Chapter 8: Problem 45
(A) The reverse-saturation current in a diode is \(I_{x}=5 \times 10^{-12} \mathrm{~A}\). The maximum small-signal diffusion resistance is to be \(r_{d}=32 \Omega\). Determine the minimum forwardbias voltage that can be applied to meet this specification. (b) Repeat part \((a)\) if the maximum small-signal diffusion resistance is to be \(r_{d}=60 \Omega\).
Short Answer
Step by step solution
Understand the Relationship
Calculate Forward Current for Maximum Resistance
Use Diode Equation
Approximate for Large Exponential
Calculate Minimum Forward Voltage for Part A
Repeat Steps for New Resistance
Calculate Minimum Forward Voltage for Part B
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Small-Signal Diffusion Resistance
- As the current increases, \( r_d \) decreases, indicating a lower resistance to current changes.
- Conversely, a lower current implies a higher \( r_d \), showing greater resistance.
Thermal Voltage
- \( k \) is the Boltzmann constant \( (1.38 \times 10^{-23} \, ext{J/K}) \).
- \( T \) is the temperature in Kelvin.
- \( q \) is the charge of an electron \( (1.6 \times 10^{-19} \, ext{C}) \).
Diode Equation
- \( I \) is the diode current.
- \( I_x \) is the reverse-saturation current, a very small current when the diode is reverse-biased.
- \( V \) is the applied voltage across the diode.
- \( V_T \) is the thermal voltage.