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Consider a silicon sample at \(T=300 \mathrm{~K}\) that is uniformly doped with acceptor impurity atoms at a concentration of \(N_{a}=10^{16} \mathrm{~cm}^{-3}\). At \(t=0\), a light source is turned on generating excess carriers uniformly throughout the sample at a rate of \(g^{\prime}=8 \times\) \(10^{20} \mathrm{~cm}^{-3} \mathrm{~s}^{-1}\). Assume the minority carrier lifetime is \(\tau_{n 0}=5 \times 10^{-7} \mathrm{~s}\), and assume mobility values of \(\mu_{n}=900 \mathrm{~cm}^{2} / \mathrm{V}-\mathrm{s}\) and \(\mu_{p}=380 \mathrm{~cm}^{2} / \mathrm{V}-\mathrm{s} .(a)\) Determine the conductivity of the silicon as a function of time for \(t \geq 0 .(b)\) What is the value of conductivity at ( i) \(t=0\) and (ii) \(t=\infty\) ?

Short Answer

Expert verified
At \( t=0 \), \( \sigma = q[(n_0 + \Delta n) \mu_n + (p_0 + \Delta p) \mu_p] \). At \( t=\infty \), \( \sigma = q(n_0 \mu_n + p_0 \mu_p) \).

Step by step solution

01

Identify the equations for conductivity

The conductivity \( \sigma \) of a semiconductor is given by \( \sigma = q(n \mu_n + p \mu_p) \), where \( q \) is the electronic charge (\(1.6 \times 10^{-19} \) C), \( n \) and \( p \) are the electron and hole concentrations, and \( \mu_n \) and \( \mu_p \) are the electron and hole mobilities, respectively.
02

Define initial conditions and changes over time

Initially at \( t=0 \), since the material is p-type, the majority carrier concentration is \( p_0 = N_a = 10^{16}\,\text{cm}^{-3} \) and minority carrier concentration in thermal equilibrium \( n_0 \) can be found using \( n_0 = \frac{n_i^2}{p_0} \), where \( n_i \) is the intrinsic carrier concentration of silicon at 300 K (\( n_i \approx 1.5 \times 10^{10} \text{cm}^{-3} \)). Excess carriers \( \Delta n = \Delta p = g' \tau_{n0} \) are generated due to light.
03

Calculate excess carrier concentration

Using \( \Delta n = g' \tau_{n0} \), we find \( \Delta n = (8 \times 10^{20} \, \text{cm}^{-3} \text{s}^{-1}) \times (5 \times 10^{-7} \, \text{s}) = 4 \times 10^{14} \, \text{cm}^{-3} \). This gives the total electron concentration as \( n(t) = n_0 + \Delta n \) and hole concentration as \( p(t) = p_0 + \Delta p \).
04

Determine conductivity as a function of time

The excess carrier lifetimes affect the dynamic response of \( n(t) \) and \( p(t) \). At any time \( t \geq 0 \), \( n(t) = n_0 + \Delta n e^{-t/\tau} \) and \( p(t) = p_0 + \Delta p e^{-t/\tau} \), where \( \tau = \tau_{n0} \). The conductivity is \( \sigma(t) = q[n(t) \mu_n + p(t) \mu_p] \).
05

Evaluate conductivity at \( t=0 \)

At \( t=0 \), \( n(0) = n_0 + \Delta n \) and \( p(0) = p_0 + \Delta p \). Thus, \( \sigma(0) = q[(n_0 + \Delta n) \mu_n + (p_0 + \Delta p) \mu_p] \). Substituting known values and solving provides the specific conductivity value.
06

Evaluate conductivity at \( t=\infty \)

As \( t \to \infty \), the excess carriers are negligible, \( n(\infty) \approx n_0 \), \( p(\infty) \approx p_0 \). Thus, \( \sigma(\infty) = q(n_0\mu_n + p_0\mu_p) \). Calculating using these steady-state conditions gives the final conductivity value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Excess Carriers
Excess carriers in a semiconductor are additional charge carriers (electrons and holes) generated above the equilibrium concentration. In our exercise, these carriers are induced when a light source floods through the silicon sample. This leads to the generation of electron-hole pairs uniformly across the material. These excess carriers are pivotal in enhancing the conductivity of the semiconductor.
When the light is turned on, the rate of generation of these carriers is specified as \( g^{\prime} = 8 \times 10^{20} \, \text{cm}^{-3} \text{s}^{-1} \). The excess carrier concentration \( \Delta n = \Delta p \) can be determined using the relationship:
\[ \Delta n = g^{\prime} \tau_{n0} \]
where \( \tau_{n0} \) is the minority carrier lifetime.

These excess carriers play a crucial role because they directly influence the conductivity of the material. As more charge carriers are available for conduction, the conductivity changes over time as they are generated, recombine, or dissipate. Understanding how these carriers behave over time helps in predicting the semiconductor's dynamic electrical properties.
Minority Carrier Lifetime
The minority carrier lifetime is a critical parameter in semiconductor physics that describes the average time a minority charge carrier (electron in p-type or hole in n-type material) can exist before recombination. In the context of the exercise, the minority carrier lifetime is given as \( \tau_{n0} = 5 \times 10^{-7} \, \text{s} \). This means each excess electron or hole, on average, lasts for this duration before recombining.

