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A spring whose composition is not completely known might be either bronze (sp gr 8.8) or brass (sp gr 8.4). It has a mass of \(1.26 \mathrm{~g}\) when measured in air and \(1.11 \mathrm{~g}\) in water. Which is it made of?

Short Answer

Expert verified
The spring is made of brass.

Step by step solution

01

Determine the Buoyant Force

First, we need to calculate the buoyant force exerted on the spring when it is submerged in water. This force is given by the weight of the water displaced: \( F_b = m_{air} - m_{water} = 1.26 \, \text{g} - 1.11 \, \text{g} = 0.15 \, \text{g} \).
02

Convert Grams to Milliliters (Volume)

The buoyant force in grams can be directly converted into the volume in milliliters since 1 gram of water is equivalent to 1 milliliter in volume. Therefore, the volume of the spring is: \( V = 0.15 \, \text{mL} \).
03

Calculate the Density of the Spring

The density of the spring can be calculated using the formula: \( \text{Density} = \frac{\text{Mass}}{\text{Volume}} \). Substitute the known values: \( \text{Density} = \frac{1.26 \, \text{g}}{0.15 \, \text{mL}} = 8.4 \, \text{g/mL} \).
04

Compare Density with Given Specific Gravities

Finally, compare the calculated density (8.4 g/mL) with the specific gravities of bronze and brass. Bronze has a specific gravity of 8.8, and brass has a specific gravity of 8.4. Since the density matches that of brass, the spring is made of brass.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Buoyant Force
When an object is submerged in a fluid, like water, it experiences an upward force called the buoyant force. This force is the reason why things feel lighter underwater. The buoyant force is equal to the weight of the fluid that the object displaces. In simple terms, if you drop an object in water, it will push away some of the water, and that displacement creates a force that pushes the object upwards. To determine the buoyant force in the problem, we calculated the difference between the mass of the spring in air and its mass in water. The equation was: \( F_b = m_{air} - m_{water} = 1.26 \, \text{g} - 1.11 \, \text{g} = 0.15 \, \text{g} \).This tells us that the spring displaces 0.15 grams of water when submerged, and thus experiences a buoyant force of 0.15 grams. Remember:
  • The buoyant force helps us find the volume of the object when we know the density of the fluid it is submerged in.
  • It's a key principle in fluid mechanics, established by Archimedes.
Density
Density is a measure of how much mass is contained in a given volume. It tells us how tightly packed the molecules within a substance are. We calculate density using the formula:\[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \]In our problem, the mass of the spring is 1.26 grams, and its volume can be found using the buoyant force calculated earlier, which was 0.15 mL. Converting this force directly gives us the spring's volume because 1 gram of water equals 1 milliliter. Thus, the density of the spring is:\[ \text{Density} = \frac{1.26 \, \text{g}}{0.15 \, \text{mL}} = 8.4 \, \text{g/mL} \]This crucial calculation helps in identifying the material nature of the spring.
  • If density is a high value, the material is likely dense and heavy for its size, like metals.
  • In this context, we compared the calculated density with known specific gravities to determine the spring's composition.
Mass and Volume
Mass and volume are fundamental properties of matter. Mass refers to the amount of substance within an object and is typically measured in grams or kilograms. Volume, on the other hand, is the space an object occupies, measured in units like milliliters or cubic centimeters. These two properties are critical in finding out additional characteristics of materials, such as density.In the exercise, the mass of the spring was straightforwardly given: 1.26 grams when measured in air. The volume, even though not directly given, was found through the buoyant force we calculated. Since 1 gram of water equals 1 milliliter, we directly used the mass difference in air and water to determine the spring's volume as:\( 0.15 \, \text{mL} \).This combination of mass and volume allowed us to calculate the density, giving clues about the spring's material. Always remember:
  • Mass is a constant for a given object, while volume can change depending on conditions like temperature and pressure.
  • The relation between mass and volume underlines the concept of density.

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Most popular questions from this chapter

A \(60-\mathrm{kg}\) rectangular box, open at the top, has base dimensions of \(1.0 \mathrm{~m}\) by \(0.80 \mathrm{~m}\) and a depth of \(0.50 \mathrm{~m} .(a)\) How deep will it sink in fresh water? \((b)\) What weight \(F_{W b}\) of ballast will cause it to sink to a depth of \(30 \mathrm{~cm}\) ? (a) Assuming that the box floats, $$\begin{array}{c} F_{B}=\text { Weight of displaced water }=\text { Weight of box } \\ \left(1000 \mathrm{~kg} / \mathrm{m}^{3}\right)\left(9.81 \mathrm{~m} / \mathrm{s}^{2}\right)(1.0 \mathrm{~m} \times 0.80 \mathrm{~m} \times y)=(60 \mathrm{~kg})\left(9.81 \mathrm{~m} / \mathrm{s}^{2}\right) \end{array}$$ where \(y\) is the depth the box sinks. Solving yields \(y=0.075 \mathrm{~m}\). Because this is smaller than \(0.50 \mathrm{~m}\), our assumption is shown to be correct. (b) \(F_{B}=\) weight of box \(+\) weight of ballast But the \(F_{B}\) is equal to the weight of the displaced water. Therefore, the above equation becomes $$\left(1000 \mathrm{~kg} / \mathrm{m}^{3}\right)\left(9.81 \mathrm{~m} / \mathrm{s}^{2}\right)(1.0 \mathrm{~m} \times 0.80 \mathrm{~m} \times 0.30 \mathrm{~m})=(60)(9.81) \mathrm{N}+F_{W b}$$ from which \(F_{W b}=1760 \mathrm{~N}=1.8 \mathrm{kN}\). The ballast must have a mass of \((1760 / 9.81) \mathrm{kg}=180 \mathrm{~kg}\).

What must be the volume \(V\) of a \(5.0\) -kg balloon filled with helium \(\left(\rho_{\mathrm{He}}=0.178 \mathrm{~kg} / \mathrm{m}^{3}\right)\) if it is to lift a \(30-\mathrm{kg}\) load? Use \(\rho_{\text {air }}=1.29 \mathrm{~kg} / \mathrm{m}^{3}\). The buoyant force, \(V \rho_{\mathrm{air}} g\), must lift the weight of the balloon, its load, and the helium within it: $$ V \rho_{\text {air }} g=(35 \mathrm{~kg})(g)+V \rho_{\mathrm{He}} g $$ which gives $$ V=\frac{35 \mathrm{~kg}}{\rho_{\mathrm{air}}-\rho_{\mathrm{He}}}=\frac{35 \mathrm{~kg}}{1.11 \mathrm{~kg} / \mathrm{m}^{3}}=32 \mathrm{~m}^{3} $$

A glass tube is bent into the form of a U. A \(50.0-\mathrm{cm}\) height of olive oil in one arm is found to balance \(46.0 \mathrm{~cm}\) of water in the other. What is the density of the olive oil?

A glass of water has a \(10-\mathrm{cm}^{3}\) ice cube floating in it. The glass is filled to the brim with cold water. By the time the ice cube has completely melted, how much water will have flowed out of the glass? The sp gr of ice is \(0.92\).

A metal object "weighs" \(26.0 \mathrm{~g}\) in air and \(21.48 \mathrm{~g}\) when totally immersed in water. What is the volume of the object? Its mass density?

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