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In many filtering applications, it is often undesirable for the step response of a filter to overshoot its final value. In processing pictures, for example, the overshoot in the step response of a linear filter may produce flare-that is, an increase in intensity at sharp boundaries. It is possible, however. to eliminate overshoot by requiring that the impulse response of the filter be positive for all time. Show that if \(h(t),\) the impulse response of a continuous-time LTT filter, is always greater than or equal to zero, the step response of the filter is a monotonically nondecreasing function and therefore will not have overshoot.

Short Answer

Expert verified
The step response is nondecreasing, preventing overshoot, when the impulse response is non-negative.

Step by step solution

01

Understanding the Problem

We need to show that if the impulse response, \( h(t) \), of a filter is non-negative for all time, the corresponding step response will not exhibit overshoot. The key here is to analyze how the step response is related to the impulse response.
02

Write the Step Response

The step response of a linear time-invariant (LTI) system is the integral of its impulse response function. For a continuous-time system, the step response \( s(t) \) can be expressed as: \[ s(t) = \int_{0}^{t} h(\tau) \, d\tau \] where \( h(t) \) is the impulse response.
03

Analyze the Step Response Derivative

To determine if the step response is nondecreasing, compute its derivative with respect to time:\[ \frac{ds(t)}{dt} = h(t) \]Since \( h(t) \geq 0 \) for all \( t \), the derivative \( \frac{ds(t)}{dt} \geq 0 \). This implies that the step response \( s(t) \) is a nondecreasing function.
04

Conclusion of No Overshoot

A monotonically nondecreasing function means that the value of the step response never decreases; hence, there's no overshoot past the final value, which is the endpoint in time of \( s(t) \). The requirement that \( h(t) \geq 0 \) ensures no negative slopes, thus preventing overshoot.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Impulse Response
The impulse response of a system is a crucial concept in filter design, helping to determine how the system reacts to different input signals. It captures the output when the system is subjected to a brief, but intense input, typically modeled as a delta function. This response can characterize the entire behavior of a system, given its linear and time-invariant properties. In mathematical terms, if we have a continuous-time filter, the impulse response is denoted as \( h(t) \).

  • A non-negative impulse response means that \( h(t) \geq 0 \) for all time \( t \)
  • It is often desirable for applications where signal fidelity, like image processing, is essential to maintain quality
By ensuring \( h(t) \) remains non-negative, we pave the way for a stable and predictable system behavior. This property of the impulse response is fundamental in designing filters that avoid unwanted phenomena such as overshoots.
Step Response
The step response of a filter is pivotal in understanding how it will react over time to a constant input signal that starts abruptly. This response can be visualized through the integral of the impulse response over time. More precisely, if \( h(t) \) is the impulse response of a system, the step response \( s(t) \) is given by:

\[ s(t) = \int_{0}^{t} h(\tau) \, d\tau \]

This integral reflects the accumulation of the system's responses over continuous instances from zero up to time \( t \). The step response provides insights into the system's stability and its propensity to reach a steady state.

  • Integral of a non-negative impulse response results in a non-decreasing step response
  • Knowing \( s(t) \) helps predict long-term behavior of the system
For a filter design without overshoot, the target is to have a step response that smoothly approaches its steady state without exceeding it.
Linear Time-Invariant Systems
Linear Time-Invariant (LTI) systems form the backbone of many signal processing applications because of their predictable and stable nature. These systems exhibit two key properties: linearity and time-invariance. The linearity ensures that the system's response to a complex signal is the sum of its responses to simple components of that signal. Time-invariance, on the other hand, guarantees that the system's characteristics do not change over time.

  • An LTI system's behavior is fully captured by its impulse response \( h(t) \)
  • The step response \( s(t) \) can be directly tied back to the properties of the impulse response
In filter design, LTI systems allow for precise control and manipulation, providing the ability to predict and control the outputs effectively over time.
Monotonic Functions
In the context of filter design, monotonic functions play a crucial role. A function is said to be monotonic if it is entirely non-decreasing or non-increasing. For a filter's step response, a monotonic non-decreasing behavior means the output never dips below previous values.

For the step response \( s(t) \), derived from the impulse response \( h(t) \), its characteristic behavior is crucial for ensuring no overshoot.

