Chapter 25: Problem 11
Four point charges in air are placed at the four corners of a square that is \(30 \mathrm{~cm}\) on each side. Find the potential at the center of the square if \((a)\) the four charges are each \(+2.0 \mu \mathrm{C}\) and \((b)\) two of the four charges are \(+2.0 \mu \mathrm{C}\) and two are \(-2.0 \mu \mathrm{C}\).
Short Answer
Step by step solution
Understanding Potential and Formula
Calculating Distance to Center
Case a - All Charges are +2.0 μC
Case b - Mixed Charges
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coulomb's Law
This means:
- If the charges increase, the force increases.
- If the distance increases, the force decreases.
- \( F \) is the electrostatic force.
- \( k \) is Coulomb's constant \((8.99 \times 10^9 \, \text{Nm}^2/\text{C}^2)\).
- \( q_1 \) and \( q_2 \) are the charges.
- \( r \) is the distance between the charges.
Point Charge
Point charges are useful in simplifying calculations and understanding electric fields, especially when dealing with symmetrical situations.
- Consider a charge at a definite location, with no physical extent.
- Its electric field influences other charges around it regardless of its physical size.
- \( V \) is the electric potential at a distance \( r \) from the charge \( q \).
- \( k \) is Coulomb's constant.
- \( r \) is the distance from the charge to the point of interest.
Electric Field
It can be described using the formula:\[E = \frac{F}{q}\]where:
- \( E \) is the electric field.
- \( F \) is the force experienced.
- \( q \) is the charge witnessing the force.
- They point away from positive charges and toward negative charges.
- The closer you are to a charge, the stronger the field.
- Fields can superimpose; when multiple charges are present, the total field is the vector sum of individual fields.
Pythagorean Theorem
The theorem states:\[c^2 = a^2 + b^2\]where:
- \( c \) is the length of the hypotenuse.
- \( a \) and \( b \) are the lengths of the other two sides.
Using this theorem, if each side of the square is 0.3 m, the diagonal \( d \) is:\[d = \sqrt{0.3^2 + 0.3^2} = 0.3\sqrt{2}\]This helps us find the distance from each corner to the center as half the diagonal:\[r = \frac{d}{2} = \frac{0.3\sqrt{2}}{2} = 0.212 \, \text{m}\]By understanding this distance, we can calculate the electric potential at that point from the charges.