apart, and \(h_{k}\) represents the gain factor on the \(k\) th echo resulting from an initial acoustic impulse. (a) Suppose that \(x(t)\) represents the original acoustic signal (the music produced by an orchestra, for example) and that \(y(t)=x(t) * h(t)\) is the actual signal that is heard if no processing is done to remove the echoes. In order to remove the distortion introduced by the echoes, assume that a microphone is used to sense \(y(t)\) and that the resulting signal is transduced into an electrical signal. We will also use \(y(t)\) to denote this signal, as it represents the electrical equivalent of the acoustic signal, and we can go from one to the other via acoustic-electrical conversion systems. The important point to note is that the system with impulse response given by eq. (P2.64-1) is invertible. Therefore, we can find an LTI system with impulse response \(g(r)\) such that $$y(t) * g(t)=x(t)$$ and thus, by processing the electrical signal \(y(t)\) in this fashicn and then converting back to an acoustic signal, we can remove the troublesome echoes. The required impulse response \(g(t)\) is also an impulse train: $$g(t)=\sum_{k=0}^{x} g_{k} \delta(t-k T)$$ Determine the algebraic equations that the successive \(g_{k}\) must satisfy, and solve these equations for \(g_{0}, g_{1},\) and \(g_{2}\) in terms of \(h_{k}\) (b) Suppose that \(h_{0}=1, h_{1}=1 / 2,\) and \(h_{t}=0\) for all \(i \geq 2\) What is \(g(t)\) in this case? (c) A good model for the generation of echocs is illustrated in Figure P2.64. Hence, each successive echo represents a fed-back version of \(y(t),\) delayed by \(T\) seconds and scaled by \(\alpha .\) Typically, \(0<\alpha<1,\) as successive echoes are attendated. (i) What is the impulse response of this systern's (Assume initial rest, i.e., \(y(t)=0\) for \(t<0\) if \(x(t)=0\) for \(t<0 .\) (ii) Show that the system is stable if \(0<\alpha<1\) and unstable if \(\alpha>1\) (iii) What is \(g(t)\) in this case? Construct a realization of the inverse system using adders, coefficient multipliers, and \(T\) -second delay elements. (d) Although we have phrased the preceding discussion in terms of continuous- time systems because of the application we have been considering, the same general ideas hold in diserete tome. That is, the CTI systern with impulse response $$h[n]=\sum_{k=0}^{\infty} \delta | n-k N$$ is invertible and has as its inverse an LTI sysiern with impulse response $$g[n]=\sum_{k=0}^{\infty} g_{k} \delta | n-k N$$ It is not difficult to check that the \(g_{r}\) satisfy the same algebrace equations as in part (a) Consider bow the discrete-time LTI system with impulse response $$h[n]=\sum_{k=-\infty}^{\infty} \delta[n-k N]$$ This system is nor invertible. Find two inputs that produce the same output.

Consider a causal LTI system \(S\) whose input \(x[n]\) and output \(y[n]\) are related by the difference equation $$2 y[n]-y[n-1]+y[n-3]=x[n]-5 x[n-4]$$ (a) Verify that \(S\) may be considered a cascade connection of two causal LII systems \(S_{1}\) and \(S_{2}\) with the following input-output relationship: $$\begin{aligned} &S_{1}: 2 y_{1}[n]=x_{1}[n]-5 x_{1}\\{n-4\\}\\\ &S_{2}: y_{2}[n]=\frac{1}{2} y_{2}[n-1]-\frac{1}{2} y_{2}[n-3]+x_{2}[n] \end{aligned}$$ (b) Draw a block diagram representation of \(S_{1}\) (c) Draw a block diagram representation of \(S_{2}\) (d) Draw a block diagram representation of \(S\) as a cascade connection of the block diagram representation of \(S_{1}\) followed by the block diagram representation of \(S_{2}\) (e) Draw a block diagram representation of \(S\) as a cascade connection of the block diagram representation of \(S_{2}\) followed by the block diagram representation of \(S_{1}\) (f) Show that the four delay elements in the block diagram representation of \(S\) obtained in part (e) may be collapsed to three. The resulting block diagram is referred to as a Direct Form \(I I\) realization of \(S,\) while the block diagrams obtained in parts \((\mathrm{d})\) and (e) are referred to as Direct Form \(I\) realizations of \(S\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.