/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 24 How many electrons are contained... [FREE SOLUTION] | 91Ó°ÊÓ

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How many electrons are contained in \(1.0\) C of charge? What is the mass of the electrons in \(1.0 \mathrm{C}\) of charge?

Short Answer

Expert verified
There are \(6.25 \times 10^{18}\) electrons in \(1.0\) C and their mass is \(5.69 \times 10^{-12}\) kg.

Step by step solution

01

Identify the Charge of One Electron

The charge of one electron is known to be \(-1.6 \times 10^{-19}\) Coulombs. This value will help us determine how many electrons make up a total charge of \(1.0\) Coulomb.
02

Calculate Number of Electrons

To find the number of electrons in \(1.0\) C of charge, divide the total charge by the charge of one electron:\[\text{Number of electrons} = \frac{1.0 \text{ C}}{1.6 \times 10^{-19} \text{ C/electron}} = 6.25 \times 10^{18} \text{ electrons}.\]
03

Identify the Mass of One Electron

The mass of one electron is \(9.11 \times 10^{-31}\) kilograms. This will be used to calculate the total mass of the electrons.
04

Calculate Total Mass of Electrons

To find the total mass of the electrons, multiply the number of electrons by the mass of one electron:\[\text{Total mass} = 6.25 \times 10^{18} \text{ electrons} \times 9.11 \times 10^{-31} \text{ kg/electron} = 5.69 \times 10^{-12} \text{ kg}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Charge of an Electron
The charge of an electron is a fundamental constant in physics. It is denoted by the symbol \(e\) and has a value of \(-1.6 \times 10^{-19}\) Coulombs (C). This negative sign indicates that the electron carries a negative charge, as opposed to protons, which carry a positive charge. Understanding this constant is crucial when studying electric forces and fields.

Given that charges come in multiples of the electron's charge, it allows us to quantify and predict the behavior of matter under electromagnetic forces. For example, when asked to determine how many electrons make up a certain charge, like \(1.0\) C, simply divide the total charge by the charge of one electron. This gives you \[\frac{1.0 \text{ C}}{1.6 \times 10^{-19} \text{ C/electron}} = 6.25 \times 10^{18} \text{ electrons}.\]

Electrons are responsible for electricity flow in conductors and play a fundamental role in chemical reactions by participating in bond formation. Thus, appreciating the size and the importance of an electron's charge helps to understand a broad array of physical phenomena.
Mass of an Electron
The mass of an electron is another crucial constant in electricity and magnetism. It is significantly smaller than that of protons and neutrons, being only \(9.11 \times 10^{-31}\) kilograms. This extraordinarily small mass gives electrons the ability to respond rapidly to electric and magnetic fields.

Despite their small mass, electrons play a massive role in the mass of charged systems due to their numbers and charge interactions. In electromagnetic contexts, knowing the number of electrons helps estimate the collective mass of these electrons in a given system. For instance, if you know there are \(6.25 \times 10^{18}\) electrons in \(1.0\) C of charge, then multiplying this number by the mass of one electron gives us the total mass of electrons:
  • \[\text{Total mass} = 6.25 \times 10^{18} \times 9.11 \times 10^{-31} \text{ kg} = 5.69 \times 10^{-12} \text{ kg} \]
Understanding the mass of electrons is essential in fields ranging from quantum physics to chemistry, where electron-mass interplay dictates molecular and atomic behavior.
Coulomb's Law
Coulomb's Law is a fundamental principle in electrostatics, describing the force between two charged objects. This law states that the magnitude of the force (\(F\)) between two point charges is directly proportional to the product of the absolute values of the charges (\(q_1\) and \(q_2\)) and inversely proportional to the square of the distance (\(r\)) between them:
  • \[ F = k_e \frac{|q_1 \cdot q_2|}{r^2} \]
where \(k_e\) is Coulomb's constant, approximately \(8.99 \times 10^9 \text{ N m}^2/ ext{C}^2\).

This law provides insight into how charged particles such as electrons and protons interact over distances. It helps predict the force of attraction or repulsion between charged entities. For practical purposes, it tells us the feasibility of electrostatic forces in binding atoms or in technologies like capacitors and laser traps.

Thus, Coulomb's Law provides a framework for understanding fundamental interactions in nature, indicating how the charge of an electron and even its mass can influence forces at the atomic level.

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Most popular questions from this chapter

Two equally charged small balls are \(3 \mathrm{~cm}\) apart in air and repel each other with a force of \(40 \mu \mathrm{N}\). Compute the charge on each ball.

Determine the force between two free electrons spaced 1.0 angstrom \(\left(10^{-10} \mathrm{~m}\right)\) apart in vacuum.