Understanding minority carrier lifetime is essential because it directly affects the performance and efficiency of semiconductor devices. The longer the lifetime, the greater number of carriers can contribute to conduction, thus increasing material conductivity momentarily as shown by our exercise. This lifetime helps in describing how quickly a material returns to equilibrium after being perturbed, like how it returns to its baseline conductivity when the light source is removed or after an extended period with no further generation.
The lifetime influences the temporal response in the conductive properties of semiconductors, crucial for designing devices such as LEDs, photodetectors, and solar cells.
Electron and Hole Mobility
Electron and hole mobility are essential parameters that describe how quickly electrons and holes can move through the semiconductor material when subjected to an electric field. In our scenario, the mobility values are \( \mu_{n} = 900 \, \text{cm}^{2} / \text{V-s} \) for electrons and \( \mu_{p} = 380 \, \text{cm}^{2} / \text{V-s} \) for holes.

This mobility influences the semiconductor's conductivity, as conductivity \( \sigma \) is calculated using:
\[ \sigma = q(n \mu_n + p \mu_p) \]
where \( n \) and \( p \) are the concentrations of electrons and holes respectively. High mobility means that carriers can move more swiftly through the material, contributing to higher currents and improving device performance.
Mobility reflects the materials' resistance to carrier motion and involves factors such as scattering from impurities, lattice vibrations, and temperature.
  • High electron mobility is often preferred in devices for faster carrier transportation.
  • Hole mobility is generally lower due to the greater effective mass and complex path of holes in valence bands.
By understanding and optimizing mobility, semiconductor materials can be tailored for specific applications, ensuring efficiency and speed in electronic devices.

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Most popular questions from this chapter

(a) Consider a silicon sample at \(T=300 \mathrm{~K}\) doped with \(10^{16} \mathrm{~cm}^{-3}\) donor atoms. Let \(\tau_{p 0}=5 \times 10^{-7} \mathrm{~s}\). A light source turns on at \(t=0\) producing excess carriers with a uniform generation rate of \(g^{\prime}=5 \times 10^{20} \mathrm{~cm}^{-3} \mathrm{~s}^{-1}\). At \(t=5 \times 10^{-7} \mathrm{~s}\), the light source turns off. (i) Derive the expression(s) for the excess carrier concentration as a function of time over the range \(0 \leq t \leq \infty\). (ii) What is the value of the excess concentration when the light source turns off. \((b)\) Repeat part \((a)\) for the case when the light source turns off at \(t=2 \times 10^{-6} \mathrm{~s} .(c)\) Sketch the excess minority carrier concentrations versus time for parts \((a)\) and \((b)\).

Assume that an \(\mathrm{n}\) -type semiconductor is uniformly illuminated, producing a uniform excess generation rate \(g^{\prime}\). Show that in steady state the change in the semiconductor conductivity is given by $$ \Delta \sigma=e\left(\mu_{n}+\mu_{p}\right) \tau_{p 0} g^{\prime} $$

Consider silicon at \(T=300 \mathrm{~K}\) that is doped with donor impurity atoms to a concentration of \(N_{d}=5 \times 10^{15} \mathrm{~cm}^{-3} .\) The excess carrier lifetime is \(2 \times 10^{-7} \mathrm{~s}\). (a) Determine the thermal equilibrium recombination rate of holes. \((b)\) Excess carriers are generated such that \(\delta n=\delta p=10^{14} \mathrm{~cm}^{-3}\). What is the recombination rate of holes for this condition?

(a) Design a GaAs photoconductor that is \(4 \mu \mathrm{m}\) thick. Assume that the material is doped at \(N_{d}=10^{16} \mathrm{~cm}^{-3}\) and has lifetime values of \(\tau_{n 0}=10^{-7} \mathrm{~s}\) and \(\tau_{p 0}=5 \times 10^{-8}\) s. With an excitation of \(g^{\prime}=10^{21} \mathrm{~cm}^{-3} \mathrm{~s}^{-1}\), a photocurrent of at least \(2 \mu \mathrm{A}\) is required with an applied voltage of \(2 \mathrm{~V}\). \((b)\) Repeat the design for a silicon photoconductor that has the same parameters as given in part \((a)\).

Consider the function \(f(x, t)=(4 \pi D t)^{-1 / 2} \exp \left(-x^{2} / 4 D t\right) .(a)\) Show that this function is a solution to the differential equation \(D\left(\partial^{2} f / \partial x^{2}\right)=\partial f / \partial t .(b)\) Show that the integral of the function \(f(x, t)\) over \(x\) from \(-\infty\) to \(+\infty\) is unity for all values of time. \((c)\) Show that this function approaches a \(\delta\) function as \(t\) approaches zero.

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