/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 12 An atom (not a hydrogen atom) ab... [FREE SOLUTION] | 91Ó°ÊÓ

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An atom (not a hydrogen atom) absorbs a photon whose associated frequency is \(5.6 \times 10^{14} \mathrm{~Hz}\). By what amount does the en ergy of the atom increase?

Short Answer

Expert verified
The energy of the atom increases by \(3.7116 \times 10^{-19} \text{ J}\).

Step by step solution

01

Identify the Relationship

To start solving the problem, we need to remember that the energy of a photon can be calculated using the formula \(E = h \cdot f\), where \(E\) is the energy of the photon, \(h\) is Planck's constant \(6.626 \times 10^{-34} \text{ Js}\), and \(f\) is the frequency of the photon.
02

Substitute the Given Values

Now, we substitute the given frequency of the photon, \(f = 5.6 \times 10^{14} \text{ Hz}\), into the formula \(E = h \times f\). So, \(E = 6.626 \times 10^{-34} \times 5.6 \times 10^{14}\).
03

Calculate the Energy of the Photon

Let's perform the multiplication to find the energy: \(E = 6.626 \times 10^{-34} \times 5.6 \times 10^{14} = 3.7116 \times 10^{-19} \text{ J}\).
04

Conclusion on Energy Increase

Since the photon's energy is fully absorbed by the atom, the atom's energy increases by an amount equal to the energy of the photon, which is \(3.7116 \times 10^{-19} \text{ J}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Frequency
The frequency of a wave tells us how often the wave's crest passes a certain point in one second. It's measured in hertz (Hz), which means cycles per second. For photons and other electromagnetic waves, frequency is a fundamental property because it relates directly to energy.

In our problem, the frequency of the photon is given as \(5.6 \times 10^{14}\) Hz. This high frequency suggests that the photon belongs to the visible or near-infrared part of the electromagnetic spectrum, which is common in many atomic transitions.

It’s important to recognize that frequency has a direct relationship with energy. Higher frequency means higher energy. This is described quantitatively by the formula \(E = h \cdot f\), where \(E\) is energy, \(f\) is frequency, and \(h\) is Planck's constant. Understanding this relationship is key in fields such as quantum physics and chemistry, where energy levels and transitions are critical.
  • Frequency helps determine the energy of a photon.
  • More frequent waves, i.e., higher frequency, carry more energy.
  • Frequency is tied closely with color and energy in atomic processes.
Planck's Constant
Planck’s constant is a fundamental constant in quantum mechanics, symbolized as \(h\). Its value is approximately \(6.626 \times 10^{-34}\) joule-seconds (Js). This seemingly small number plays a huge role in the realm of particles and waves.

When Max Planck introduced this constant, it was to solve the ultraviolet catastrophe in black-body radiation. However, it opened the door to quantum theory, revolutionizing physics by suggesting that energy is quantized, or comes in packets, called quanta or photons for light.

Planck's constant links the frequency of a photon to its energy through the relationship \(E = h \cdot f\). This formula shows that even small changes in frequency produce significant changes in energy, illustrating why Planck’s constant is so pivotal in describing the behavior of subatomic particles.
  • Symbolized by \(h\) and valued at \(6.626 \times 10^{-34}\) Js.
  • Essential for calculating photon energies.
  • Foundation of quantum mechanics, connecting wave and particle duality.
Atomic Absorption
Atomic absorption occurs when an atom takes in energy from a photon, resulting in a change in the atom’s energy level. When a photon is absorbed, its energy is transferred to the atom, often exciting an electron to a higher energy state or level.

In the context of our exercise, the atom absorbs a photon with a frequency of \(5.6 \times 10^{14}\) Hz. This absorption causes the energy of the atom to increase by \(3.7116 \times 10^{-19}\) J, exactly the energy of the photon that was absorbed. This is a perfect example of how the conservation of energy principle works at an atomic level.

Understanding atomic absorption is crucial in spectroscopy and quantum chemistry, where researchers investigate how substances interact with different light frequencies.
  • Photon absorption leads to an increase in atomic energy.
  • Energy gain corresponds to the energy of the absorbed photon.
  • Key concept in fields like spectroscopy and chemical analysis.

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Most popular questions from this chapter

A one-dimensional infinite well of length \(200 \mathrm{pm}\) contains an electron in its third excited state. We position an electron-detector probe of width \(2.00 \mathrm{pm}\) so that it is centered on a point of maximum probability density. (a) What is the probability of detection by the probe? (b) If we insert the probe as described 1000 times, how many times should we expect the electron to materialize on the end of the probe (and thus be detected)?

An electron in a one-dimensional infinite potential well of length \(L\) has ground-state energy \(E_{1}\). The length is changed to \(L^{\prime}\) so that the new ground-state energy is \(E_{1}^{\prime}=0.500 E_{1}\). What is the ratio \(L^{\prime} / L ?\)

An electron (mass \(m\) ) is contained in a cubical box of widths \(L_{x}=L_{y}=L_{z}\). (a) How many different frequencies of light could the electron emit or absorb if it makes a transition between a pair of the lowest five energy levels? What multiple of \(h / 8 m L^{2}\) gives the (b) lowest, (c) second lowest, (d) third lowest, (e) highest, (f) second highest, and \((\mathrm{g})\) third highest frequency?

A hydrogen atom is excited from its ground state to the state with \(n=4\). (a) How much energy must be absorbed by the atom? Consider the photon energies that can be emitted by the atom as it de-excites to the ground state in the several possible ways. (b) How many different energies are possible; what are the (c) highest, (d) second highest, (e) third highest, (f) lowest, (g) second lowest, and ( \(\mathrm{h}\) ) third lowest energies?

What is the ground-state energy of (a) an electron and (b) a proton if each is trapped in a one-dimensional infinite potential well that is \(300 \mathrm{pm}\) wide?

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