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An electric generator contains a coil of 100 turns of wire, each forming a rectangular loop \(50.0 \mathrm{~cm}\) by \(30.0 \mathrm{~cm}\). The coil is placed entirely in a uniform magnetic field with magnitude \(B=4.30 \mathrm{~T}\) and with \(\vec{B}\) initially perpendicular to the coil's plane. What is the maximum value of the emf produced when the coil is spun at \(1278 \mathrm{rev} / \mathrm{min}\) about an axis perpendicular to \(\vec{B}\) ?

Short Answer

Expert verified
The maximum emf produced is approximately 864.34 V.

Step by step solution

01

Understand the Problem

We need to determine the maximum electromotive force (emf) produced by a rotating rectangular coil in a magnetic field. The key formula for the emf generated in a coil rotating in a magnetic field is derived from Faraday's Law of Induction: \[ \varepsilon = -N \frac{d\Phi}{dt} \]where \(N\) is the number of turns, and \(\Phi\) is the magnetic flux.
02

Calculate the Magnetic Flux

The magnetic flux \(\Phi\) is given by the formula:\[ \Phi = B \times A \times \cos(\theta) \]Initially, \(\cos(\theta) = 1\) because the magnetic field is perpendicular to the coil. The area \(A\) of one coil is:\[ A = \text{length} \times \text{width} = 0.50 \times 0.30 = 0.15 \text{ m}^2 \]Thus, the initial flux is:\[ \Phi = 4.30 \times 0.15 \times 1 = 0.645 \text{ Wb} \]
03

Compute Angular Velocity

The coil is spun at 1278 revolutions per minute (rpm). First, convert this to radians per second (rad/s):\[ \omega = 1278 \times \frac{2\pi}{60} \approx 133.91 \text{ rad/s} \]
04

Determine Maximum EMF

The maximum emf, \(\varepsilon_{max}\), occurs when the change in flux is maximum, which happens when the coil is oriented such that \(\cos(\theta)\) changes most rapidly. The formula for emf is:\[ \varepsilon_{max} = N \cdot B \cdot A \cdot \omega \]Substitute the known values:\[ \varepsilon_{max} = 100 \times 4.30 \times 0.15 \times 133.91 \approx 864.34 \text{ V} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Magnetic Flux
Magnetic flux is a key concept in electromagnetism. It represents the number of magnetic field lines passing through a given surface. In the context of Faraday's Law of Induction, the magnetic flux through a loop of wire determines how much electromotive force (emf) is generated as the loop interacts with the magnetic field.

For a coil perpendicular to a magnetic field, the magnetic flux \( \Phi \) is calculated by:
  • \( \Phi = B \times A \times \cos(\theta) \)
  • \( B \) is the magnetic field strength (in Tesla, T).
  • \( A \) is the area of the coil (in square meters, m²).
  • \( \theta \) is the angle between the magnetic field and normal to the coil.
Initially, with \( \theta = 0 \), \( \cos(\theta) \) is 1, making the magnetic flux simply the product of the magnetic field and the coil's area. As the coil spins, this angle changes, affecting the flux and thus the induced emf.
Electromotive Force (EMF)
Electromotive force, or emf, is the voltage developed by any source of electrical energy such as a battery or a dynamo. In our context, it refers to the voltage generated due to the motion of a coil in a magnetic field. Faraday's Law of Induction describes how a change in magnetic flux can induce an emf in a conductor, as given by:
  • \( \varepsilon = -N \frac{d\Phi}{dt} \)
  • \( N \) is the number of turns in the coil.
  • \( \frac{d\Phi}{dt} \) is the rate of change of the magnetic flux through the coil.
The negative sign indicates the direction of induced emf as per Lenz's law, which states that the induced emf will oppose the change in flux causing it. The maximum emf is achieved when the rate of change of flux is highest, typically when the coil is moving fastest through the field perpendicularly.
Angular Velocity
Angular velocity is a measure of how fast something is rotating. It is commonly expressed in radians per second (rad/s). For a rotating coil in a magnetic field, angular velocity (\( \omega \)) is crucial because it dictates how rapidly the magnetic flux through the coil changes, directly affecting the emf produced.

To find angular velocity, convert the number of revolutions per minute (rpm) to rad/s:
  • Use the formula: \( \omega = \text{rpm} \times \frac{2\pi}{60} \)
In our exercise, the coil's angular velocity was calculated to be approximately 133.91 rad/s. This velocity influences the frequency of flux change, leading to the generation of maximum emf when the rotational speed is highest. Understanding angular velocity helps predict how efficient an electric generator can be as it transforms mechanical movement into electrical energy.

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Most popular questions from this chapter

A small circular loop of area \(2.00 \mathrm{~cm}^{2}\) is placed in the plane of, and concentric with, a large circular loop of radius \(1.00 \mathrm{~m}\). The current in the large loop is changed at a constant rate from \(50.0 \mathrm{~A}\) to \(-50.0 \mathrm{~A}\) (a change in direction) in a time of \(1.00 \mathrm{~s}\), starting at \(t=0\). What is the magnitude of the magnetic field \(\vec{B}\) at the center of the small loop due to the current in the large loop at (a) \(t=0\), (b) \(t=0.500 \mathrm{~s}\), and (c) \(t=1.00 \mathrm{~s}\) ? (d) From \(t=0\) to \(t=1.00 \mathrm{~s}\), is \(\vec{B}\) reversed? Because the inner loop is small, assume \(\vec{B}\) is uniform over its area. (e) What emf is induced in the small loop at \(t=0.500 \mathrm{~s}\) ?

Two identical long wires of radius \(a=0.530 \mathrm{~mm}\) are parallel and carry identical currents in opposite directions. Their center-tocenter separation is \(d=20.0 \mathrm{~cm}\). Neglect the flux within the wires but consider the flux in the region between the wires. What is the inductance per unit length of the wires?

Two long, parallel copper wires of diameter \(4.0 \mathrm{~mm}\) carry currents of \(7.0 \mathrm{~A}\) in opposite directions. (a) Assuming that their central axes are \(20 \mathrm{~mm}\) apart, calculate the magnetic flux per meter of wire that exists in the space between those axes. (b) What percentage of this flux lies inside the wires? (c) Repeat part (a) for parallel currents.

Coil 1 has \(L_{1}=35 \mathrm{mH}\) and \(N_{1}=100\) turns. Coil 2 has \(L_{2}=40 \mathrm{mH}\) and \(N_{2}=200\) turns. The coils are fixed in place; their mutual inductance \(M\) is \(9.0 \mathrm{mH}\). A \(6.0 \mathrm{~mA}\) current in coil 1 is changing at the rate of \(4.0 \mathrm{~A} / \mathrm{s}\). (a) What magnetic flux \(\Phi_{12}\) links coil 1 , and (b) what self-induced emf appears in that coil? (c) What magnetic flux \(\Phi_{21}\) links coil 2, and (d) what mutually induced emf appears in that coil?

At \(t=0\), a battery is connected to a series arrangement of a resistor and an inductor. If the inductive time constant is \(60.0 \mathrm{~ms}\), at what time is the rate at which energy is dissipated in the resistor equal to the rate at which energy is stored in the inductor's magnetic field?

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