/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 Express each of the following in... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Express each of the following in terms of other angular measures: (a) \(28^{\circ}\), (b) \(\frac{1}{4} \mathrm{rev} / \mathrm{s}\), (c) \(2.18 \mathrm{rad} / \mathrm{s}^{2}\). (a) \(28^{\circ}=(28\) deg \()\left(\frac{1 \mathrm{rev}}{360 \mathrm{deg}}\right)=0.078 \mathrm{rev}\) \(=(28 \mathrm{deg})\left(\frac{2 \pi \mathrm{rad}}{360 \mathrm{deg}}\right)=0.49 \mathrm{rad}\) (b) \(\begin{aligned} \frac{1}{4} \frac{\mathrm{rev}}{\mathrm{s}} &=\left(0.25 \frac{\mathrm{rev}}{\mathrm{s}}\right)\left(\frac{360 \mathrm{deg}}{1 \mathrm{rev}}\right)=90 \frac{\mathrm{deg}}{\mathrm{s}} \\ &=\left(0.25 \frac{\mathrm{rev}}{\mathrm{s}}\right)\left(\frac{2 \pi \mathrm{rad}}{1 \mathrm{rev}}\right)=\frac{\pi}{2} \frac{\mathrm{rad}}{\mathrm{s}} \end{aligned}\) (c) \(\begin{aligned} 2.18 \frac{\mathrm{rad}}{\mathrm{s}^{2}} &=\left(2.18 \frac{\mathrm{rad}}{\mathrm{s}^{2}}\right)\left(\frac{360 \mathrm{deg}}{2 \pi \mathrm{rad}}\right)=125 \frac{\mathrm{deg}}{\mathrm{s}^{2}} \\ &=\left(2.18 \frac{\mathrm{rad}}{\mathrm{s}^{2}}\right)\left(\frac{1 \mathrm{rev}}{2 \pi \mathrm{rad}}\right)=0.347 \frac{\mathrm{rev}}{\mathrm{s}^{2}} \end{aligned}\)

Short Answer

Expert verified
(a) 0.078 rev and 0.49 rad. (b) 90 deg/s and \(\pi/2\) rad/s. (c) 125 deg/s² and 0.347 rev/s².

Step by step solution

01

Convert Degrees to Revolutions

Convert \(28^{\circ}\) to revolutions using the conversion \(1 \text{ rev} = 360^{\circ}\):\[28^{\circ} = 28 \left( \frac{1 \text{ rev}}{360 \text{ deg}} \right) = 0.078 \text{ rev}\]
02

Convert Degrees to Radians

Convert \(28^{\circ}\) to radians using the conversion \(2\pi \text{ rad} = 360^{\circ}\):\[28^{\circ} = 28 \left( \frac{2\pi \text{ rad}}{360 \text{ deg}} \right) = 0.49 \text{ rad}\]
03

Convert Revolutions per Second to Degrees per Second

Convert \(\frac{1}{4} \text{ rev/s}\) to degrees per second:\[\frac{1}{4} \text{ rev/s} = 0.25 \text{ rev/s} \times \frac{360 \text{ deg}}{\text{ rev}} = 90 \text{ deg/s}\]
04

Convert Revolutions per Second to Radians per Second

Convert \(\frac{1}{4} \text{ rev/s}\) to radians per second:\[\frac{1}{4} \text{ rev/s} = 0.25 \text{ rev/s} \times \frac{2\pi \text{ rad}}{\text{ rev}} = \frac{\pi}{2} \text{ rad/s}\]
05

Convert Radians per Second Squared to Degrees per Second Squared

Convert \(2.18 \text{ rad/s}^2\) to degrees per second squared:\[2.18 \text{ rad/s}^2 = 2.18 \times \frac{360 \text{ deg}}{2\pi \text{ rad}} = 125 \text{ deg/s}^2\]
06

