/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 61 A hot-air balloon of mass \(M\) ... [FREE SOLUTION] | 91Ó°ÊÓ

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A hot-air balloon of mass \(M\) is descending vertically with downward acceleration of magnitude \(a\). How much mass (ballast) must be thrown out to give the balloon an upward acceleration of magnitude \(a\) ? Assume that the upward force from the air (the lift) does not change because of the decrease in mass.

Short Answer

Expert verified
The mass to be thrown out is \( m = \frac{2Ma}{2a + g} \).

Step by step solution

01

Understand the Forces Involved

The forces acting on the balloon are gravity and lift. The downward force due to gravity is the weight of the balloon, given by \( Mg \). The buoyant force (lift) is constant and initially allows the balloon to descend with acceleration \( a \).
02

Analyze Initial Descent

During descent, the net force is the difference between gravitational force and lift, which allows us to write \( Mg - L = Ma \). Here \( L \) is the lift force.
03

Set Up Equation for Ascend

For the balloon to ascend with acceleration \( a \), we need the lift to overcome the new weight of the balloon. This gives us \( L = (M - m)g + (M - m)a \), where \( m \) is the mass to be thrown out.
04

Equate Lift in Both Situations

Since the lift force \( L \) is constant, set the expressions for \( L \) from both the descent and the ascent phase equal: \( Mg - Ma = (M - m)g + (M - m)a \).
05

Solve for the Mass to be Thrown Out

Re-arrange the equation \( Mg - Ma = (M - m)g + (M - m)a \) to \[ m(2a + g) = 2Ma \]. Solving for \( m \) gives \[ m = \frac{2Ma}{2a + g} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Force and Acceleration
Understanding how force leads to acceleration is key in this problem. According to Newton's Second Law, the force acting on an object is equal to its mass times its acceleration. Mathematically, this is expressed as \( F = ma \), where \( F \) is the force, \( m \) is the mass, and \( a \) is the acceleration.
For the hot-air balloon scenario, two main forces impact the balloon: gravity and lift. Gravity pulls the balloon downward with a force equal to its weight, or \( Mg \), where \( g \) is the acceleration due to gravity.
On the other hand, the lift exerts an upward force that partially counteracts gravity. When the balloon has a downward acceleration \( a \), it implies that the net force is still acting downward, confirming that the gravitational force is stronger than the lift, leading to \( Mg - L = Ma \). Understanding this interaction helps us figure out how changes in mass affect the motion of the balloon.
Buoyancy
Buoyancy is the upward force that opposes the weight of an object made to float or immersed in a fluid. In the case of the hot-air balloon, buoyancy is represented by the lift force that counters gravitational pull. This lift does not change with the balloon's mass, as it's based on the air properties and the balloon's volume.
When we need to change the balloon's motion from descending to ascending, it's crucial to adjust the mass being lifted, not the lift itself. In the exercise, the lift remains constant, as noted when changing the balloon's behavior from descending with acceleration \( a \) to ascending with the same acceleration. Therefore, understanding buoyancy as constant helps us focus on adjusting the mass when seeking the necessary change in motion.
Vertical Motion
When considering vertical motion, it's important to look at the forces acting up and down. Vertical motion is controlled by the balance between these forces, which dictates whether an object accelerates, decelerates, or maintains a constant speed.
For the balloon, initially descending with acceleration \( a \), the net force is acting downward. To make the balloon ascend, the direction of the net force must also change.
The solution involves making the upward force due to lift exceed the downward force of gravity by a greater margin. To achieve this change in vertical motion, the exercise determines how much ballast (additional weight) needs to be removed, using the relationship between mass, force, and acceleration.
Mass and Weight
Mass and weight are often used interchangeably but are distinct concepts. Mass is a measure of the amount of matter in an object, whereas weight is the force exerted on that mass by gravity. Weight is calculated as \( W = mg \), where \( m \) is the mass and \( g \) is the gravitational acceleration.
In the balloon problem, mass plays a critical role. To control the balloon's motion, we adjust its weight by removing some mass. The exercise shows how to compute the exact amount of mass to discard in order to reverse the balloon's acceleration while using constant lift. The equation \( m = \frac{2Ma}{2a + g} \) provides the needed mass to be thrown out, linking the initial conditions and desired outcomes precisely.

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