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What fraction of the volume of a piece of quartz \(\left(\rho=2.65 \mathrm{~g} / \mathrm{cm}^{3}\right)\) will be submerged when it is floating in a container of mercury \((\rho\) \(\left.=13.6 \mathrm{~g} / \mathrm{cm}^{3}\right) ?\)

Short Answer

Expert verified
Approximately 19.49% of the quartz's volume is submerged.

Step by step solution

01

Understanding Archimedes' Principle

When an object floats in a fluid, the weight of the fluid displaced by the object equals the weight of the object. This is Archimedes' principle, which we use to find the submerged volume fraction.
02

Calculate the Weight of the Quartz

The weight of any object can be found using the formula: \[ \text{Weight of Quartz} = \text{Volume} \times \text{Density of Quartz} \]Let the volume of the quartz be \(V\) and density \(\rho_q = 2.65 \text{ g/cm}^3\). The weight is \(2.65V\) grams.
03

Calculate the Weight of Displaced Mercury

The weight of displaced mercury when the quartz is submerged is:\[ \text{Weight of Displaced Mercury} = \text{Submerged Volume of Quartz} \times \text{Density of Mercury} \]This is given by \( \rho_m \times V_s \), where \(V_s\) is the submerged volume, and \(\rho_m = 13.6 \text{ g/cm}^3\).
04

Apply Archimedes' Principle

According to Archimedes' principle, the weight of the displaced mercury equals the weight of the quartz.\[ 2.65V = 13.6V_s \]Here, \(V_s\) is the submerged volume.
05

Solve for the Submerged Volume Fraction

Rearrange the equation from Step 4 to solve for the fraction of the volume submerged:\[ \frac{V_s}{V} = \frac{2.65}{13.6} \]Calculate the fraction:\[ \frac{V_s}{V} = 0.1949 \]
06

Conclusion

Approximately 19.49% of the volume of the quartz is submerged when it is floating in mercury.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density
Density is a measure of how much mass is contained in a given volume. It is an intrinsic property of matter, which means it does not change regardless of the size of the sample you have.
Density is usually expressed in units such as grams per cubic centimeter (g/cm extsuperscript{3}) or kilograms per cubic meter (kg/m extsuperscript{3}). \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] This formula helps us understand how much material is packed into a given space.
  • For example, quartz has a density of 2.65 g/cm extsuperscript{3}. This means 1 cubic centimeter of quartz weighs 2.65 grams.
  • On the other hand, mercury, which is denser, has a density of 13.6 g/cm extsuperscript{3}. This higher number signifies that mercury is much more tightly packed than quartz.
Recognizing the differences in density between substances helps us understand why some objects float while others sink. When an object of lower density is placed in a fluid of higher density, it floats because it displaces more fluid weight than its own weight.
Weight of Displaced Fluid
The concept of the weight of displaced fluid is central to understanding why objects float, as explained by Archimedes’ principle. When an object is submerged in a fluid, it pushes or displaces some of that fluid out of the way. The weight of this displaced fluid provides a buoyant force, or an upward lift.
The weight of the displaced fluid can be calculated using the formula: \[ \text{Weight of Displaced Fluid} = \text{Submerged Volume} \times \text{Density of Fluid} \] This means, for the quartz example:
  • When quartz is submerged in mercury, the displaced mercury's weight is given by the submerged quartz volume multiplied by the mercury's density (13.6 g/cm extsuperscript{3}).
  • This weight of the displaced fluid must equal the weight of the object (quartz) for it to float, providing the necessary upward force to counter the gravitational force pulling the object downwards.
Practically, this explains why something might be able to "float" in mercury, despite mercury being a liquid metal because it is incredibly dense compared to the object.
Submerged Volume Fraction
The submerged volume fraction is the proportion of an object's volume that is beneath the surface when it is floating in a fluid. This concept is crucial in applications from shipbuilding to environmental science. In our example, the quartz piece is partially submerged in mercury, and we determine what fraction of its volume is underwater.Applying Archimedes' Principle, we established the relationship between displaced fluid's weight and the object's weight. Using equations, the submerged volume fraction is found by:\[ \frac{V_s}{V} = \frac{\text{Density of Quartz}}{\text{Density of Mercury}} = \frac{2.65}{13.6} \]Where:
  • \( V_s \) is the submerged volume of quartz.
  • \( V \) is the total volume of quartz.
Here, this results in roughly 19.49%, indicating that a smaller portion of the quartz is actually submerged. This happens because quartz is less dense than mercury.
This submerged volume fraction tells us how much of the quartz stays below the surface and is key for understanding buoyancy in different fluids.

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Most popular questions from this chapter

A wooden cylinder has a mass \(m\) and a base area \(A\). It floats in water with its axis vertical. Show that the cylinder undergoes SHM if given a small vertical displacement. Find the frequency of its motion. When the cylinder is pushed down a distance \(y\), it displaces an additional volume Ay of water. Because this additional displaced volume has mass \(A y_{\rho w}\), an additional buoyant force \(A y_{\rho w g}\) acts on the cylinder, where \(\rho_{w}\) is the density of water. This is an unbalanced force on the cylinder and is a restoring force. In addition, the force is proportional to the displacement and so is a Hooke's Law force. Therefore, the cylinder will undergo SHM, as described in Chapter 11 . Comparing \(F_{B}=A \rho_{w} g y\) with Hooke's Law in the form \(F=k y\), we see that the elastic constant for the motion is \(k=A \rho_{w} g .\) This, acting on the cylinder of mass \(m\), causes it to have a vibrational frequency of $$ f=\frac{1}{2 \pi} \sqrt{\frac{k}{m}}=\frac{1}{2 \pi} \sqrt{\frac{A \rho_{w} g}{m}} $$

A 2.0-cm cube of metal is suspended by a fine thread attached to a scale. The cube appears to have a mass of \(47.3 \mathrm{~g}\) when measured submerged in water. What will its mass appear to be when submerged in glycerin, sp gr = 1.26? [Hint: Find \(\rho\) too.]

A glass of water has a \(10-\mathrm{cm}^{3}\) ice cube floating in it. The glass is filled to the brim with cold water. By the time the ice cube has completely melted, how much water will have flowed out of the glass? The sp gr of ice is \(0.92\).

Suppose we have a spring scale that reads in grams and we measure the mass of a cork in air to be \(5.0 \mathrm{~g} .\) Using the same scale, it is found that a sinker has an apparent mass of 86 g when completely immersed in water. The cork is attached to the sinker, the two are completely immersed in water, and now the scale reads 71 g. Determine the density of the cork. [Hint: The buoyance of the cork is responsible for the decreased scale reading.]

The diameter of the large piston of a hydraulic press is \(20 \mathrm{~cm}\), and the area of the small piston is \(0.50 \mathrm{~cm}^{2}\). If a force of \(400 \mathrm{~N}\) is applied to the small piston, (a) what is the resulting force exerted on the large piston? (b) What is the increase in pressure underneath the small piston? ( \(c\) ) Underneath the large piston?

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