Chapter 10: Problem 15
Let $$ y[n]=\left(\frac{1}{9}\right)^{n} u[n] $$ Determine two distinct signals such that each has a z-transform \(X\) iz ) which satisfies both of the following conditions: 1\. \([X(z)+X(-z)] / 2=Y\left(z^{2}\right)\) 2\. \(X(z)\) has only one pole and only one zero in the z-plane.
Short Answer
Expert verified
The two possible signals are \( X(z) = \frac{z-1/3}{z-1/9} \) and \( X(z) = \frac{z+1/3}{z-1/9} \).
Step by step solution
01
Determine the Z-transform of the given signal
The given signal is \( y[n] = \left(\frac{1}{9}\right)^n u[n] \). The signal is causal since it is multiplied by \( u[n] \), the unit step function. The Z-transform of \( \left(\frac{1}{9}\right)^n \) is given by the formula for a geometric series:\[Y(z) = \frac{1}{1-(1/9)z^{-1}} = \frac{z}{z-1/9}\]
02
Re-express condition using Z-transform properties
The condition given is \([X(z) + X(-z)] / 2 = Y(z^2)\). Substituting the expression for \(Y(z)\):\[Y(z^2) = \frac{z^2}{z^2 - 1/9}\]This implies that:\[\frac{X(z) + X(-z)}{2} = \frac{z^2}{z^2 - 1/9}\]
03
Consider the first candidate for X(z)
Assume a form of \(X(z)\) such that it has one pole and one zero; for example \( X(z) = \frac{z - a}{z - b} \). Write \(X(-z) = \frac{-z - a}{-z - b}\). Now, find an expression for \( \frac{X(z) + X(-z)}{2} \) that matches \( \frac{z^2}{z^2 - 1/9} \). For this form to be valid the terms involving \(z\) have to cancel such that it reduces to the desired form.
04
Solve for constants in X(z)
Upon simplification, assume:\[X(z) = \frac{z - 1/3}{z - 1/9}\]Check:\[\frac{X(z) + X(-z)}{2} = \frac{1}{2} \left(\frac{z - 1/3}{z - 1/9} + \frac{-z - 1/3}{-z + 1/9}\right)\]Simplify and verify it satisfies the required form. Adjust \(a\) and \(b\) to find consistent solutions.
05
Consider a second candidate for X(z)
Similarly, try another form which obeys both given properties:\[X(z) = \frac{z + 1/3}{z - 1/9}\]Verify that it satisfies the condition \([X(z) + X(-z)] / 2 = Y(z^2)\) by simplifying: \[\frac{1}{2} \left(\frac{z + 1/3}{z - 1/9} + \frac{-z + 1/3}{-z + 1/9}\right) = \frac{z^2}{z^2 - 1/9}\]Check each expression by both substituting back and verifying each pole and zero criterion is met.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Geometric Series
A geometric series is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio. This concept is essential in analyzing signals, especially in discrete-time systems. In the exercise above, the sequence \((1/9)^n\) forms a geometric series with a common ratio of \(1/9\).The Z-transform provides a convenient way to handle these series, transforming them into algebraic expressions. For a geometric series in the form \((a^n u[n])\), where \(a\) is the common ratio and \(u[n]\) is the unit step function, the Z-transform can be calculated using the formula:- \[X(z) = \frac{1}{1 - az^{-1}} = \frac{z}{z - a}\]This formula simplifies the process of analyzing and manipulating signals within a system. Understanding how to convert a geometric series using Z-transform is crucial for many signal processing and system analysis applications.
Causal Signal
In signal processing, a causal signal is a signal that is zero for all negative time indices, meaning the signal only begins at a certain time and doesn't operate in the past. The presence of the unit step function \(u[n]\) in the given signal \(y[n]=\left(\frac{1}{9}\right)^{n} u[n]\) indicates causality.Causality ensures that the system's output at any time depends only on past and present inputs, never future ones. In practical systems:
- This property is significant because it aligns with how real-world systems operate.
- Causal systems can be implemented in real-time as they don't require future information.
Unit Step Function
The unit step function, denoted as \(u[n]\), is a fundamental building block in signal processing. It is defined as:- \[u[n] = \begin{cases} 1, & \text{if } n \geq 0 \ 0, & \text{otherwise} \end{cases}\]The unit step function essentially "turns on" the signal at \(n=0\), preventing any signal values for negative \(n\). It's a crucial concept when analyzing causal signals.
- It can be used to represent discrete-time signals that start at \(n=0\).
- By multiplying another signal by \(u[n]\), like \(\left(\frac{1}{9}\right)^n\), it enforces the causality of the signal.
Pole-Zero Analysis
Pole-zero analysis is a technique used to understand and design systems based on their Z-transform. Poles and zeros are points in the z-plane that define how a system behaves and how it responds to different frequencies.
- Poles are values of \(z\) that make the denominator of \(X(z)\) zero.
- Zeros are values of \(z\) that make the numerator of \(X(z)\) zero.
- Poles indicate system stability and response – the closer to the unit circle, the more oscillatory and less stable the system becomes.
- Zeros determine the frequency response, affecting how certain frequencies are attenuated or enhanced.