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57 What is the excess charge on a conducting sphere of radius \(r=0.35 \mathrm{~m}\) if the potential of the sphere is \(1500 \mathrm{~V}\) and \(V=0\) at infinity?

Short Answer

Expert verified
The excess charge on the sphere is approximately \(5.84 \times 10^{-8} \text{ C}\).

Step by step solution

01

Understand the Problem

We need to find the excess charge on a conducting sphere. We are given the radius of the sphere as \(r = 0.35 \text{ m}\) and the potential of the sphere as \(1500 \text{ V}\). The reference potential (\(V = 0\)) is set at infinity.
02

Use the Formula for Potential of a Sphere

The potential \(V\) of a conducting sphere is given by the formula \(V = \frac{kQ}{r}\), where \(k\) is the Coulomb's constant \(8.99 \times 10^9 \text{ N m}^2/ ext{C}^2 \), \(Q\) is the charge on the sphere, and \(r\) is the radius of the sphere.
03

Rearrange the Formula to Solve for Charge

From the formula \(V = \frac{kQ}{r}\), rearrange to solve for \(Q\): \(Q = \frac{Vr}{k}\).
04

Substitute Known Values into the Equation

Substitute \(V = 1500 \text{ V}\), \(r = 0.35 \text{ m}\), and \(k = 8.99 \times 10^9 \text{ N m}^2/ ext{C}^2\) into the equation: \(Q = \frac{1500 \times 0.35}{8.99 \times 10^9}\).
05

Calculate the Charge

Perform the calculation: \(Q \approx \frac{525}{8.99 \times 10^9} \approx 5.84 \times 10^{-8} \text{ C}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conducting Sphere
A conducting sphere is a spherical object that can transfer electric charge freely across its surface. This is due to the conductive material that allows electrons to move easily from one part of the sphere to another.

When a conducting sphere is charged, the charge disperses uniformly over its surface. This is because like charges repel each other, spreading out as far as possible. Hence, the sphere's surface becomes an equipotential surface, meaning every point on the surface is at the same electric potential.

In electrostatics, conducting spheres are often used to analyze electric fields and potentials because they provide simplistic yet insightful models for understanding more complex systems. They exemplify the principle that the electric field inside a conductor in electrostatic equilibrium is zero. Therefore, charges reside only on the surface of the sphere.
Electric Potential
Electric potential, often denoted by 'V', is a measure of the potential energy per unit charge at a point in an electric field. It is a scalar quantity, meaning it only has magnitude and no direction.

Electric potential is crucial for understanding how charges interact within an electric field. It is defined as the work done to move a unit positive charge from a reference point (often infinity) to a specific point within the field. The SI unit of electric potential is the volt (V).
  • A positive test charge moved against the electric field experiences an increase in potential.
  • A negative test charge moved with the electric field also sees an increase in potential.
For a conducting sphere, the electric potential (V) at the surface is given by the formula: \[V = \frac{kQ}{r}\]where 'k' is Coulomb's constant, 'Q' is the charge, and 'r' is the radius. This formula gives insights into how a sphere's charge affects its surrounding potential.
Coulomb's Law
Coulomb's Law is a fundamental principle in electrostatics that quantifies the force between two point charges. It states that the electric force between two point charges is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The mathematical form of Coulomb's law is:\[F = k \frac{|q_1q_2|}{r^2}\]where:
  • 'F' is the magnitude of the force between the charges.
  • 'k' is the Coulomb's constant \(8.99 \times 10^9 \text{ N m}^2/\text{C}^2\).
  • 'q_1' and 'q_2' are the magnitudes of the charges.
  • 'r' is the distance between the centers of the two charges.
Coulomb's Law helps us understand the electrostatic interaction between charged objects. While the law itself deals with point charges, its fundamental concept is extendable to larger systems like conducting spheres, where charge can approximate as being concentrated at the sphere's center for computational simplicity.

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Most popular questions from this chapter

The electric potential \(V\) in the space between two flat parallel plates 1 and 2 is given (in volts) by \(V=1500 x^{2}\), where \(x\) (in meters) is the perpendicular distance from plate 1 . At \(x=1.8 \mathrm{~cm}\), (a) what is the magnitude of the electric field and (b) is the field directed toward or away from plate \(1 ?\)

A particle of charge \(q\) is fixed at point \(P\), and a second particle of mass \(m\) and the same charge \(q\) is initially held a distance \(r_{1}\) from \(P\). The second particle is then released. Determine its momentum magnitude when it is a distance \(r_{2}\) from \(P\). Let \(q=3.1 \mu \mathrm{C}\), \(m=20 \mathrm{mg}, r_{1}=0.90 \mathrm{~mm}\), and \(r_{2}=1.5 \mathrm{~mm}\).

The electric field in a region of space has the components \(E_{y}=E_{z}=0\) and \(E_{x}=\) \((4.00 \mathrm{~N} / \mathrm{C}) x^{2}\). Point \(A\) is on the \(y\) axis at \(y=3.00\) \(\mathrm{m}\), and point \(B\) is on the \(x\) axis at \(x=4.00 \mathrm{~m}\). What is the potential difference \(V_{B}-V_{A}\) ?

An electron is projected with an initial speed of \(1.6 \times 10^{5} \mathrm{~m} / \mathrm{s}\) directly toward a proton that is fixed in place. If the electron is initially a great distance from the proton, at what distance from the proton is the speed of the electron instantaneously equal to twice the initial value?

Two metal spheres, each of radius \(3.0 \mathrm{~cm}\), have a center-tocenter separation of \(2.0 \mathrm{~m}\). Sphere 1 has charge \(+1.0 \times 10^{-8} \mathrm{C}\); sphere 2 has charge \(-8.0 \times 10^{-8}\) C. Assume that the separation is large enough for us to say that the charge on each sphere is uniformly distributed (the spheres do not affect each other). With \(V=0\) at infinity, calculate (a) the potential at the point halfway between the centers and the potential on the surface of (b) sphere 1 and \((c)\) sphere 2 .

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