Chapter 35: Problem 2
A time-varying voltage \(v=(60.0 \mathrm{~V}) \sin 120 \pi\) t is applied across a 20.0-\Omega resistor. What will an ac ammeter in series with the resistor read? The rms voltage across the resistor is Then $$ \begin{array}{l} V=0.707 v_{0}=(0.707)(60.0 \mathrm{~V})=42.4 \mathrm{~V} \\ I=\frac{V}{R}=\frac{42.4 \mathrm{~V}}{20.0 \Omega}=2.12 \mathrm{~A} \end{array} $$
Short Answer
Step by step solution
Understand the problem
Calculate the RMS voltage
Calculate the RMS current
Conclude the AC ammeter reading
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ohm's Law
- \( I \) is the current in amperes (A),
- \( V \) is the voltage in volts (V),
- \( R \) is the resistance in ohms (\( \Omega \)).
RMS Voltage
AC Circuits
- Frequency, which indicates how often the current changes direction per second. It's typically measured in hertz (Hz).
- Phase, which relates to the position of the current or voltage wave in time.
- Impedance, which is the complex resistance to the flow of current and combines real resistance and reactance.
Sinusoidal Voltage
- \( V_0 \) is the peak voltage,
- \( \omega \) is the angular frequency, \( 2 \pi \times \text{frequency} \),
- \( t \) stands for time.