/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 A small laser emits light at pow... [FREE SOLUTION] | 91Ó°ÊÓ

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A small laser emits light at power \(5.00 \mathrm{~mW}\) and wavelength \(633 \mathrm{~nm}\). The laser beam is focused (narrowed) until its diameter matches the \(1206 \mathrm{~nm}\) diameter of a sphere placed in its path. The sphere is perfectly absorbing and has density \(5.00 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\). What are (a) the beam intensity at the sphere's location, (b) the radiation pressure on the sphere, (c) the magnitude of the corresponding force, and (d) the magnitude of the acceleration that force alone would give the sphere?

Short Answer

Expert verified
(a) Intensity is approximately \(4.39 \times 10^9 \text{ W/m}^2\). (b) Radiation pressure is around \(14.6 \text{ Pa}\). (c) Force is about \(1.66 \times 10^{-11} \text{ N}\). (d) Acceleration is approximately \(3.62 \times 10^6 \text{ m/s}^2\).

Step by step solution

01

Calculate the Laser Beam Intensity

The intensity of the laser beam can be calculated using the formula for intensity: \[I = \frac{P}{A}\]where \(P\) is the power of the laser and \(A\) is the area of the beam. The area of a circle is \(A = \pi \left(\frac{d}{2}\right)^2\), where \(d\) is the diameter of the beam, which is the same as the sphere's diameter. So,\[A = \pi \left(\frac{1206 \times 10^{-9} \text{ m}}{2}\right)^2\]\[A = \pi \times (603 \times 10^{-9})^2\]\[A \approx 1.14 \times 10^{-12} \text{ m}^2\]Then, the intensity:\[I = \frac{5.00 \times 10^{-3} \text{ W}}{1.14 \times 10^{-12} \text{ m}^2}\]\[I \approx 4.39 \times 10^9 \text{ W/m}^2\]
02

Determine the Radiation Pressure on the Sphere

The radiation pressure \(P_{r}\) for a perfectly absorbing sphere is given by:\[P_{r} = \frac{I}{c}\]where \(I\) is the intensity of the beam, and \(c = 3.00 \times 10^8 \text{ m/s}\) is the speed of light. Substituting the intensity we found:\[P_{r} = \frac{4.39 \times 10^9 \text{ W/m}^2}{3.00 \times 10^8 \text{ m/s}}\]\[P_{r} \approx 14.6 \text{ Pa}\]
03

Calculate the Force on the Sphere

The force \(F\) exerted on a surface by radiation pressure is given by:\[F = P_{r} \times A\]Using the area \(A\) calculated in Step 1:\[F = 14.6 \text{ Pa} \times 1.14 \times 10^{-12} \text{ m}^2\]\[F \approx 1.66 \times 10^{-11} \text{ N}\]
04

