Chapter 12: Problem 32
A horizontal rectangular platform is suspended by four identical wires, one at each of its corners. The wires are \(3.0 \mathrm{~m}\) long and have a diameter of \(2.0 \mathrm{~mm}\). Young's modulus for the material of the wires is \(180 \mathrm{GPa}\). How far will the platform drop (due to elongation of the wires) if a \(50-\mathrm{kg}\) load is placed at the center of the platform?
Short Answer
Step by step solution
Understand the Problem
Identify Relevant Formula
Calculate Force Applied
Calculate Cross-sectional Area
Calculate Elongation for One Wire
Account for Four Wires
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Elongation Formula
- \( F \): the force applied to the wire
- \( L_0 \): the wire's original length
- \( A \): the wire's cross-sectional area
- \( Y \): Young's modulus of the material
Cross-Sectional Area
- \( A = \pi \left(\frac{d}{2}\right)^2 \)
Applied Force
- \( F = m \cdot g \)
- \( m \) is the mass of the object in kg
- \( g \) is the acceleration due to gravity (approximately 9.81 \( \text{m/s}^2 \) on Earth)
Material Properties
- Stress divided by strain within the material's elastic limit