Chapter 44: Problem 21
Observations of neutrinos emitted by the supernova SN1987a (Fig. 43-12b) place an upper limit of \(20 \mathrm{eV}\) on the rest energy of the electron neutrino. If the rest energy of the electron neutrino were, in fact, \(20 \mathrm{eV}\), what would be the speed difference between light and a \(1.5 \mathrm{MeV}\) electron neutrino?
Short Answer
Step by step solution
Understand the Rest Energy Formula
Energy-Momentum Relationship Review
Calculate the Lorentz Factor
Solve for the Speed of the Neutrino
Calculate Speed Difference
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Rest Energy
- \( E \) is the rest energy.
- \( m \) is the rest mass of the particle.
- \( c \) is the speed of light in a vacuum, approximately \( 3 \, \times 10^8 \) meters per second.
Lorentz Factor
- \( v \) is the velocity of the particle.
- \( c \) is the speed of light.