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Entoptic halos. If someone looks at a bright outdoor lamp in otherwise dark surroundings, the lamp appears to be surrounded by bright and dark rings (hence halos) that are actually a circular diffraction pattern as in Fig. 36-10, with the central maximum overlapping the direct light from the lamp. The diffraction is produced by structures within the cornea or lens of the eye (hence entoptic). If the lamp is monochromatic at wavelength \(550 \mathrm{~nm}\) and the first dark ring subtends angular diameter \(2.0^{\circ}\) in the observer's view, what is the (linear) diameter of the structure producing the diffraction?

Short Answer

Expert verified
The structure causing diffraction has a linear diameter of approximately 38.4 micrometers.

Step by step solution

01

Understand the Problem

We need to find the linear diameter of a structure in the eye that produces a circular diffraction pattern. The pattern is composed of bright and dark rings, and we are given the angular diameter of the first dark ring and the wavelength of light.
02

Use the Diffraction Formula

We need to use the formula for the angular position of the first minimum in a circular diffraction pattern, which is given by: \[ \theta = 1.22 \frac{\lambda}{d} \]where \( \theta \) is the angular radius of the first minimum, \( \lambda \) is the wavelength of the light, and \( d \) is the linear diameter of the aperture (or structure causing diffraction).
03

Convert Angular Diameter to Angular Radius

The angular diameter of the first dark ring given is \( 2.0^{\circ} \). The angular radius \( \theta \) is half of this diameter: \[ \theta = \frac{2.0^{\circ}}{2} = 1.0^{\circ} \]
04

Convert Degrees to Radians

Angles in the formula need to be in radians. Convert \( 1.0^{\circ} \) to radians:\[ \theta = 1.0^{\circ} \times \frac{\pi}{180^{\circ}} \approx 0.01745 \text{ radians} \]
05

Rearrange the Formula to Solve for Diameter

Rearrange the diffraction formula to solve for \( d \): \[ d = 1.22 \frac{\lambda}{\theta} \]
06

Plug in the Values

Plug the values into the rearranged formula:\[ d = 1.22 \times \frac{550 \times 10^{-9} \text{ m}}{0.01745} \]
07

Calculate the Diameter

Perform the computation to find \( d \):\[ d \approx 3.84 \times 10^{-5} \text{ m} \]The linear diameter of the structure is approximately \( 38.4 \text{ micrometers} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Entoptic Halos
Entoptic halos are a fascinating phenomenon that occurs when bright light sources appear to be encircled by concentric rings of light and dark bands. These halos are particularly visible when you observe a bright outdoor lamp in a dark environment. The reason they are called "entoptic" is that the diffraction causing these patterns happens within the eye itself, typically in structures like the cornea or lens.

The appearance of entoptic halos is a direct result of a circular diffraction pattern, which is caused when light waves bend around small obstacles within the eye. This effect is more evident in monochromatic light, meaning light of a single wavelength, like the 550 nm light mentioned. When such light encounters tiny structures, it produces a pattern of alternating bright and dark rings, creating the illusion of halos around a light source.
Circular Diffraction
Circular diffraction refers to the bending and spreading out of light waves when they pass around the edges of a circular aperture or object. This is a fundamental concept in optics and is responsible for the halo patterns seen in entoptic phenomena.

In the case of entoptic halos, the structures in the eye act as the apertures. Light spreads out and forms a series of minima and maxima, visible as rings. The first minimum in these patterns is a crucial point of calculation, as it marks the transition from a bright to a dark ring. This point is used to calculate parameters like the linear diameter of the diffracting structure using formulas derived from diffraction theory.
  • The central maximum of this pattern directly overlaps with the light source itself.
  • The rings get progressively fainter and wider away from the light source.
Wavelength of Light
The wavelength of light plays a critical role in the formation of diffraction patterns. Wavelength is the distance between consecutive peaks of a wave and is usually measured in nanometers (nm). In the given exercise, light with a wavelength of 550 nm is used.

This specific wavelength falls within the visible spectrum, corresponding to the color green. When light of this wavelength undergoes diffraction, it influences the size and spacing of the diffraction pattern. Specifically, the position of the dark and bright rings (minima and maxima) is highly dependent on the wavelength used. Shorter wavelengths would result in patterns with smaller, tighter rings, while longer wavelengths would produce larger patterns.
Angular Diameter
Angular diameter is the apparent size of an object, as perceived by an observer. It's measured in degrees and describes how much of the observer's field of view an object takes up. When dealing with circular diffraction, the angular diameter helps determine the size of the diffraction pattern.

In the exercise, the angular diameter of the first dark ring is provided as 2.0 degrees. To compute diffraction parameters, this diameter needs to be converted to an angular radius, which is half the diameter (1.0 degree). Conversion to radians is necessary for calculations, as mathematical formulas in physics often require angle measures in radians to ensure accuracy.
  • For practical applications, understanding angular diameter allows for the estimation of the size of the structures causing diffraction.
  • This understanding is critical in deriving relevant physical characteristics like the linear diameter of diffracting structures using mathematical models.

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Most popular questions from this chapter

a) How many bright fringes appear between the first diffraction-envelope minima to either side of the central maximum in a double-slit pattern if \(\lambda=550 \mathrm{~nm}, d=0.180 \mathrm{~mm}\), and \(a=30.0 \mu \mathrm{m}\) ? (b) What is the ratio of the intensity of the third bright fringe to the intensity of the central fringe?

The wall of a large room is covered with acoustic tile in which small holes are drilled \(6.0 \mathrm{~mm}\) from center to center. How far can a person be from such a tile and still distinguish the individual holes, assuming ideal conditions, the pupil diameter of the observer's eye to be \(4.0 \mathrm{~mm}\), and the wavelength of the room light to be \(550 \mathrm{~nm}\) ?

In the single-slit diffraction experiment of Fig. \(36-4\), let the wavelength of the light be \(500 \mathrm{~nm}\), the slit width be \(6.00 \mu \mathrm{m}\), and the viewing screen be at distance \(D=4.00 \mathrm{~m}\). Let a \(y\) axis extend upward along the viewing screen, with its origin at the center of the diffraction pattern. Also let \(I_{p}\) represent the intensity of the diffracted light at point \(P\) at \(y=15.0 \mathrm{~cm}\). (a) What is the ratio of \(I_{P}\) to the intensity \(I_{m}\) at the center of the pattern? (b) Determine where point \(P\) is in the diffraction pattern by giving the maximum and minimum between which it lies, or the two minima between which it lies.

The \(D\) line in the spectrum of sodium is a doublet with wavelengths \(589.0\) and \(589.6 \mathrm{~nm}\). Calculate the minimum number of lines needed in a grating that will resolve this doublet in the third-order spectrum.

Sound waves with frequency \(2500 \mathrm{~Hz}\) and speed \(343 \mathrm{~m} / \mathrm{s}\) diffract through the rectangular opening of a speaker cabinet and into a large auditorium of length \(d=100 \mathrm{~m}\). The opening, which has a horizontal width of \(30.0 \mathrm{~cm}\), faces a wall \(100 \mathrm{~m}\) away (Fig. 36-35). Along that wall, how far from the central axis will a listener be at the first diffraction minimum and thus have difficulty hearing the sound? (Neglect reflections.)

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