Chapter 27: Problem 4
An electric iron of resistance \(20 \Omega\) takes a current of \(5.0 \mathrm{~A}\). Calculate the thermal energy, in joules, developed in \(30 \mathrm{~s}\). $$ \begin{array}{l} \text { Energy }=\mathrm{P} t \\ \text { Energy }=I^{2} R t=(5 \mathrm{~A})^{2}(20 \Omega)(30 \mathrm{~s})=15 \mathrm{~kJ} \end{array} $$
Short Answer
Step by step solution
Understand the Formula
Identify Given Values
Substitute Values into the Formula
Calculate the Energy
Express the Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ohm's Law
- Current (I): The flow of electric charge through a conductor.
- Voltage (V): The potential difference that drives the current through the circuit.
- Resistance (R): The opposition to the flow of electric current, measured in ohms.
Thermal Energy
- **Resistance Effect:** The material's resistance causes the moving electrons to collide with atoms, converting electrical energy to thermal energy.
- **Time Influence:** More energy is produced the longer the current continues to flow, assuming constant resistance and current.
- **Current's Role:** The greater the current, the more thermal energy generated due to increased electron movement.
Electrical Resistance
- Material Type: Conductors have low resistance, while insulators have high resistance.
- Wire Length and Cross-sectional Area: Longer wires have more resistance, while wires with a larger diameter have less.
- Temperature: Increasing temperature can increase resistance in most conductors.
Current Electricity
- **Direct Current (DC):** Used in batteries and electronics; the flow of electricity is unidirectional.
- **Alternating Current (AC):** Commonly used in household power supplies; the electrical charge changes direction periodically.
- **Conductors and Insulators:** Materials like copper allow easy flow of current, while rubber acts as an insulator, blocking current.