Chapter 11: Problem 2
A spring undergoes 12 vibrations in \(40 \mathrm{~s}\). Find the period and frequency of the oscillation. $$ T=\frac{\text { Elapsed time }}{\text { Vibrations made }}=\frac{40 \mathrm{~s}}{12}=3.3 \mathrm{~s} \quad f=\frac{\text { Vibrations made }}{\text { Elapsed time }}=\frac{12}{40 \mathrm{~s}}=0.30 \mathrm{~Hz} $$
Short Answer
Step by step solution
Understanding the Period Formula
Calculate the Period
Understanding the Frequency Formula
Calculate the Frequency
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Period of Oscillation
- \( T = \frac{\text{Elapsed time}}{\text{Number of vibrations}} \)
- \( T = \frac{40 \, \text{s}}{12} \approx 3.3 \, \text{s} \)
Frequency of Oscillation
- \( f = \frac{\text{Number of vibrations}}{\text{Elapsed time}} \)
- \( f = \frac{12}{40 \, \text{s}} = 0.30 \, \text{Hz} \)
Spring Oscillations
- The mass attached to the spring, with more mass resulting in slower oscillations (longer period, lower frequency).
- The stiffness of the spring, with stiffer springs resulting in faster oscillations (shorter period, higher frequency).