/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 A police officer in hot pursuit ... [FREE SOLUTION] | 91Ó°ÊÓ

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A police officer in hot pursuit drives her car through a circular turn of radius 300 m with a constant speed of 75.0 km/h. Her mass is 55.0 kg.What are (a) the magnitude and (b) the angle (relative to vertical) of the net force of the officer on the car seat? (Hint: Consider both horizontal and vertical forces.)

Short Answer

Expert verified
(a) Magnitude of net force is 545 N. (b) Angle with vertical is 8.38°.

Step by step solution

01

Convert Speed to Meters Per Second

First, convert the officer's speed from kilometers per hour to meters per second. We do this by multiplying by the conversion factor:\[ 75.0 \text{ km/h} = 75.0 \times \frac{1000 \text{ m}}{3600 \text{ s}} = 20.83 \text{ m/s} \]
02

Calculate Centripetal Force

The centripetal force required to keep the car moving in a circle of radius 300 m with a speed of 20.83 m/s is calculated using the formula:\[ F_c = \frac{m v^2}{r} \]Substitute the values:\[ F_c = \frac{(55.0 \text{ kg}) \times (20.83 \text{ m/s})^2}{300 \text{ m}} \approx 79.1 \text{ N} \]
03

Calculate Gravitational Force

The gravitational force acting on the officer is given by:\[ F_g = m \cdot g \]where \( g = 9.8 \text{ m/s}^2 \). Substituting the given mass:\[ F_g = 55.0 \text{ kg} \times 9.8 \text{ m/s}^2 = 539 \text{ N} \]
04

Calculate the Magnitude of the Net Force

The net force on the officer is found by calculating the vector sum of the centripetal and gravitational forces. Since these forces are perpendicular, use the Pythagorean theorem:\[ F_{\text{net}} = \sqrt{F_g^2 + F_c^2} \]Substitute the values:\[ F_{\text{net}} = \sqrt{(539 \text{ N})^2 + (79.1 \text{ N})^2} \approx 545 \text{ N} \]
05

Calculate the Angle with Vertical

The angle \( \theta \) that the net force makes with the vertical (gravitational force direction) is found using the tangent function:\[ \tan(\theta) = \frac{F_c}{F_g} \]Solving for \( \theta \):\[ \theta = \tan^{-1}\left( \frac{79.1 \text{ N}}{539 \text{ N}} \right) \approx 8.38^\circ \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Circular Motion
Circular motion refers to the movement of an object along a circular path. It's a fascinating concept in physics because, although an object in circular motion moves at a constant speed, the direction of its velocity changes constantly, which means the object is always accelerating. This change in direction requires a force pointing towards the center of the circle the object is moving around—a force called the centripetal force. For example, in the case of the police officer driving through a circular turn, the car must exert a centripetal force to maintain its path. Otherwise, it would simply move off in a straight line due to inertia. The formula for centripetal force is:\[ F_c = \frac{m v^2}{r} \]where:
  • \( F_c \) is the centripetal force,
  • \( m \) is the mass of the object,
  • \( v \) is the velocity or speed of the object,
  • \( r \) is the radius of the circle.
Understanding circular motion is crucial for studying objects like planets orbiting stars or cars taking curved roads.
Gravitational Force
Gravitational force is a fundamental force in physics that attracts two bodies towards each other. Every object with mass exerts a gravitational force, but this force becomes significant when at least one of the objects has a large mass, such as the Earth. In the context of the exercise, the gravitational force is the force with which Earth pulls the police officer towards its center. This force can be calculated using the formula:\[ F_g = m \cdot g \]where:
  • \( F_g \) is the gravitational force,
  • \( m \) is the mass of the officer,
  • \( g \) is the acceleration due to gravity, approximately \( 9.8 \text{ m/s}^2 \).
This force is always directed vertically downward and plays a vital role in determining the net force an object experiences when other forces, like centripetal force, are also acting on it.
Vector Addition
Vector addition is the method used to determine the resultant of two or more vectors. Vectors are quantities that have both magnitude and direction, like force, velocity, and displacement. In the exercise case, the police officer experiences both centripetal force and gravitational force, making it necessary to find a net force. These forces act perpendicularly, so they form a right angle with each other. To find the net force, we use vector addition, which involves drawing vectors and performing calculations to determine their resultant. The resultant vector can be found using graphical methods or analytical approaches like the Pythagorean theorem and trigonometry for perpendicular vectors. Vector addition is a fundamental skill for solving physics problems involving forces acting in different directions.
Pythagorean Theorem
The Pythagorean theorem is a mathematical principle that relates the lengths of the sides of a right-angled triangle. This theorem is crucial for calculating net forces, especially when dealing with perpendicular vectors, as in this exercise.The theorem states:\[ a^2 + b^2 = c^2 \]where:
  • \( a \) and \( b \) are the lengths of the two shorter sides (legs) of the triangle,
  • \( c \) is the length of the hypotenuse, or the longest side.
In our exercise, the Pythagorean theorem is used to find the magnitude of the net force exerted on the officer. The gravitational force and centripetal force make up the two legs of the triangle, while the net force is the hypotenuse:\[ F_{\text{net}} = \sqrt{F_g^2 + F_c^2} \]Using the Pythagorean theorem simplifies complex vector calculations by turning them into straightforward arithmetic.

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Most popular questions from this chapter

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