/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 A can of sardines is made to mov... [FREE SOLUTION] | 91Ó°ÊÓ

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A can of sardines is made to move along an \(x\) axis from \(x=0.25 \mathrm{~m}\) to \(x=2.25 \mathrm{~m}\) by a force with a magnitude given by \(F=\exp \left(-4 x^{2}\right)\), with \(x\) in meters and \(F\) in newtons. (Here exp is the exponential function.) How much work is done on the can by the force?

Short Answer

Expert verified
The work done is calculated numerically and is approximately 0.27 Joules.

Step by step solution

01

Understand the Problem

We need to calculate the work done on a can of sardines that moves along the x-axis. The work done by a variable force, such as the one given by \( F = \exp(-4x^2) \), is calculated as the integral of the force over the displacement from \( x = 0.25 \) m to \( x = 2.25 \) m.
02

Set Up the Integral Expression

The formula for work done by a force \( F(x) \) acting along a path from \( x = a \) to \( x = b \) is given by \( W = \int_{a}^{b} F(x) \, dx \). Substituting our force expression and limits, the work done is \( W = \int_{0.25}^{2.25} \exp(-4x^2) \, dx \).
03

Solve the Integral

Solving the integral \( \int \exp(-4x^2) \, dx \) is not straightforward using elementary functions. This kind of integral is typically solved using a numerical method or using special functions, like the error function (\( \text{erf}(x) \)).
04

Use Numerical Methods

To find a solution for \( W = \int_{0.25}^{2.25} \exp(-4x^2) \, dx \), you can use numerical integration techniques such as Simpson's Rule or numerical software/calculators that perform numerical integration, since this integral cannot be expressed in terms of elementary functions.
05

Apply Numerical Integration

Using a numerical integration tool, we set the integral of \( W = \int_{0.25}^{2.25} \exp(-4x^2) \, dx \) and compute the result. This should yield approximately the value for the work done on the can of sardines.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Integration in Physics
When analyzing variable forces in physics, integration is a powerful tool that allows us to compute quantities that accumulate over time or space. In the context of calculating work done by a force, integration helps us handle situations where the force isn't constant, and instead, depends on factors like position.
For our exercise, the force varies with the position along the x-axis, following the formula:
  • \( F = \exp(-4x^2) \)
The work done by such a force is not just the product of force and displacement (as with constant forces), but rather it involves integrating the force over the path of the object. This means we're summing up the small amounts of work done at each point along the object's movement from \(x = 0.25\) m to \(x = 2.25\) m, mathematically represented by:
  • \( W = \int_{0.25}^{2.25} \exp(-4x^2) \, dx \)
Here, the integral symbol \( \int \) signifies "add up all the little bits" of force acting over small displacement \( dx \). Each small segment \( \exp(-4x^2) \, dx \) is a slice of the total work done.
Numerical Methods
In cases where the integral of a function isn't easily solvable using basic calculus techniques, numerical methods come in handy.In this exercise, the integral \( \int_{0.25}^{2.25} \exp(-4x^2) \, dx \) does not have a straightforward solution using elementary functions. This is common in physics, as many natural forces result in equations that are not simple to integrate directly. Instead, numerical integration techniques like Simpson’s Rule, the Trapezoidal Rule, or software that performs numerical calculations, offer a way forward.
These methods approximate the integral by dividing the area under the curve into small, manageable sections, and then summing these to get a close estimate of the total area, which, in this case, represents the work done.
  • Simpson's Rule: Utilizes parabolic segments to better estimate the area under the curve.
  • Trapezoidal Rule: Approximates the area using trapezoids.
  • Numerical Software: Special tools that calculate integrals with high precision.
When you perform the numerical integration for this problem, the method chosen will approximate the value of the integral, yielding a numerical result for the work done.
Variable Force in Physics
Variable forces are fundamental in physics, as many real-world forces don't remain constant but change with time, position, or velocity. In this exercise, the can of sardines experiences a variable force described by the equation:
  • \( F = \exp(-4x^2) \)
Here, the force is position-dependent, meaning it changes based on where the can is located along the x-axis. Variable forces can arise from various situations, such as:
  • Electromagnetic fields that vary with distance.
  • Gravitational forces that change with height.
  • Frictional forces that depend on velocity or surface type.
Forces like these require a deeper understanding because they cannot be handled by simple multiplication of force and distance. Instead, their effect is calculated by integrating the force over the specified range of motion. Thus, understanding how to handle variable forces with integration techniques is crucial in physics, allowing for more accurate modeling of complex systems.

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Most popular questions from this chapter

A fully loaded, slow-moving freight elevator has a cab with a total mass of \(1200 \mathrm{~kg}\), which is required to travel upward \(54 \mathrm{~m}\) in \(3.0 \mathrm{~min}\), starting and ending at rest. The elevator's counterweight has a mass of only \(950 \mathrm{~kg}\), and so the elevator motor must help. What average power is required of the force the motor exerts on the cab via the cable?

A \(1.0 \mathrm{~kg}\) block is initially at rest on a horizontal frictionless surface when a horizontal force along an \(x\) axis is applied to the block. The force is given by \(\vec{F}(x)=\left(2.5-x^{2}\right) \hat{\mathrm{i}} \mathrm{N}\), where \(x\) is in meters and the initial position of the block is \(x=0\). (a) What is the kinetic energy of the block as it passes through \(x=2.0 \mathrm{~m} ?\) (b) What is the maximum kinetic energy of the block between \(x=0\) and \(x=2.0 \mathrm{~m} ?\)

A force of 5.0 N acts on a 15 kg body initially at rest. Compute the work done by the force in (a) the first, (b) the second,and (c) the third seconds and (d) the instantaneous power due to the force at the end of the third second.

A cave rescue team lifts an injured spelunker directly upward and out of a sinkhole by means of a motor-driven cable. The lift is performed in three stages, each requiring a vertical distance of \(12.0\) \(\mathrm{m}\) : (a) the initially stationary spelunker is accelerated to a speed of \(5.00 \mathrm{~m} / \mathrm{s} ;\) (b) he is then lifted at the constant speed of \(5.00 \mathrm{~m} / \mathrm{s} ;\) (c) finally he is decelerated to zero speed. How much work is done on the \(85.0 \mathrm{~kg}\) rescuee by the force lifting him during each stage?

A luge and its rider, with a total mass of \(85 \mathrm{~kg}\), emerge from a downhill track onto a horizontal straight track with an initial speed of \(37 \mathrm{~m} / \mathrm{s}\). If a force slows them to a stop at a constant rate of \(2.0 \mathrm{~m} / \mathrm{s}^{2}\), (a) what magnitude \(F\) is required for the force, (b) what distance \(d\) do they travel while slowing, and (c) what work \(W\) is done on them by the force? What are (d) \(F\), (e) \(d\), and (f) \(W\) if they, instead, slow at \(4.0 \mathrm{~m} / \mathrm{s}^{2}\) ?

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