Chapter 32: Problem 32
A parallel-plate capacitor with circular plates of radius \(R\) is being charged. Show that the magnitude of the current density of the displacement current is \(J_{d}=\mathrm{e}_{0}(d E / d t)\) for \(r \leq R\).
Short Answer
Expert verified
Displacement current density is \( J_d = \epsilon_0 \frac{dE}{dt} \).
Step by step solution
01
Understand the Problem
We have a parallel-plate capacitor with circular plates, and we need to find the expression for the magnitude of the displacement current density, \( J_d \), using the relationship given by \( J_d = \epsilon_0 \frac{dE}{dt} \), where \( \epsilon_0 \) is the permittivity of free space and \( E \) is the electric field between the plates.
02
Recall the Concept of Displacement Current
The displacement current arises in regions of changing electric fields and is described by the equation \( J_d = \epsilon_0 \frac{dE}{dt} \). In a charging capacitor, the electric field \( E \) changes over time as charge accumulates on the plates.
03
Review the Electric Field Between Capacitor Plates
For a parallel-plate capacitor, the electric field \( E \) is uniform and can be defined as \( E = \frac{Q}{\epsilon_0 A} \), where \( Q \) is the charge on the plates and \( A = \pi R^2 \) is the area of the plates.
04
Introduce Displacement Current Density Formula
Using the formula for displacement current density \( J_d = \epsilon_0 \frac{dE}{dt} \), we can see that \( J_d \) is proportional to the rate of change of the electric field \( E \) between the plates.
05
Calculate the Time Derivative of Electric Field
Compute the rate of change of the electric field \( \frac{dE}{dt} \). If the charge \( Q \) on the capacitor changes with time, then \( \frac{dE}{dt} = \frac{1}{\epsilon_0 A} \frac{dQ}{dt} \).
06
Relate Current to Displacement Current
The current \( I \) charging the capacitor is related to the rate of change of charge as \( I = \frac{dQ}{dt} \). Thus, \( \frac{dE}{dt} = \frac{I}{\epsilon_0 A} \).
07
Formulate the Displacement Current Density Equation
Substitute \( \frac{dE}{dt} \) into the displacement current density formula: \( J_d = \epsilon_0 \frac{I}{\epsilon_0 A} = \frac{I}{A} \). Since \( A = \pi R^2 \), it simplifies to \( J_d = \frac{I}{\pi R^2} \).
08
Conclude the Expression for Displacement Current Density
Verify that the expression \( J_d = \epsilon_0 \frac{dE}{dt} \) holds true under the conditions that \( r \leq R \), fitting the model for the capacitor configuration described.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Capacitance
Capacitance is a measure of a capacitor's ability to store electric charge. It is defined by the formula:
In simple terms, capacitance tells us how much charge a capacitor can hold for a given voltage. The larger the capacitance, the more charge the capacitor can store.
In a parallel-plate capacitor, the capacitance is affected by:
- \( C = \frac{Q}{V} \)
In simple terms, capacitance tells us how much charge a capacitor can hold for a given voltage. The larger the capacitance, the more charge the capacitor can store.
In a parallel-plate capacitor, the capacitance is affected by:
- The area of the plates \( (A) \)
- The distance between the plates \( (d) \)
- The material between the plates, known as the dielectric
- \( C = \frac{\epsilon_0 A}{d} \)
Electric Field
An electric field is a region around a charged object where a force is exerted on other charges. It describes the influence a charge exerts on its surroundings. The electric field \( E \) between parallel plates is uniform and can be given by the formula:
In a charging parallel-plate capacitor, the electric field changes over time as the charge builds up on the plates. This time-varying characteristic is crucial for understanding the concept of displacement current.
The fact that the electric field is uniform between the plates guarantees constant force and energy interaction when moving a charge from one plate to the other. This uniformity breaks down at the edges of the plates, resulting in a slight effect known as "fringing fields."
- \( E = \frac{V}{d} \)
In a charging parallel-plate capacitor, the electric field changes over time as the charge builds up on the plates. This time-varying characteristic is crucial for understanding the concept of displacement current.
The fact that the electric field is uniform between the plates guarantees constant force and energy interaction when moving a charge from one plate to the other. This uniformity breaks down at the edges of the plates, resulting in a slight effect known as "fringing fields."
Parallel-Plate Capacitor
A parallel-plate capacitor is a simple and common type of capacitor consisting of two parallel conductive plates separated by an insulating material, the dielectric. When a voltage is applied across the plates, they accumulate equal and opposite charges, creating a uniform electric field between them.
The capacitance \( C \) of a parallel-plate capacitor is determined by the formula:
Parallel-plate capacitors are widely used because they are straightforward and easy to manufacture. They are excellent for applications where large capacitance values are required in a limited space. They also serve a vital role in smoothing power supplies and tuning radio frequencies.
The capacitance \( C \) of a parallel-plate capacitor is determined by the formula:
- \( C = \frac{\epsilon_r \epsilon_0 A}{d} \)
Parallel-plate capacitors are widely used because they are straightforward and easy to manufacture. They are excellent for applications where large capacitance values are required in a limited space. They also serve a vital role in smoothing power supplies and tuning radio frequencies.
Permittivity of Free Space
The permittivity of free space, also known as the electric constant, is a physical constant denoted by \( \epsilon_0 \). It quantifies the ability of free space to permit electric field lines. Its approximate value is \( 8.854 \times 10^{-12} \text{ F/m} \).
In the context of parallel-plate capacitors, \( \epsilon_0 \) appears in the formula for capacitance:
Permittivity also plays a fundamental role in Coulomb's law, which describes the force between two charges in a vacuum. It is a constant used throughout electromagnetism and is essential for understanding how electric fields propagate in different media.
In the context of parallel-plate capacitors, \( \epsilon_0 \) appears in the formula for capacitance:
- \( C = \frac{\epsilon_0 A}{d} \)
Permittivity also plays a fundamental role in Coulomb's law, which describes the force between two charges in a vacuum. It is a constant used throughout electromagnetism and is essential for understanding how electric fields propagate in different media.
- Influences the speed of light in a vacuum: \( c = \frac{1}{\sqrt{\mu_0 \epsilon_0}} \)
- Integral to Maxwell's equations, which govern electromagnetism