/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 28 An \(x\)-ray beam of a certain w... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

An \(x\)-ray beam of a certain wavelength is incident on an \(\mathrm{NaCl}\) crystal, at \(30.0^{\circ}\) to a certain family of reflecting planes of spacing \(37.6 \mathrm{pm}\). If the reflection from those planes is of the first order, what is the wavelength of the \(x\) rays?

Short Answer

Expert verified
The X-ray wavelength is 37.6 pm.

Step by step solution

01

Understand the Problem

We need to find the wavelength of an X-ray beam when it is reflected from a crystal at a given angle and spacing between planes. This can be solved using Bragg's Law.
02

Introduce Bragg's Law

Bragg's Law is given by the equation \( n\lambda = 2d\sin(\theta) \). For this problem, \( n \) is the order of reflection, \( \lambda \) is the wavelength, \( d \) is the spacing between crystal planes, and \( \theta \) is the angle of incidence.
03

Substitute Known Values

In the given problem, \( n = 1 \) (first-order reflection), \( d = 37.6 \) pm, and \( \theta = 30.0^{\circ} \). Substitute these values into Bragg's Law: \( 1\times\lambda = 2\times37.6\times\sin(30.0^{\circ}) \).
04

Calculate Sin and Wavelength

Calculate \( \sin(30.0^{\circ}) = 0.5 \). Substitute into the equation to get \( \lambda = 2 \times 37.6 \times 0.5 \).
05

Complete the Calculation

Perform the multiplication: \( \lambda = 2 \times 37.6 \times 0.5 = 37.6 \) pm.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

X-ray diffraction
X-ray diffraction is a phenomenon that occurs when X-rays are scattered by the orderly arrangement of atoms in a crystal. This process reveals the crystal's atomic and molecular structure because the pattern of scattered X-rays produces a unique diffraction pattern. These patterns result from constructive interference of X-rays scattered in specific directions.

This technique is pivotal in fields like chemistry and physics as it allows scientists to determine the structure of complex molecules, such as proteins and minerals. It works because different elements scatter X-rays uniquely, creating intricate patterns that can be analyzed.
  • X-rays have wavelengths in the range of atomic spacings, making them ideal for studying crystal structures.
  • Diffraction patterns act like fingerprints for identifying crystal structures.
  • Understanding X-ray diffraction is key in materials science for developing new materials.
This diffraction also relies on a predictable angle-dependent scattering that can be analyzed using Bragg's Law, crucial for calculating various parameters like wavelength.
Crystal lattice
A crystal lattice is a highly ordered structure where atoms or molecules are arranged in a repeating pattern, extending in all three spatial dimensions. This regular arrangement forms a structure that is characteristic of crystalline materials like salt, diamond, and metals.

In the context of X-ray diffraction, a crystal lattice plays a crucial role. The planes of atoms in a crystal lattice serve as multiple closely-spaced mirrors that scatter the incident X-rays.
  • Lattice structures determine the diffraction pattern owing to their specific three-dimensional arrangement.
  • They are defined by unit cells, the smallest repeating units in a crystal, which contains information about the entire structure.
  • The spacing between these planes influences the angles and intensities of the diffracted beams.
For scientists, analyzing these diffraction patterns provides information about the positions of atoms within the crystal, allowing for the deduction of the structure's full geometric layout.
Wavelength calculation
Wavelength calculation in the context of X-ray diffraction is often achieved using Bragg's Law, which correlates the X-ray wavelength with the angle of incidence and the spacing between planes in a crystal lattice. This relationship is crucial for determining the X-ray wavelengths used in diffraction experiments.

Bragg's Law is expressed in the formula: \[ n\lambda = 2d\sin(\theta) \]where
  • \( n \) is the order of reflection, often an integer.
  • \( \lambda \) represents the wavelength of the X-rays.
  • \( d \) is the distance between crystallographic planes.
  • \( \theta \) is the angle of incidence.
To calculate the unknown wavelength from known values, you rearrange the formula based on given problem data. For example, by substituting the angle, order, and plane spacing into the equation, one can solve for the wavelength as demonstrated in the exercise. This calculation is foundational in X-ray crystallography, as it helps visualize unseen atomic structures.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The radar system of a navy cruiser transmits at a wavelength of \(1.6 \mathrm{~cm}\), from a circular antenna with a diameter of \(2.3 \mathrm{~m}\). At a range of \(5.6 \mathrm{~km}\), what is the smallest distance that two speedboats can be from each other and still be resolved as two separate objects by the radar system?

A grating has 350 lines/mm. How many orders of the entire visible spectrum \((400-700 \mathrm{~nm})\) can it produce in a diffraction experiment, in addition to the \(m=0\) order?

The telescopes on some commercial surveillance satellites can resolve objects on the ground as small as \(85 \mathrm{~cm}\) across (see Google Earth), and the telescopes on military surveillance satellites reportedly can resolve objects as small as \(10 \mathrm{~cm}\) across. Assume first that object resolution is determined entirely by Rayleigh's criterion and is not degraded by turbulence in the atmosphere. Also assume that the satellites are at a typical altitude of \(420 \mathrm{~km}\) and that the wavelength of visible light is \(550 \mathrm{~nm}\). What would be the required diameter of the telescope aperture for (a) \(85 \mathrm{~cm}\) resolution and (b) \(10 \mathrm{~cm}\) resolution? (c) Now, considering that turbulence is certain to degrade resolution and that the aperture diameter of the Hubble Space Telescope is \(2.4 \mathrm{~m}\), what can you say about the answer to (b) and about how the military surveillance resolutions are accomplished?

Light of wavelength \(420 \mathrm{~nm}\) is incident on a narrow slit. The angle between the first diffraction minimum on one side of the central maximum and the first minimum on the other side is \(2.00^{\circ}\). What is the width of the slit?

Sound waves with frequency \(2500 \mathrm{~Hz}\) and speed \(343 \mathrm{~m} / \mathrm{s}\) diffract through the rectangular opening of a speaker cabinet and into a large auditorium of length \(d=100 \mathrm{~m}\). The opening, which has a horizontal width of \(30.0 \mathrm{~cm}\), faces a wall \(100 \mathrm{~m}\) away (Fig. 36-35). Along that wall, how far from the central axis will a listener be at the first diffraction minimum and thus have difficulty hearing the sound? (Neglect reflections.)

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.