  • If \( \frac{ds(t)}{dt} = h(t) \geq 0 \), this confirms \( s(t) \) is monotonic non-decreasing
  • Monotonicity ensures stability and predictability in the system output
This steady ascent towards the steady state value is instrumental in applications requiring smooth transitions, eliminating abrupt jumps that cause overshoot.

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Most popular questions from this chapter

A three-point symmetric moving average, referred to as a weighted moving average, is of the form \\[ y[n]=b\\{a x[n-1]+x[n]+a x[n+1]\\} \\] (a) Determine, as a function of \(a\) and \(b\), the frequency response \(H\left(e^{j \omega}\right)\) of the three point moving average in eq. \((\mathrm{P} 6.47-1)\) (b) Determine the scaling factor \(b\) such that \(H\left(e^{j \omega}\right)\) has unity gain at zero frequency. (c) In many time-series analysis problems, a common choice for the coefficient \(a\) in the weighted moving average in eq. \((P 6.47-1)\) is \(a=1 / 2\) Determine and sketch the frequency response of the resulting filter.

Suppose we are given the following five facts about a particular LTI system \(S\) with impulse response \(h[n]\) and \(z\) -transform \(H(z)\). I. \(h|n|\) is real. 2\. \(h[n]\) is right sided. 3\. \(\lim _{=-x} H(z)=1\) 4\. \(H\) i \(z\) ) has two zeros. 5\. \(H(z)\) has one of its poles at a nonreal location on the circle defined by \(|z|=3 / 4\) Answer the following two questions: (a) Is \(S\) causal? (b) Is \(S\) stable?

Consider a causal, nonrecursive (FIR) filter whose real-valued impulse response \(h[n]\) is zero for \(n \geq N\) (a) Assuming that \(N\) is odd, show that if \(h[n]\) is symmetric about \((N-1) / 2\) (i.e., if \(h[(N-1) / 2+n]=h[(N-1) / 2-n]\\},\) then \\[ H\left(e^{j \omega}\right)=A(\omega) e^{-j((N-1) / 2|\omega|} \\] where \(A(\omega)\) is a real-valued function of \(\omega .\) We conclude that the filter has linear phase (b) Give an example of the impulse response \(h[n]\) of a causal, linear-phase FIR filter such that \(h[n]=0\) for \(n \geq 5\) and \(h[n] \neq 0\) for \(0 \leq n \leq 4\) (c) Assuming that \(N\) is even, show that if \(h[n]\) is symtnetric about \((N-1) / 2\) (i.e., if \(h[(N / 2)+n]=h[N / 2-n-1]),\) then \\[ H\left(e^{j \omega}\right)=A(\omega) e^{-j(N-1) / 2 j \omega} \\] where \(A(\omega)\) is a real-valued function of \(\omega\) (d) Give an example of the impulse response \(h[n]\) of a causal, linear-phase FIR fiter such that \(h[n]=0\) for \(n \geq 4\) and \(h[n] \neq 0\) for \(0 \leq n \leq 3\)

Consider the following algebraic expression for the \(z\) -transform \(X(z)\) of a signal \(x[n]\) \\[ X(z)=\frac{1+z^{-1}}{1+\frac{1}{3} z^{-1}} \\](a) Assuming the ROC to be \(|z|>1 / 3\), use long division to determine the values of \(x\\{0\\}, x[1],\) and \(x\\{2\\}\) (b) Assuming the ROC to be \(|z|<1 / 3,\) use long division to determine the values of \(x[0], x[-1],\) and \(x[-2]\)

Determine the \(z\) -transform for each of the following sequences. Sketch the pole zero plot and indicate the region of convergence. Indicate whether or not the Fourier transform of the sequence exisis. (a) \(\delta[n+5]\) (b) \(\delta(n-5]\) (c) \((-1)^{n} u[n]\) (d) \(\left(\frac{1}{2}\right)^{n+1} u[n+3]\) (e) \(\left(-\frac{1}{3}\right)^{n} u[-n-2]\) \((f)\left(\frac{1}{4}\right)^{n} u[3-n]\) (g) \(\left.2^{n} u |-n\right]+\left(\frac{1}{4}\right)^{n} u[n-1]\) (h) \(\left(\frac{1}{3}\right)^{n-2} u[n-2]\)

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