/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 In 1992, Swiss police arrested t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In 1992, Swiss police arrested two men who were attempting to smuggle osmium out of Eastern Europe for a clandestine sale. However, by error, the smugglers had picked up \({ }^{137} \mathrm{Cs}\). Reportedly, each smuggler was carrying a \(1.0 \mathrm{~g}\) sample of \({ }^{137} \mathrm{Cs}\) in a pocket! In (a) bequerels and (b) curies, what was the activity of each sample? The isotope \({ }^{137} \mathrm{Cs}\) has a half-life of \(30.2 \mathrm{y}\). (The activities of radioisotopes commonly used in hospitals range up to a few millicuries.)

Short Answer

Expert verified
Each sample's activity is approximately 3.215 x 10^12 Bq or 0.0868 Ci.

Step by step solution

01

Understand the Definitions

A bequerel (Bq) is the SI unit for measuring radioactivity and is defined as one decay per second. A curie (Ci) is another unit of radioactivity defined as 3.7 x 10^10 decays per second. These units will help us calculate the activity.
02

Calculate Decay Constant

The decay constant (λ) can be calculated using the formula \( \lambda = \frac{\ln(2)}{T_{1/2}} \), where \( T_{1/2} \) is the half-life of the substance. For \({ }^{137} \mathrm{Cs}\), \( T_{1/2} = 30.2 \) years. Convert this to seconds: \( 30.2 \times 365 \times 24 \times 3600 \). Then calculate \( \lambda \).
03

Determine the Number of Nuclei

Find the number of nuclei in 1 gram of \({ }^{137} \mathrm{Cs}\). Use Avogadro's number \( N_A = 6.022 \times 10^{23} \) and the molar mass of \(^{137}Cs\), which is 137 g/mol. The number of moles is \( \frac{1}{137} \) moles, so the number of nuclei is \( \frac{1}{137} \times 6.022 \times 10^{23} \).
04

Calculate Activity in Bequerels

Activity (A) in Bq is given by \( A = \lambda N \), where \( N \) is the number of radioactive nuclei. Substitute for \( \lambda \) and \( N \) which were calculated earlier to find the activity in bequerels.
05

Convert Activity to Curies

To find the activity in curies, use the conversion factor: 1 Ci = 3.7 x 10^10 Bq. Convert the activity calculated in bequerels to curies using this conversion.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Bequerel
The bequerel, abbreviated as Bq, is a unit used to measure radioactivity. It refers to one radioactive decay event occurring every second.
The concept is crucial because it quantitatively represents how active a radioactive substance is. If you think about radioactivity in terms of energy and particles being emitted, the bequerel gives us an exact measurement of that emission rate.
For example, if a material has an activity of 1 Bq, it means that 1 atomic nucleus decays each second. Measurements like this are vital in fields such as nuclear medicine, where knowing the level of radioactivity helps doctors manage doses for patients.
It is essential to remember that while the bequerel gives precise decay information, the actual energy released per decay event can vary between different radioactive materials.
Curie
The curie, symbolized as Ci, is another unit for measuring radioactivity, but significantly larger than the bequerel. It is defined based on the activity of one gram of radium-226, amounting to 3.7 x 10^10 decays per second.
Unlike the bequerel, which gives a straightforward count per second, the curie deals with much larger quantities and is often used when describing large radioactive sources.
To illustrate, a sample with an activity of 1 Ci would see 3.7 x 10^10 decay events per second, making it a very substantial indicator of radioactive intensity.
This unit becomes very practical in environments dealing with significant amounts of radioactive material, like in industries or nuclear power facilities, where understanding the potential radiation impact is critical.
A notable point is that conversions between bequerels and curies are essential for practical applications, especially when aligning international measurements and standards in science.
Half-Life
Half-life is a fundamental concept in understanding radioactive decay. It represents the time required for half of the radioactive nuclei in a sample to decay.
This period is constant for a given radioisotope, allowing for predictable calculations of decay over time.
For example, the half-life of Cesium-137 (\(^{137}\text{Cs}\)) is 30.2 years, meaning every 30.2 years, the amount of radioactive \(^{137}\text{Cs}\) reduces to half its previous quantity.
Understanding half-life is crucial for applications ranging from radioactive waste management to the use of isotopes in medical treatments. It helps in predicting how long a substance remains dangerously radioactive and the timing required for its potency in treatments.
Decay Constant
The decay constant (\(\lambda\)) plays a key role in the mathematics of radioactivity. Its value signifies the likelihood that a nucleus will decay per unit of time and is central to calculating activity.
Defined as \(\lambda = \frac{\ln(2)}{T_{1/2}}\), where \(T_{1/2}\) is the half-life, \(\lambda\) connects the physical half-life of a substance with its decay rate.
By using the decay constant, we can derive how quickly a sample loses its radioactivity, making it a vital part of the equations that govern radioactive processes.
For instance, once you know the half-life of \(^{137}\text{Cs}\), calculating \(\lambda\) allows us to find out just how energetic or active the sample is at any given moment.
Radioisotope
Radioisotopes, or radioactive isotopes, are atoms with unstable nuclei that release radiation as they move towards stability. These isotopes were present in the smuggled samples of cesium-137.
They have diverse applications across several fields.
  • In medicine: Used in diagnostics and treatment, such as in imaging techniques or cancer therapy.
  • In industry: Used for checking the integrity of materials or in power generation.
  • In research: Provide crucial insights when studying biochemical and chemical processes.
Working with radioisotopes requires careful handling due to the radiation they emit. Understanding these isotopes and their properties helps in making responsible use of their powerful applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

An organic sample of mass \(4.00 \mathrm{~kg}\) absorbs \(2.00 \mathrm{~mJ}\) via slow neutron radiation \((\mathrm{RBE}=5)\). What is the dose equivalent \((\mathrm{mSv})\) ?

What is the binding energy per nucleon of the europium isotope \(\frac{152}{63}\) Eu? Here are some atomic masses and the neutron mass. $$ \begin{array}{lrrr} { }_{63}^{152} \mathrm{Eu} & 151.921742 \mathrm{u} & { }^{1} \mathrm{H} & 1.007825 \mathrm{u} \\ \mathrm{n} & 1.008665 \mathrm{u} & & \end{array} $$

Generally, more massive nuclides tend to be more unstable to alpha decay. For example, the most stable isotope of uranium, \({ }^{238} \mathrm{U}\), has an alpha decay half-life of \(4.5 \times 10^{9} \mathrm{y} .\) The most stable isotope of plutonium is \({ }^{244} \mathrm{Pu}\) with an \(8.0 \times 10^{7} \mathrm{y}\) half-life, and for curium we have \({ }^{248} \mathrm{Cm}\) and \(3.4 \times 10^{5} \mathrm{y}\). When half of an original sample of \({ }^{238} \mathrm{U}\) has decayed, what fraction of the original sample of (a) plutonium and (b) curium is left?

A \(1.00 \mathrm{~g}\) sample of samarium emits alpha particles at a rate of 120 particles/s. The responsible isotope is \({ }^{147} \mathrm{Sm}\), whose natural abundance in bulk samarium is \(15.0 \%\). Calculate the half-life.

When aboveground nuclear tests were conducted, the explosions shot radioactive dust into the upper atmosphere. Global air circulations then spread the dust worldwide before it settled out on ground and water. One such test was conducted in October \(1976 .\) What fraction of the \({ }^{90}\) Sr produced by that explosion still existed in October \(2006 ?\) The half-life of \({ }^{90} \mathrm{Sr}\) is \(29 \mathrm{y}\).

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.