Calculate the Acceleration of the Sphere

The acceleration \(a\) of the sphere can be found using Newton's second law \(F = m \cdot a\). First, calculate the mass \(m\) of the sphere:\[m = \text{volume} \times \text{density}\]For a sphere, the volume is:\[V = \frac{4}{3} \pi \left(\frac{d}{2}\right)^3\]\[V = \frac{4}{3} \pi (603 \times 10^{-9})^3\]\[V \approx 9.18 \times 10^{-22} \text{ m}^3\]Then, using the density \(5.00 \times 10^{3} \text{ kg/m}^3\), calculate mass:\[m = 9.18 \times 10^{-22} \text{ m}^3 \times 5.00 \times 10^{3} \text{ kg/m}^3\]\[m \approx 4.59 \times 10^{-18} \text{ kg}\]Now, calculate acceleration:\[a = \frac{F}{m}\]\[a = \frac{1.66 \times 10^{-11} \text{ N}}{4.59 \times 10^{-18} \text{ kg}}\]\[a \approx 3.62 \times 10^6 \text{ m/s}^2\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Intensity of Light
The concept of light intensity is pivotal when discussing laser beams and their effects. Intensity refers to the amount of energy a light beam carries in a given area per second. It's measured in watts per square meter (\(\text{W/m}^2\)).
To find the intensity of a light beam, such as from a laser, you use the formula: \(I = \frac{P}{A}\), where \(P\) is the power of the laser and \(A\) is the area over which the power is spread. For Example:
- Calculate the area \(A\) of the beam: the area of a circle (since the beam is usually circular) is \(A = \pi\left(\frac{d}{2}\right)^2\), with \(d\) being the diameter.
- This means if a laser has a power output of 5 mW (milliwatts) and a beam diameter of 1206 nm, you can determine its intensity.
- The area would be \(A \approx 1.14 \times 10^{-12} \text{ m}^2\) and thus, the intensity \(I \approx 4.39 \times 10^9 \text{ W/m}^2\).
Understanding intensity is crucial as it affects how much pressure and force the light exerts on objects. The stronger the intensity, the more substantial its impacts.
Force Calculation
Calculating the force due to light on a surface involves understanding radiation pressure. Radiation pressure is the pressure exerted by light when it hits a surface.
For a perfectly absorbing object like our sphere, the radiation pressure \(P_r\) can be calculated by dividing the light's intensity by the speed of light \(c\): \(P_r = \frac{I}{c}\).
Here’s how it works:
- With intensity \(I = 4.39 \times 10^9 \text{ W/m}^2\) and \(c = 3.00 \times 10^8 \text{ m/s}\), we find \(P_r \approx 14.6 \text{ Pa}\) (pascals).
- The force (\(F\)) exerted by this pressure on the sphere is found by multiplying the pressure by the area it affects: \(F = P_r \times A\).
- Using our previously calculated area \(A \approx 1.14 \times 10^{-12} \text{ m}^2\), the force \(F \approx 1.66 \times 10^{-11} \text{ N}\).
Therefore, this calculation is essential for understanding how light can influence motion and behavior in microscopic systems.
Acceleration Due to Light Pressure
Acceleration due to light pressure is an intriguing demonstration of how light, a seemingly intangible phenomenon, can produce physical movement. This effect follows from Newton's second law of motion.
Here’s the approach:
- First, determine the mass \(m\) of the sphere, which involves calculating its volume and using its density: 1. Volume \(V = \frac{4}{3}\pi\left(\frac{d}{2}\right)^3\) for our sphere results in \(V \approx 9.18 \times 10^{-22} \text{ m}^3\). 2. With a density of \(5.00 \times 10^{3} \text{ kg/m}^{3}\), the mass is \(m \approx 4.59 \times 10^{-18} \text{ kg}\).
- Then, utilize the force calculated earlier \(F \approx 1.66 \times 10^{-11} \text{ N}\) and apply Newton’s formula \(a = \frac{F}{m}\) to find acceleration.
- This gives an acceleration \(a \approx 3.62 \times 10^6 \text{ m/s}^2\).
Understanding acceleration due to light pressure is particularly important in fields like space technology, where light-powered propulsion is a potential area of exploration.

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Most popular questions from this chapter

Figure 33-45 depicts a simplistic optical fiber: a plastic core \(\left(n_{1}=1.58\right)\) is surrounded by a plastic sheath \(\left(n_{2}=1.46\right)\). A light ray is incident on one end of the fiber at angle \(\theta\). The ray is to undergo total internal reflection at point \(A\), where it encounters the core-sheath boundary. (Thus there is no loss of light through that bound- ary.) What is the maximum value of \(\theta\) that allows total internal reflection at \(A\) ?

Light in vacuum is incident on the surface of a glass slab. In the vacuum the beam makes an angle of \(32.0^{\circ}\) with the normal to the surface, while in the glass it makes an angle of \(16.0^{\circ}\) with the normal. What is the index of refraction of the glass?

A plane electromagnetic wave, with wavelength \(5.0 \mathrm{~m}\), travels in vacuum in the positive direction of an \(x\) axis. The electric field, of amplitude \(215 \mathrm{~V} / \mathrm{m}\), oscillates parallel to the \(y\) axis. What are the (a) frequency, (b) angular frequency, and (c) angular wave number of the wave? (d) What is the amplitude of the magnetic field component? (e) Parallel to which axis does the magnetic field oscillate? (f) What is the time-averaged rate of energy flow in watts per square meter associated with this wave? The wave uniformly illuminates a surface of area \(2.0 \mathrm{~m}^{2}\). If the surface totally absorbs the wave, what are \((g)\) the rate at which momentum is transferred to the surface and (h) the radiation pressure on the surface?

An airplane flying at a distance of \(10 \mathrm{~km}\) from a radio transmitter receives a signal of intensity \(28 \mu \mathrm{W} / \mathrm{m}^{2}\). What is the amplitude of the (a) electric and (b) magnetic component of the signal at the airplane? (c) If the transmitter radiates uniformly over a hemisphere, what is the transmission power?

An isotropic point source emits light at wavelength \(500 \mathrm{~nm}\), at the rate of \(300 \mathrm{~W}\). A light detector is positioned \(400 \mathrm{~m}\) from the source. What is the maximum rate \(\partial B / \partial t\) at which the magnetic component of the light changes with time at the detector's location?

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