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A certain type of glass has an index of refraction of \(1.62\) for red light. (a) At what angle will light (in air) be completely polarized when reflected by the glass? (b) Will the reflection angle for complete polarization of blue light be larger or smaller?

Short Answer

Expert verified
(a) 58.0°; (b) The angle will be larger for blue light.

Step by step solution

01

Understand Brewster's Angle

The angle at which light is completely polarized when reflected from a surface is known as Brewster's angle. Brewster's angle can be found using the formula: \[\tan(\theta_B) = \frac{{n_2}}{{n_1}}\]where \(n_2\) is the index of refraction of the medium that the light enters, and \(n_1\) is the index of refraction of the initial medium (typically air with \(n_1 = 1\)).
02

Calculate Brewster's Angle for Red Light

Given that the index of refraction of the glass for red light is \(n_2 = 1.62\), and \(n_1 = 1\) for air, plug in these values into Brewster's angle formula:\[\tan(\theta_B) = \frac{1.62}{1} = 1.62\]To find \(\theta_B\), take the arctan of 1.62 using a calculator:\[\theta_B = \tan^{-1}(1.62) \approx 58.0^\circ\]
03

Consider Blue Light Refraction Index

To determine if the reflection angle for complete polarization of blue light is larger or smaller, we need to know its index of refraction. For most materials, the index for blue light is higher than for red light. Assume \(n_2(blue) > 1.62\).
04

Determine Effect on Brewster's Angle for Blue Light

If \(n_2\) increases, then the tangent of Brewster's angle \(\tan(\theta_B)\) increases, which means \(\theta_B\) itself (arctan of a higher value) will also increase. Thus, the reflection angle for complete polarization of blue light is larger than that for red light.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Brewster's Angle
When light encounters a surface, it can be reflected or refracted. At a certain angle, known as Brewster's Angle, the reflected light is completely polarized. This means that the reflected light waves oscillate in a single plane. Brewster's Angle occurs when the angle between the reflected and refracted rays is 90 degrees.

The key to finding Brewster's Angle, \(\theta_B\), lies in using the formula:
  • \(\tan(\theta_B) = \frac{n_2}{n_1}\)
Here, \(n_2\) represents the index of refraction of the medium the light enters (like glass), and \(n_1\) represents the index of refraction of the medium the light is coming from (usually air, with \(n_1 = 1\)).

For red light entering glass with an index of refraction of \(1.62\), Brewster's Angle can be calculated as follows:
  • \(\tan(\theta_B) = 1.62\)
  • \(\theta_B = \tan^{-1}(1.62) \approx 58.0^\circ\)
Polarization
Light waves can oscillate in different planes. In natural (unpolarized) light, these oscillations occur in all directions perpendicular to the direction of travel. Polarization refers to the process of restricting the oscillations of light waves to a particular plane.

Polarized light can be created in several ways:
  • Reflection: As light reflects off a surface at Brewster’s Angle, the reflected light becomes completely polarized.
  • Transmission: Using polarizing filters can allow only certain light waves to pass through, resulting in polarized light.
Polarized light is common in various applications such as sunglasses, camera filters, and LCD screens. Understanding polarization helps to manage light's behavior in many optical technologies.
Index of Refraction
The index of refraction, denoted as \(n\), is a number that describes how light propagates through a medium. It is defined as the ratio of the speed of light in a vacuum to the speed of light in the medium.
  • \(n = \frac{c}{v}\)
Where \(c\) is the speed of light in a vacuum (approximately \(3 \times 10^8\) m/s), and \(v\) is the speed of light in the medium. Different colors of light may refract differently, leading to different indices of refraction for each color. Typically, blue light has a slightly higher index of refraction than red light when passing through the same medium.

This is important for calculations involving Brewster's Angle. If the index for blue light is higher, the resulting Brewster's Angle will also be larger, which means more refraction occurs.

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