Chapter 3: Problem 44
In the product \(\vec{F}=q \vec{v} \times \vec{B}\), take \(q=3\) $$ \vec{v}=2.0 \hat{\mathrm{i}}+4.0 \hat{\mathrm{j}}+6.0 \hat{\mathrm{k}} \text { and } \vec{F}=4.0 \hat{\mathrm{i}}-20 \hat{\mathrm{j}}+12 \hat{\mathrm{k}} $$ What then is \(\vec{B}\) in unit-vector notation if \(B_{x}=B_{y} ?\)
Short Answer
Expert verified
\(\vec{B} = -2 \hat{\mathrm{i}} - 2 \hat{\mathrm{j}} - \frac{8}{3} \hat{\mathrm{k}}\)
Step by step solution
01
Understand the Given Variables
We are given the equation \(\vec{F} = q \vec{v} \times \vec{B}\), where \(q = 3\), \(\vec{v} = 2.0 \hat{\mathrm{i}} + 4.0 \hat{\mathrm{j}} + 6.0 \hat{\mathrm{k}} \), and \(\vec{F} = 4.0 \hat{\mathrm{i}} - 20 \hat{\mathrm{j}} + 12 \hat{\mathrm{k}}\). We need to find \(\vec{B}\) assuming \(B_{x} = B_{y}\).
02
Set Up the Cross Product Formula
Using the cross product formula \(\vec{F} = q(\vec{v} \times \vec{B})\), we substitute for \(\vec{v}\) and \(\vec{B} = B_{x} \hat{\mathrm{i}} + B_{x} \hat{\mathrm{j}} + B_{z} \hat{\mathrm{k}}\):\[\vec{F} = 3 \begin{vmatrix} \hat{\mathrm{i}} & \hat{\mathrm{j}} & \hat{\mathrm{k}} \ 2.0 & 4.0 & 6.0 \ B_{x} & B_{x} & B_{z} \end{vmatrix}\]
03
Compute the Determinant for Cross Product
Compute the determinant:\[\vec{v} \times \vec{B} = \hat{\mathrm{i}} (4B_{z} - 6B_{x}) - \hat{\mathrm{j}} (2B_{z} - 6B_{x}) + \hat{\mathrm{k}} (2B_{x} - 4B_{x})\]Simplifying:\[= (4B_{z} - 6B_{x}) \hat{\mathrm{i}} - (2B_{z} - 6B_{x}) \hat{\mathrm{j}} + (-2B_{x}) \hat{\mathrm{k}}\]
04
Substitute and Solve for \(B_x\) and \(B_z\)
Multiply the result by 3 (since \(q=3\)), equate to \(\vec{F}\): \[3[(4B_{z} - 6B_{x}) \hat{\mathrm{i}} - (2B_{z} - 6B_{x}) \hat{\mathrm{j}} + (-2B_{x}) \hat{\mathrm{k}}] = 4.0 \hat{\mathrm{i}} - 20 \hat{\mathrm{j}} + 12 \hat{\mathrm{k}}\]This gives:\[12B_{z} - 18B_{x} = 4 \]\[-6B_{z} + 18B_{x} = -20 \]\[-6B_{x} = 12 \]
05
Solve the Equations
From \(-6B_{x} = 12\), solve for \(B_{x}\):\[B_{x} = -2\]Substitute \(B_{x}\) into the first equation:\[12B_{z} - 18(-2) = 4 \Rightarrow 12B_{z} + 36 = 4 \Rightarrow 12B_{z} = -32 \Rightarrow B_{z} = -\frac{8}{3}\]
06
Write the Final Vector \(\vec{B}\)
Now that we have \(B_{x} = -2\) and \(B_{z} = -\frac{8}{3}\), the vector \(\vec{B}\) is:\[\vec{B} = -2 \hat{\mathrm{i}} - 2 \hat{\mathrm{j}} - \frac{8}{3} \hat{\mathrm{k}}\]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Vector Cross Product
The vector cross product is a fundamental operation used in physics and engineering to find a vector that is perpendicular to two other vectors. In the context of magnetic forces, it allows us to determine the direction and magnitude of the force experienced by a charged particle in a magnetic field. The calculation involves taking the cross product of two vectors: the velocity of the charged particle (\(\vec{v}\)) and the magnetic field (\(\vec{B}\)). The expression for the magnetic force is given by:
The cross product of two vectors \(\vec{A} = a_1\, \hat{\mathrm{i}} + a_2\, \hat{\mathrm{j}} + a_3\, \hat{\mathrm{k}}\) and \(\vec{B} = b_1\, \hat{\mathrm{i}} + b_2\, \hat{\mathrm{j}} + b_3\, \hat{\mathrm{k}}\) is calculated using the determinant of a matrix:
- \(\vec{F} = q (\vec{v} \times \vec{B})\)
The cross product of two vectors \(\vec{A} = a_1\, \hat{\mathrm{i}} + a_2\, \hat{\mathrm{j}} + a_3\, \hat{\mathrm{k}}\) and \(\vec{B} = b_1\, \hat{\mathrm{i}} + b_2\, \hat{\mathrm{j}} + b_3\, \hat{\mathrm{k}}\) is calculated using the determinant of a matrix:
- \[\vec{A} \times \vec{B} = \begin{vmatrix} \hat{\mathrm{i}} & \hat{\mathrm{j}} & \hat{\mathrm{k}} \ a_1 & a_2 & a_3 \ b_1 & b_2 & b_3 \end{vmatrix}\]
Vector Notation
In physics, vectors are quantities that have both magnitude and direction. Vector notation is a way of representing these quantities mathematically using unit vectors. A unit vector is a vector of length one that points in a specific direction. Common unit vectors include:
\(\vec{v} = 2.0 \hat{\mathrm{i}} + 4.0 \hat{\mathrm{j}} + 6.0 \hat{\mathrm{k}}\)indicates that it has components of 2, 4, and 6 in the x, y, and z directions, respectively. Using vector notation simplifies the manipulation of vectors and makes the mathematics more understandable and manageable to work with during problem-solving.
- \(\hat{\mathrm{i}}\) for the x-direction
- \(\hat{\mathrm{j}}\) for the y-direction
- \(\hat{\mathrm{k}}\) for the z-direction
\(\vec{v} = 2.0 \hat{\mathrm{i}} + 4.0 \hat{\mathrm{j}} + 6.0 \hat{\mathrm{k}}\)indicates that it has components of 2, 4, and 6 in the x, y, and z directions, respectively. Using vector notation simplifies the manipulation of vectors and makes the mathematics more understandable and manageable to work with during problem-solving.
Physics Problem Solving
Solving physics problems, like the one dealing with vectors in a magnetic field, involves a combination of understanding the physics principles at play and performing accurate mathematical calculations. The steps are generally:
- Identify known quantities and what you need to determine. Establish the connections between them using relevant formulas. Here, the formula \(\vec{F} = q(\vec{v} \times \vec{B})\) helps us find \(\vec{B}\).
- Set up the mathematical operation needed, such as the cross product in this exercise. Convert the problem into mathematical equations using vector notation.
- Perform the calculations with care, adjusting for any specific conditions stated, like setting \(B_x = B_y\) here.
- Re-examine your solution, especially if there are physical constraints or conditions, ensuring the results make sense in the context of the problem.