Three point charges in vacuum are placed on the \(x\) -axis in Fig. \(24-\) 1 . Find the net force on the \(-5 \mu \mathrm{C}\) charge due to the two other charges. Because unlike charges attract, the forces on the \(-5 \mu \mathrm{C}\) charge are as shown. The magnitudes of \(\overrightarrow{\mathbf{F}}_{E 3}\) and \(\overrightarrow{\mathbf{F}}_{E 8}\) are given by Coulomb's Law: $$ \begin{array}{l} F_{E 3}=\left(9.0 \times 10^{9} \mathrm{~N} \cdot \mathrm{m}^{2} / \mathrm{C}^{2}\right) \frac{\left(3.0 \times 10^{-6} \mathrm{C}\right)\left(5.0 \times 10^{-6} \mathrm{C}\right)}{(0.20 \mathrm{~m})^{2}}=3.4 \mathrm{~N} \\ F_{E 8}=\left(9.0 \times 10^{9} \mathrm{~N} \cdot \mathrm{m}^{2} / \mathrm{C}^{2}\right) \frac{\left(8.0 \times 10^{-6} \mathrm{C}\right)\left(5.0 \times 10^{-6} \mathrm{C}\right)}{(0.30 \mathrm{~m})^{2}}=4.0 \mathrm{~N} \end{array} $$ Keep in mind the following: (1) Proper units (coulombs and meters) must be used. (2) Because we want only the magnitudes of the forces, we do not carry along the signs of the charges. That is, we use their absolute values. Determine if the forces are attractive or repulsive and then draw them in your diagram. Pick a direction to be positive and sum the forces. From the diagram, the resultant force on the center charge is $$ F_{E}=F_{E 8}-F_{E 3}=4.0 \mathrm{~N}-3.4 \mathrm{~N}=0.6 \mathrm{~N} $$ and it is in the \(+x\) -direction, to the right.

Two small charged spheres are placed in vacuum on the \(x\) -axis: \(+3.0 \mu \mathrm{C}\) at \(x=0\) and \(-5.0 \mu \mathrm{C}\) at \(x=40 \mathrm{~cm} .\) Where must a third charge \(q\) be placed if the force it experiences is to be zero? The situation is represented in Fig. 24-4. We know that \(q\) must be placed somewhere on the \(x\) -axis. (Why?) Suppose that \(q\) is positive. When it is placed in interval \(B C\), the two forces on it are in the same direction and cannot cancel. When it is placed to the right of \(C\), the attractive force from the \(-5 \mu \mathrm{C}\) charge is always larger than the repulsion of the \(+3.0 \mu \mathrm{C}\) charge. Therefore, the force on \(q\) cannot be zero in this region. Only in the region to the left of \(B\) can cancellation occur. (Can you show that this is also true if \(q\) is negative?) For \(q\) placed as shown, when the net force on it is zero, we have \(F_{E 3}=F_{E 5}\) and so, for distances in meters, $$ k_{0} \frac{q\left(3.0 \times 10^{-6} \mathrm{C}\right)}{d^{2}}=k_{0} \frac{q\left(5.0 \times 10^{-6} \mathrm{C}\right)}{(0.40 \mathrm{~m}+d)^{2}} $$ After canceling \(q, k_{0}\), and \(10^{-6} \mathrm{C}\) from each side, cross- multiply to obtain $$ 5 d^{2}=3.0(0.40+d)^{2} \text { or } d^{2}-1.2 d-0.24=0 $$ Using the quadratic formula, $$ d=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}=\frac{1.2 \pm \sqrt{1.44+0.96}}{2}=0.60 \pm 0.775 \mathrm{~m} $$ Two values, \(1.4 \mathrm{~m}\) and \(-0.18 \mathrm{~m}\), are therefore found for \(d\). The first is the correct one; the second gives the point in \(B C\) where the two forces have the same magnitude but do not cancel.

In the Bohr model of the hydrogen atom, an electron \((q=-e)\) circles a proton \(\left(q^{\prime}=e\right)\) in an orbit of radius \(5.3 \times 10^{-11} \mathrm{~m} .\) The attraction between the proton and electron furnishes the centripetal force needed to hold the electron in orbit. Find \((a)\) the force of electrical attraction between the particles and \((b)\) the electron's speed. The electron mass is \(9.1 \times 10^{-31} \mathrm{~kg}\). The electron and proton are essentially point charges. Accordingly, (b) The force found in \((a)\) is the centripetal force, \(m v^{2} / r\). Therefore, $$ 8.2 \times 10^{-8} \mathrm{~N}=\frac{m v^{2}}{r} $$ from which it follows that $$ v=\sqrt{\frac{\left(8.2 \times 10^{-8} \mathrm{~N}\right)(r)}{m}}=\sqrt{\frac{\left(8.2 \times 10^{-8} \mathrm{~N}\right)\left(5.3 \times 10^{-11} \mathrm{~m}\right)}{9.1 \times 10^{-31} \mathrm{~kg}}}=2.2 \times 10^{6} \mathrm{~m} / \mathrm{s} $$

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