Convert Radians per Second Squared to Revolutions per Second Squared

Convert \(2.18 \text{ rad/s}^2\) to revolutions per second squared:\[2.18 \text{ rad/s}^2 = 2.18 \times \frac{1 \text{ rev}}{2\pi \text{ rad}} = 0.347 \text{ rev/s}^2\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Degrees to Radians
Understanding how to convert degrees to radians is crucial in angular measurement. This conversion is commonly used in mathematics and physics, as it allows for easier calculation in trigonometry and calculus. Degrees measure angles with the full circle being 360 degrees. Radians, on the other hand, measure angles based on the radius of a circle. In a complete circle, there are \(2\pi\) radians. To convert degrees to radians, you multiply the number of degrees by \(\frac{\pi}{180}\). For example, to convert \(28^{\circ}\) to radians:\[28^{\circ} \times \frac{\pi}{180^{\circ}} = 0.49 \, \text{rad}\]This conversion formula is vital for many applications in science and engineering, where radian measure is the standard.
Revolutions per Second
Revolutions per second (rev/s) is a unit used to express angular speed, which tells how fast an object is rotating. Understanding this concept is essential in fields like mechanical engineering and physics. One revolution is a complete turn around a circle, equivalent to \(360^{\circ}\) or \(2\pi\) radians. When mentioned as rev/s, it measures how many full circles an object completes in one second.To convert revolutions per second to degrees per second or radians per second, simply use the equivalency of 1 rev = \(360^{\circ}\) or 1 rev = \(2\pi \) rad.For example, converting \(\frac{1}{4} \, \text{rev/s}\) to degrees per second:\[0.25 \, \text{rev/s} \times 360 \, \text{deg/rev} = 90 \, \text{deg/s}\]And to radians per second:\[0.25 \, \text{rev/s} \times 2\pi \, \text{rad/rev} = \frac{\pi}{2} \, \text{rad/s}\]
Radians per Second Squared
Radians per second squared (rad/s²) is the unit of angular acceleration. It describes how quickly the angular velocity of an object is changing over time. This measure is crucial in understanding rotating systems, especially in physics and engineering.Angular acceleration, in radians per second squared, tells us how the speed of rotation is increasing or decreasing. To translate this into other units like degrees per second squared or revolutions per second squared, use the basic conversions:1 rad/s² equals \( \frac{180}{\pi} \) deg/s².Additionally, 1 rad/s² equals \( \frac{1}{2\pi} \) rev/s².For instance, converting \(2.18 \, \text{rad/s}^2\) into degrees per second squared:\[2.18 \, \text{rad/s}^2 \times \frac{180}{\pi} \, \text{deg/rad} = 125 \, \text{deg/s}^2\]And into revolutions per second squared:\[2.18 \, \text{rad/s}^2 \times \frac{1}{2\pi} \, \text{rev/rad} = 0.347 \, \text{rev/s}^2\]
Angular Velocity
Angular velocity is a vector quantity that represents the rate of rotation about an axis. It provides us with information on how fast an object rotates or spins. This is essential in various applications, from satellite motion analysis to simple mechanical clocks.Typically measured in radians per second (rad/s) or degrees per second (deg/s), angular velocity indicates the change of angular position of an object with time.For example, a wheel spinning at \(90 \, \text{deg/s}\) indicates that it rotates 90 degrees every second. In radians, the same motion equates to:\[90 \, \text{deg/s} \times \frac{\pi}{180 \, \text{deg}} = \frac{\pi}{2} \, \text{rad/s}\]By understanding angular velocity, you can predict where an object will be at a future time, assuming constant speed.
Angular Acceleration
Angular acceleration is the rate of change of angular velocity over time. It's a measure of how quickly an object speeds up or slows down its rotation.Just like linear acceleration measures changes in linear speed, angular acceleration measures changes in rotational speed. Common units for this are radians per second squared (rad/s²) or degrees per second squared (deg/s²).In practice, understanding angular acceleration helps with designing systems that involve rotational dynamics, such as car engines or wind turbines. For example, if an object accelerates from \(0\) to \( \frac{\pi}{2} \, \text{rad/s} \) in \(5\) seconds, its angular acceleration is calculated as:\[ \frac{\frac{\pi}{2} - 0}{5 \, \text{s}} = 0.314 \, \text{rad/s}^2\] Being aware of angular acceleration is crucial for predicting motion in rotating systems and ensuring smooth operation across various applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A \(200-\mathrm{g}\) object is tied to the end of a cord and whirled in a horizontal circle of radius \(1.20 \mathrm{~m}\) at a constant \(3.0 \mathrm{rev} / \mathrm{s}\). Assume that the cord is horizontal - that is, that gravity can be neglected. Determine ( \(a\) ) the centripetal acceleration of the object and ( \(b\) ) the tension in the cord. (a) The object is not accelerating tangentially to the circle but is undergoing a radial, or centripetal, acceleration given by $$ a_{c}=\frac{v^{2}}{r}=r \omega^{2} $$ where \(\omega\) must be in \(\mathrm{rad} / \mathrm{s}\). Since \(3.0 \mathrm{rev} / \mathrm{s}=6.0 \pi \mathrm{rad} / \mathrm{s}\), $$ a_{C}=(1.20 \mathrm{~m})(6.0 \pi \mathrm{rad} / \mathrm{s})^{2}=426 \mathrm{~m} / \mathrm{s}^{2}=0.43 \mathrm{~km} / \mathrm{s}^{2} $$ (b) To cause the acceleration found in \((a)\), the cord must pull on the \(0.200-\mathrm{kg}\) mass with a centripetal force given by $$ F_{C}=m a_{C}=(0.200 \mathrm{~kg})\left(426 \mathrm{~m} / \mathrm{s}^{2}\right)=85 \mathrm{~N} $$ This is the tension in the cord

( \(a\) ) Compute the radial acceleration of a point at the equator of the Earth. (b) Repeat for the North Pole of the Earth. Take the radius of the Earth to be \(6.37 \times 10^{6} \mathrm{~m}\).

A car wheel \(30 \mathrm{~cm}\) in radius is tuming at a rate of \(8.0 \mathrm{rev} / \mathrm{s}\) when the car begins to slow uniformly to rest in \(\mathrm{A}\) time of \(14 \mathrm{~s}\). Find the number of revolutions made by the wheel and the distance the car goes in the \(14 \mathrm{~s}\).

A \(60.0-\mathrm{kg}\) pilot in a glider traveling at \(40.0 \mathrm{~m} / \mathrm{s}\) wishes to turn an inside vertical loop such that his body exerts a force of \(350 \mathrm{~N}\) on the seat when the glider is at the top of the loop. What must be the radius of the loop under these conditions? [Hint: Gravity and the seat exert forces on the pilot.]

A car moving at \(5.0 \mathrm{~m} / \mathrm{s}\) tries to round a corner in a circular arc of \(8.0 \mathrm{~m}\) radius. The roadway is flat. How large must the coefficient of friction be between wheels and roadway if the car is not to skid?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.