Chapter 31: Problem 1
Compute the value of \(B\) in air at a point \(5 \mathrm{~cm}\) from a long straight wire carrying a current of \(15 \mathrm{~A}\). From Fig. \(31-1(a)\), $$ B=\frac{\mu_{0} I}{2 \pi r}=\frac{\left(4 \pi \times 10^{-7} \mathrm{~T} \cdot \mathrm{m} / \mathrm{A}\right)(15 \mathrm{~A})}{2 \pi(0.05 \mathrm{~m})}=6 \times 10^{-5} \mathrm{~T} $$
Short Answer
Step by step solution
Understand the formula
Identify the given values
Substitute values into the formula
Simplify the expression
Calculate the magnetic field
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Magnetic Field Formula
- \( B \): The magnetic field strength, measured in teslas (T).
- \( \mu_0 \): The permeability of free space, which is a constant.
- \( I \): The electric current passing through the wire in amperes (A).
- \( r \): The distance from the wire in meters (m).
Permeability of Free Space
- It serves as a bridge between the electric current and the resulting magnetic field.
- It ensures that the units are consistent when calculating pervasive magnetic effects in practical applications.
- Understanding \( \mu_0 \) helps physicists and students grasp how magnetic fields form in ideal conditions, like those found in laboratories or theoretical models.
Current in Wire
- The intensity of the magnetic field increases with the current: more current signifies a stronger magnetic field.
- It serves as the primary source of the magnetic field around the conductor, driven by the movement of electrons.
- Understanding the interplay between current and magnetic field generation helps in designing electrical systems and devices such as electromagnets and transformers.