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A box-shaped piece of gelatin dessert has a top area of \(15 \mathrm{~cm}^{2}\) and a height of \(3.0 \mathrm{~cm}\). When a shearing force of \(0.50 \mathrm{~N}\) is applied to the upper surface, the upper surface displaces \(4.0 \mathrm{~mm}\) relative to the bottom surface. What are the shearing stress, the shearing strain, and the shear modulus for the gelatin? $$ \begin{array}{l} \sigma_{s}=\frac{\text { Tangential force }}{\text { Area of face }}=\frac{0.50 \mathrm{~N}}{15 \times 10^{-4} \mathrm{~m}^{2}}=0.33 \mathrm{kPa} \\ \varepsilon_{s}=\frac{\text { Displacement }}{\text { Height }}=\frac{0.40 \mathrm{~cm}}{3.0 \mathrm{~cm}}=0.13 \\ S=\frac{0.33 \mathrm{kPa}}{0.13}=2.5 \mathrm{kPa} \end{array} $$

Short Answer

Expert verified
Shearing stress is 0.33 kPa, shearing strain is 0.13, and shear modulus is 2.5 kPa.

Step by step solution

01

Calculate Shearing Stress

Shearing stress is computed as the tangential force divided by the area over which it acts. The given tangential force is \(0.50\, \text{N}\) and the area is \(15\, \text{cm}^2\), which needs to be converted to \(\text{m}^2\). Thus, area = \(15 \times 10^{-4}\, \text{m}^2\). The shearing stress is \(\sigma_s = \frac{0.50\, \text{N}}{15 \times 10^{-4}\, \text{m}^2} = 0.33\, \text{kPa}\)."
02

Calculate Shearing Strain

Shearing strain is the ratio of the lateral displacement to the height of the object. The lateral displacement is \(4.0\, \text{mm} = 0.40\, \text{cm}\) and the height of the gelatin is \(3.0\, \text{cm}\). Compute the strain as \(\varepsilon_s = \frac{0.40\, \text{cm}}{3.0\, \text{cm}} = 0.13\)."
03

Calculate Shear Modulus

The shear modulus, \(S\), is the ratio of the shearing stress to the shearing strain. Given \(\sigma_s = 0.33\, \text{kPa}\) and \(\varepsilon_s = 0.13\), calculate \(S = \frac{0.33\, \text{kPa}}{0.13} = 2.5\, \text{kPa}\)."

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Shearing Stress
Shearing stress is a critical concept when studying the mechanical properties of materials. It represents the force applied parallel to the surface area over which it acts. This force causes the material to distort or deform. To quantify shearing stress, you divide the tangential force by the area it affects. For example, in our gelatin exercise, a shearing force of 0.50 N was applied to the top surface, which had an area of 15 cm虏. First, it's important to convert the area into square meters by multiplying by 10鈦烩伌, resulting in 0.0015 m虏. Calculating shearing stress: \[ \sigma_s = \frac{0.50}{0.0015} = 0.33 \, \text{kPa} \] This calculation reveals how much stress per unit area is being applied, giving insight into how the material will respond.
Shearing Strain
Shearing strain measures how much a material deforms under a shear force. This is expressed as the ratio of the change in shape to the original dimensions. Essentially, it tells us how much distortion occurs in response to the applied force.In the gelatin example, the upper surface of the gelatin shifts 4.0 mm relative to the bottom surface. Converting this to centimeters gives us 0.40 cm. With a gelatin height of 3.0 cm, the shearing strain calculation becomes straightforward.The shearing strain is computed by: \[ \varepsilon_s = \frac{0.40}{3.0} = 0.13 \] This strain value, 0.13, provides a measure of the extent of deformation relative to the height of the gelatin.
Mechanical Properties of Materials
Understanding the mechanical properties of materials, like the shear modulus, is fundamental in material science and engineering. Mechanical properties help us understand how materials react under different types of forces.The shear modulus, also known as the modulus of rigidity, measures a material's tendency to change shape when subjected to a shearing force. It is defined as the ratio of shearing stress to shearing strain, indicating the material's stiffness. In the gelatin example, given the shearing stress (0.33 kPa) and shearing strain (0.13), the shear modulus calculaton is: \[ S = \frac{0.33}{0.13} = 2.5 \, \text{kPa} \]A higher shear modulus value indicates a stiffer material that resists deformation, while a lower value points to a more ductile material that deforms easily. Knowing the shear modulus helps engineers and scientists choose the right material for applications requiring specific mechanical properties.

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Most popular questions from this chapter

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