Two vats of water, one at \(87^{\circ} \mathrm{C}\) and the other at \(14{
}^{\circ} \mathrm{C}\), are separated by a metal plate. If heat flows through
the plate at 35 \(\mathrm{cal} / \mathrm{s}\), what is the change in entropy of
the system that occurs in a time of one second?
The higher-temperature vat loses entropy, while the cooler one gains entropy:
$$
\begin{array}{l}
\Delta S_{\mathrm{H}}=\frac{\Delta Q}{T_{\mathrm{H}}}=\frac{(-35
\mathrm{cal})(4.186 \mathrm{~J} / \mathrm{cal})}{360 \mathrm{~K}}=-0.41
\mathrm{~J} / \mathrm{K} \\
\Delta S_{\mathrm{L}}=\frac{\Delta Q}{T_{\mathrm{L}}}=\frac{(35
\mathrm{cal})(4.186 \mathrm{~J} / \mathrm{cal})}{287 \mathrm{~K}}=0.51
\mathrm{~J} / \mathrm{K}
\end{array}
$$
Therefore, \(0.51 \mathrm{~J} / \mathrm{K}-0.41 \mathrm{~J} / \mathrm{K}=0.10
\mathrm{~J} / \mathrm{K}\)