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A force of \(1000 \mathrm{~N}\) is applied to a small space satellite for a time of \(10.0\) minutes. If the craft has a mass of \(200 \mathrm{~kg}\), what will be its final speed? [Hint: Be careful with those exponents when using a calculator.]

Short Answer

Expert verified
The final speed of the satellite is 3000 m/s.

Step by step solution

01

Convert Time Units

The force is applied for 10.0 minutes. To use this in the equation for impulse, we must convert minutes to seconds. Since there are 60 seconds in one minute, multiply 10.0 by 60 to get the time in seconds.Time in seconds: \( t = 10.0 \times 60 = 600 \text{ seconds} \)
02

Understand Impulse and Change in Momentum

Impulse \((J)\) is the change in momentum of an object. It is given by the product of force and time. Impulse formula: \( J = F \cdot t \), where \( F \) is force and \( t \) is time.
03

Calculate Impulse

Use the impulse formula with the given values: \( J = 1000 \, \text{N} \times 600 \, \text{s} \)Calculate:\( J = 600,000 \, ext{Ns} \)
04

Relate Impulse to Change in Velocity

Impulse is also equal to the change in momentum \((\Delta p)\), which can be expressed as mass \((m)\) times the change in velocity \((\Delta v)\).\( J = m \cdot \Delta v \), where \( \Delta v \) is the change in velocity.
05

Solve for Change in Velocity

Rearrange the impulse formula to solve for \( \Delta v \):\( \Delta v = \frac{J}{m} \)Substitute the values:\( \Delta v = \frac{600,000 \, ext{Ns}}{200 \, ext{kg}} \) Calculate: \( \Delta v = 3000 \, ext{m/s} \)
06

Determine Final Speed

Assuming the initial speed of the satellite was 0 m/s, the change in velocity \( \Delta v \) is equal to its final speed. Thus, the final speed is \( 3000 \, \text{m/s} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force and Motion
To understand how forces impact the motion of objects, let's start by defining force. Force is any interaction that, when unopposed, changes the motion of an object. It can cause an object at rest to start moving or alter the speed or direction of a moving object.
  • Forces can be measured in newtons (N), where one newton is the force necessary to accelerate a 1 kg mass by 1 m/s².
  • In our satellite problem, a force of 1000 N is applied.

When a constant force is applied over time, it affects the object’s velocity. This is captured through the concept of impulse. Impulse describes the effect of a force applied over a specific time duration. It is equal to the change in momentum, which is the product of the object's mass and its velocity. The more prolonged the force is applied, the greater the change in motion.
In our example, the force of 1000 N speeds up the satellite over 600 seconds. The change in momentum results in an increase in the satellite's velocity.
Kinematics
Kinematics is a branch of mechanics that focuses on the motion of objects without regard to the forces causing the motion. It involves descriptors like velocity, speed, and acceleration.
  • Velocity refers to the speed of an object in a specified direction.
  • In the problem, we calculated the final velocity of the satellite assuming it starts from rest.

A common task in kinematics is determining how forces affect motion over time.
Here, the relationship between the force applied to the satellite and the time over which it is applied allows us to calculate how quickly the satellite gains speed.
By calculating the change in velocity, which amounted to 3000 m/s in our problem, we effectively analyzed how kinematic principles apply in this context.
Newton's Laws of Motion
Newton's Laws of Motion establish the foundation for understanding the motion of objects under the influence of forces. Let's see how they apply to our satellite:
  • First Law (Inertia): An object will remain at rest or in uniform motion unless acted upon by an external force. In our case, the satellite was initially at rest.
  • Second Law (F=ma): This law quantifies how a force affects motion, stating that the acceleration of an object depends on the net force acting on it and inversely on its mass.

Through Newton's second law, the constant 1000 N force resulted in the satellite's acceleration. Given that the satellite started from rest, the consistent application of this force over a duration permitted us to calculate its final speed.
  • Third Law (Action and Reaction): For every action, there is an equal and opposite reaction. Here, as the satellite accelerates, it exerts an equal force back on the source of the applied force.

Understanding these laws provides a clear framework for predicting the satellite's behavior under the given force.
Unit Conversion in Physics
Unit conversion is vital in solving physics problems because it ensures consistency in calculations. Often, we need to convert units to align with the formulas we utilize.
  • In the satellite problem, time was initially given in minutes, but needed conversion to seconds—common practice since the standard unit of time in physics is seconds.
  • This conversion involved multiplying the given time (10 minutes) by the number of seconds per minute (60) to result in 600 seconds.

Inconsistent units can lead to incorrect conclusions or calculations. Always double-check units at each step.
  • Using consistent units allows interoperability across formulas, enhancing accuracy and reliability.

In physics, comfortable handling of units and conversions makes problem-solving more straightforward, providing clarity and preventing potential errors.

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Most popular questions from this chapter

A ball of mass \(m\) at rest at the coordinate origin explodes into three equal pieces. At some instant, one piece is on the \(x\) -axis at \(x=40\) \(\mathrm{cm}\) and another is at \(x=20 \mathrm{~cm}, y=-60 \mathrm{~cm}\). Where is the third piece at that instant?

A \(2.0\) -kg block of wood rests on a long tabletop. A \(5.0\) -g bullet moving horizontally with a speed of \(150 \mathrm{~m} / \mathrm{s}\) is shot into the block and lodges in it. The block then slides \(270 \mathrm{~cm}\) along the table and stops. ( \(a\) ) Find the speed of the block just after impact. ( \(b\) ) Find the friction force between block and table assuming it to be constant.

A 6000 -kg truck traveling north at \(5.0 \mathrm{~m} / \mathrm{s}\) collides with a \(4000-\mathrm{kg}\) truck moving west at \(15 \mathrm{~m} / \mathrm{s}\). If the two trucks remain locked together after impact, with what speed and in what direction do they move immediately after the collision?

What force is exerted on a stationary flat plate held perpendicular to a jet of water as shown in Fig. 8-6? The horizontal speed of the water is \(80 \mathrm{~cm} / \mathrm{s}\), and \(30 \mathrm{~mL}\) of the water hit the plate each second. Assume the water moves parallel to the plate after striking it. One milliliter (mL) of water has a mass of \(1.00 \mathrm{~g}\). This question deals with speed, mass, time, and force, and that suggests impulse-momentum and Newton's Second Law. The plate exerts an impulse on the water and changes its horizontal momentum. The water exerts a counterforce on the plate. Taking the direction to the right as positive, (Impulse) \(_{x}=\) Change in \(x\) -directed momentum $$ F_{x} \Delta t=\left(m v_{x}\right)_{\text {final }}-\left(m v_{x}\right)_{\text {initial }} $$ Let \(t\) be \(1.00 \mathrm{~s}\) so that \(m\) will be the mass that strikes in \(1.00 \mathrm{~s}\), namely \(30 \mathrm{~g}\). Then the above equation becomes $$ F_{x}(1.00 \mathrm{~s})=(0.030 \mathrm{~kg})(0 \mathrm{~m} / \mathrm{s})-(0.030 \mathrm{~kg})(0.80 \mathrm{~m} / \mathrm{s}) $$ from which \(F_{x}=-0.024 \mathrm{~N}\). This is the force exerted by the plate on the water. The law of action and reaction tells us that the jet exerts an equal but opposite force on the plate.

A ball of mass \(m\) sits at the coordinate origin when it explodes into two pieces that shoot along the \(x\) -axis in opposite directions. When one of the pieces (which has mass \(0.270 m\) ) is at \(x=70 \mathrm{~cm}\), where is the other piece? [Hint: What happens to the mass center?]

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