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Particle 1 with mass \(m\) and velocity \(v\) and particle 2 with mass \(2 m\) and velocity \(-2 v\) are moving toward each other along an \(x\) axis when they undergo a one-dimensional elastic collision. After the collision, what are the velocities of (a) particle 1 and (b) particle \(2 ?\) What is the velocity of the center of mass of the two-particle system (c) before and (d) after the collision?

Short Answer

Expert verified
(a) Velocity of particle 1 after collision is \(-3v\), (b) velocity of particle 2 is \(v\). (c) and (d) The center of mass velocity before and after the collision is \(-v\).

Step by step solution

01

Identify Key Variables

Let's denote the mass of particle 1 as \(m_1 = m\), the velocity of particle 1 before collision as \(v_1 = v\), the mass of particle 2 as \(m_2 = 2m\), and the velocity of particle 2 before collision as \(v_2 = -2v\). We need to find the velocities of these particles after the collision and the velocity of the center of mass both before and after.
02

Use Conservation of Momentum

Since the collision is elastic, the total momentum before and after the collision is conserved. The initial momentum \(p_i\) is given by the sum of the momenta of the two particles: \(p_i = m_1v_1 + m_2v_2 = mv - 4mv = -3mv\). After the collision, \(p_f = m_1v_1' + m_2v_2'\), where \(v_1'\) and \(v_2'\) are the velocities of particle 1 and 2 after collision. Thus, \(-3mv = m v_1' + 2m v_2'\).
03

Use Conservation of Kinetic Energy

In elastic collision, kinetic energy is also conserved. Thus, the initial kinetic energy \(KE_i\) is \(\frac{1}{2}mv_1^2 + \frac{1}{2}(2m)v_2^2 = \frac{1}{2}m v^2 + \frac{1}{2}(2m)(-2v)^2 = \frac{1}{2}mv^2 + 4mv^2\). After the collision, \(KE_f = \frac{1}{2}mv_1'^2 + \frac{1}{2}(2m)v_2'^2\). Therefore, \(\frac{1}{2}mv^2 + 4mv^2 = \frac{1}{2}mv_1'^2 + m v_2'^2\).
04

Solve Equations Simultaneously

Solving the equations \(-3mv = m v_1' + 2m v_2'\) and \(\frac{1}{2}mv^2 + 4mv^2 = \frac{1}{2}mv_1'^2 + m v_2'^2\) gives us \(v_1' = -3v\) and \(v_2' = v\), meaning particle 1 reverses direction and particle 2 moves to the right.
05

Calculate Center of Mass Velocity Before Collision

The velocity of the center of mass \(v_{cm}\) is calculated using \(v_{cm} = \frac{m_1v_1 + m_2v_2}{m_1 + m_2}\). Before the collision, \(v_{cm} = \frac{mv +2m(-2v)}{3m} = -\frac{3v}{3} = -v\).
06

Calculate Center of Mass Velocity After Collision

After the collision, since the velocities of the particles change, but the mass distribution does not change, \(v_{cm,after} = \frac{m(-3v) + 2m(v)}{3m} = -v\). This indicates that the velocity of the center of mass remains the same.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Momentum
In an elastic collision, the total momentum of the system remains constant before and after the collision. This concept is pivotal in understanding how particles interact dynamically.
To calculate the momentum, a simple formula is utilized:
  • Momentum before collision: \( p_i = m_1v_1 + m_2v_2 \)
  • Momentum after collision: \( p_f = m_1v_1' + m_2v_2' \)
Here, \( v_1' \) and \( v_2' \) are the velocities of particle 1 and particle 2 after the collision, respectively. Because momentum is conserved, \( p_i = p_f \). So, regardless of what happens during the collision, the total momentum conserved allows us to predict the post-collision velocities.
This means that even though each particle may change its velocity through the collision, the sum of their mass-velocity products remains the same. This principle allows us to form one of the core equations needed to solve collision problems.
Conservation of Kinetic Energy
In addition to momentum, kinetic energy is also conserved in elastic collisions. Kinetic energy relates to the speed and mass of an object, providing insight into the energy dynamics involved.
The initial and final kinetic energies in an elastic collision are:
  • Initial kinetic energy: \( KE_i = \frac{1}{2}m_1v_1^2 + \frac{1}{2}m_2v_2^2 \)
  • Final kinetic energy: \( KE_f = \frac{1}{2}m_1v_1'^2 + \frac{1}{2}m_2v_2'^2 \)
For elastic collisions, \( KE_i = KE_f \), indicating that no kinetic energy is lost during the process.
This conservation, coupled with the conservation of momentum, provides the mathematical framework needed to solve for the velocities after the collision. It tells us that while energy can transfer from one particle to another, the total amount of kinetic energy in the system remains unchanged.
Center of Mass
The center of mass is a crucial concept in understanding the collective motion of a system of particles. For two particles, the center of mass velocity \( v_{cm} \) is given by:
\[ v_{cm} = \frac{m_1v_1 + m_2v_2}{m_1 + m_2} \]This formula calculates the weighted average velocity of the system, essentially representing how the entire system moves as if all the mass were concentrated at one point.
Initial and final velocities of the center of mass can be different, but in this exercise, they were identical before and after the collision. This reflects that, beyond the local interactions of collision, the overall motion as dictated by the center of mass remains unchanged. Understanding this helps to grasp both the symmetry in particle dynamics and the conservation laws at play.
Particle Dynamics
Particle dynamics describes how particles move and interact through forces and collisions. In elastic collisions, like those in this exercise, particles exchange momentum and energy effectively.
You can think of particles like tiny billiard balls hitting one another. They may bounce back, exchange speeds, or switch directions, but they never lose energy to the environment.
Key Points:
  • Each particle's velocity is influenced by its mass and momentum of other particles in a system.
  • The path and final velocities can be predicted by using conservation laws described earlier.
Understanding these dynamics involves predicting the results of interactions like collisions through equations and laws of physics, making it a rich and intriguing aspect of physics that models the real-world motions.

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