Chapter 16: Problem 14
Find the density of methane \((M=16 \mathrm{~kg} / \mathrm{kmol})\) at \(20^{\circ} \mathrm{C}\) and \(5.0 \mathrm{~atm}\). Use \(P V=(m / M) R T\) and \(\rho=m / V\) to get $$ \rho=\frac{P M}{R T}=\frac{\left(5.0 \times 1.01 \times 10^{5} \mathrm{~N} / \mathrm{m}^{2}\right)(16 \mathrm{~kg} / \mathrm{kmol})}{(8314 \mathrm{~J} / \mathrm{kmol} \cdot \mathrm{K})(293 \mathrm{~K})}=3.3 \mathrm{~kg} / \mathrm{m}^{3} $$
Short Answer
Step by step solution
Understand the Formula
Convert Given Values
Gather Known Values
Plug Values into the Formula
Compute Density
Conclusion
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal Gas Law
- \( P \) is the pressure of the gas.
- \( V \) is the volume in which the gas is contained.
- \( n \) is the amount of substance, measured in moles.
- \( R \) is the ideal gas constant.
- \( T \) is the absolute temperature, measured in kelvins.
Molar Mass
Gas Constant
Pressure Conversion
- Multiply the pressure in atm by \( 1.01 \times 10^5 \) to get the pressure in \( \mathrm{N/m}^2 \). For example, \( 5.0 \, \mathrm{atm} \) becomes \( 5.0 \times 1.01 \times 10^5 \, \mathrm{N/m}^2 \).