/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 A cord is used to vertically low... [FREE SOLUTION] | 91Ó°ÊÓ

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A cord is used to vertically lower an initially stationary block of mass \(M\) at a constant downward acceleration of \(g / 4\). When the block has fallen a distance \(d\), find (a) the work done by the cord's force on the block, (b) the work done by the gravitational force on the block, (c) the kinetic energy of the block, and (d) the speed of the block.

Short Answer

Expert verified
a) \(-\frac{3}{4} Mgd\), b) \(Mgd\), c) \(\frac{1}{4} Mgd\), d) \(\sqrt{\frac{g}{2} d}\)."

Step by step solution

01

Understanding the forces acting on the block

The block is subject to two forces: the gravitational force \( F_g = Mg \) downward and the force from the cord \( T \) upward. Since the block is accelerating downward with acceleration \( a = g/4 \), we apply Newton's second law: \( Mg - T = Ma \).
02

Solve for the tension in the cord

From \( Mg - T = Ma \), we substitute \( a = g/4 \): \( Mg - T = M \frac{g}{4} \). Solving for \( T \), we get \( T = Mg - M \frac{g}{4} = M \frac{3g}{4} \).
03

Calculate work done by the cord's force

The work done by the cord's force is given by \( W_T = T \cdot d \cdot \cos(180^\circ) = -T \cdot d \) (since the force is upward and the displacement is downward). Substituting \( T = M \frac{3g}{4} \), the work done by the cord is \( W_T = -M \frac{3g}{4} d \).
04

Calculate work done by gravitational force

The gravitational force does work \( W_g = F_g \cdot d = Mg \cdot d \cdot \cos(0^\circ) = Mg \cdot d \), since the force and displacement are in the same direction.
05

Calculate the kinetic energy of the block

The work-energy principle states that the net work done on the block is equal to its change in kinetic energy. The net work \( W_{net} = W_g + W_T \). Substituting the works: \( W_{net} = Mg \cdot d - M \frac{3g}{4} d = M \frac{g}{4} d \). Thus, the kinetic energy \( KE = M \frac{g}{4} d \).
06

Determine the speed of the block

The kinetic energy is also given by \( KE = \frac{1}{2} M v^2 \). Solving for \( v \), we have \( M \frac{g}{4} d = \frac{1}{2} M v^2 \). Simplifying, \( v^2 = \frac{g}{2} d \), so \( v = \sqrt{\frac{g}{2} d} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Newton's Second Law
Newton's Second Law is a fundamental concept in physics that describes the behavior of objects when forces are applied to them. It states that the acceleration of an object is directly proportional to the net force acting on it, and inversely proportional to its mass. This can be expressed with the formula:
  • \( F = ma \)
The force \( F \) is the total net force applied to an object, \( m \) is the mass of the object, and \( a \) is the acceleration.
In this exercise, the block being lowered is influenced by both the gravitational force and the tension in the cord.
  • Gravitational force is pulling the block downward.
  • The tension in the cord is pulling it upward.
Newton's second law helps us understand how these forces contribute to the block's downward acceleration.
Here, the equation becomes \( Mg - T = Ma \), allowing us to express how the forces balance and calculate for tension.
Gravitational Force
Gravitational force is one of the essential forces in nature, attracting two bodies towards each other with a force proportional to their masses. On Earth, this means any object with mass experiences a downward force due to gravity, which is approximately \( 9.81 \, \text{m/s}^2 \).
  • For an object with mass \( M \): \( F_g = Mg \)
  • This gravitational force acts downward.
In this exercise, gravitational force is responsible for pulling the block downwards, contributing to its motion.
The work done by this force while the block falls a distance \( d \) is crucial for calculating other properties like kinetic energy. Because the force is in the same direction as the displacement, the work done by gravity is simply:
  • \( W_g = F_g \, d = Mg \, d \)
This work plays a vital role in the block’s energy transformation during its fall.
Kinetic Energy
Kinetic energy is the energy of an object due to its motion. It is expressed as:
  • \( KE = \frac{1}{2} M v^2 \)
where \( M \) is the mass of the object and \( v \) is its velocity.
When the block starts moving, it transitions some of the potential energy (due to its height) to kinetic energy.
Using the work-energy principle, we find that the net work done on the block equals its change in kinetic energy.
  • The net work done \( W_{net} = Mg \, d - M \frac{3g}{4} \, d = M \frac{g}{4} \, d \).
  • This means the block's kinetic energy at distance \( d \) is \( KE = M \frac{g}{4} \, d \).
This equation tells us how much energy the block has gained as a result of its fall.
Tension in Cord
The tension force in a cord, such as a rope or string, is a pulling force that acts along the length of the cord, opposing other forces like gravity in this setup.
  • In the context of the exercise, tension in the cord interacts with gravity.
  • It's the force trying to 'pull back' the block to prevent free fall.
This concept can be illustrated with Newton’s second law:
  • Given by \( T = Mg - M \frac{g}{4} = M \frac{3g}{4} \)
  • The formula calculates tension by accounting for the block's downward acceleration \( a = g/4 \).
Tension is pivotal in determining how fast the block accelerates.
It’s the balancing force against gravity, causing a controlled descent rather than a free fall. Understanding tension helps in designing systems that require controlled movements, like elevators or cranes.

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Most popular questions from this chapter

A particle travels through a three-dimensional displacement given by \(\vec{d}=(5.00 \hat{\mathrm{i}}-3.00 \hat{\mathrm{j}}+4.00 \hat{\mathrm{k}}) \mathrm{m}\). If a force of magnitude \(22.0 \mathrm{~N}\) and with fixed orientation does work on the particle, find the angle between the force and the displacement if the change in the particle's kinetic energy is (a) \(45.0 \mathrm{~J}\) and (b) \(-45.0 \mathrm{~J}\).

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