/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 36 Two children are playing a game ... [FREE SOLUTION] | 91Ó°ÊÓ

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Two children are playing a game in which they try to hit a small box on the floor with a marble fired from a spring-loaded gun that is mounted on a table. The target box is horizontal distance \(D=2.20 \mathrm{~m}\) from the edge of the table; see Fig. 8-36. Bobby compresses the spring \(1.10 \mathrm{~cm}\), but the center of the marble falls \(26.3 \mathrm{~cm}\) short of the center of the box. How far should Rhoda compress the spring to score a direct hit? Assume that neither the spring nor the ball encounters friction in the gun.

Short Answer

Expert verified
Rhoda should compress the spring by approximately 1.25 cm.

Step by step solution

01

Understand the Problem

The main objective is to determine how much Rhoda should compress the spring in order to make a direct hit with the marble. We know the distance the marble falls short when Bobby compresses the spring by a certain amount.
02

Relation of Marble's compression and Distance

When Bobby compresses the spring by 1.10 cm, the marble falls 26.3 cm short of the target. Therefore, the total distance the marble travels is given by its initial distance of 220 cm minus the 26.3 cm shortfall. So, the marble travels 193.7 cm.
03

Calculate the Ratio of Spring Compression and Distance Traveled

The initial spring compression by Bobby is 1.10 cm. With this compression, the marble travels 193.7 cm. We need to find the distance the marble should travel to reach 220 cm, which is exactly the distance from the gun to the box.
04

Use Proportionality to Find New Compression

To calculate the required compression for Rhoda, we apply a ratio: \[ \frac{d_1}{d_2} = \frac{c_1}{c_2} \]where \(d_1 = 193.7\text{ cm}\), \(d_2 = 220\text{ cm}\), and \(c_1 = 1.1\text{ cm}\) is Bobby's spring compression.Substituting the known values:\[ \frac{193.7}{220} = \frac{1.1}{c_2} \]
05

Calculate Rhoda's Compression

Solve for \(c_2\):\[ c_2 = \frac{1.1 \times 220}{193.7} \approx 1.25 \text{ cm} \]This result shows that Rhoda should compress the spring by approximately 1.25 cm.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring Compression
In this physics problem, the key concept explored is how compressing a spring can affect the distance a marble will travel once it is shot from a spring-loaded gun. The main principle at play is Hooke's Law, which states that the force exerted by a spring is proportional to its compression. That means the more you compress the spring, the greater the force and thus the further the marble will go when released. This happens because the potential energy stored in the compressed spring is converted into kinetic energy that propels the marble forward.

Compressing a spring stores energy. This energy is gained by the marble when the spring releases. In the problem, we need to determine how much more Rhoda should compress the spring compared to Bobby to achieve a specific goal: hitting the target box. This requires understanding the relationship between spring compression and the resulting motion of the marble.
Proportionality
Proportionality is a simple but powerful tool that can help us solve various physics problems, such as this one. In essence, proportionality means that two ratios are equal. This concept allows us to predict how changing one variable affects another. In the case of spring compression, the distance the marble travels is directly proportional to how much the spring is compressed.

In the exercise, the distance achieved by Bobby's initial spring compression and the required distance to hit the target provide us with a ratio. We compare the ratio of these distances to the ratio of the spring compressions. Using proportionality, we calculate how much more Rhoda needs to compress the spring. This relationship can be expressed by the equation:
  • \(\frac{d_1}{d_2} = \frac{c_1}{c_2}\)
Where \(d_1\) and \(d_2\) are the respective distances, and \(c_1\) and \(c_2\) are the respective spring compressions. This gives us a straightforward method to determine the necessary compression for a successful shot.
Distance Calculation
Calculating distances in projectile motion is essential for understanding where the marble will land. In this situation, we know two critical distances: the desired distance to hit the target box and the distance the marble fell short when fired. By using these distances, we can adjust the spring compression to reach exactly where we aim.

The given problem shows that Bobby's shot fell short by 26.3 cm from the target. His marble traveled 193.7 cm due to the 1.10 cm spring compression. We want to find the required spring compression for Rhoda to make the marble travel the necessary 220 cm.

Therefore, understanding the distances involved allows us to apply our proportional relationship and solve for Rhoda's new spring compression.
Physics Problem Solving
Physics problem solving often involves breaking down complex problems into more manageable parts. In this exercise, we followed logical steps that integrated physics principles to arrive at the solution.

Initially, we understood the given data and the requirement—how far the marble shot with a specific spring compression falls short of the target. Then we used proportionality to relate spring compression to the distance the marble needs to travel.

This type of step-by-step approach is crucial:
  • Identify known and unknown variables.
  • Understand the underlying physical principles.
  • Apply mathematical relationships to solve for the unknowns.
Using this technique not only helps solve specific problems like the one in the exercise but also builds a strong foundation for tackling more complex physics scenarios in the future.

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