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An infinite line of charge produces a field of magnitude \(1.7 \times 10^{4} \mathrm{~N} / \mathrm{C}\) at distance \(9.0 \mathrm{~m}\). Find the field magnitude at distance \(2.0 \mathrm{~m}\).

Short Answer

Expert verified
The electric field at 2.0 m is \( 7.65 \times 10^4 \mathrm{~N/C} \).

Step by step solution

01

Understand the Formula

The electric field due to an infinite line of charge can be calculated using the formula: \( E = \frac{\lambda}{2\pi\epsilon_0 r} \), where \( E \) is the electric field, \( \lambda \) is the linear charge density, \( \epsilon_0 \) is the permittivity of free space, and \( r \) is the distance from the line of charge.
02

Rearrange the Formula

From the formula \( E = \frac{\lambda}{2\pi\epsilon_0 r} \), notice that the electric field \( E \) is inversely proportional to \( r \). Therefore, if the distance is reduced, the field increases. This can be expressed as \( E_1 r_1 = E_2 r_2 \).
03

Apply Given Values

We know the electric field at \( 9.0 \mathrm{~m} \) is \( 1.7 \times 10^4 \mathrm{~N/C} \). Let's call it \( E_1 \), and the distance \( r_1 = 9.0 \mathrm{~m} \). We need to compute \( E_2 \) at \( r_2 = 2.0 \mathrm{~m} \).
04

Solve for Unknown Field

Use the relation found in step 2: \( E_1 r_1 = E_2 r_2 \). Plug in the known values: \( (1.7 \times 10^4) \times 9.0 = E_2 \times 2.0 \). Solve for \( E_2 \).
05

Calculate and Conclude

Rearrange the equation to solve for \( E_2 \): \( E_2 = \frac{(1.7 \times 10^4) \times 9.0}{2.0} \). Calculate this to get \( E_2 = 7.65 \times 10^4 \mathrm{~N/C} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Infinite Line of Charge
An infinite line of charge is a theoretical concept used in physics to help understand electric fields. Imagine a straight line that extends infinitely in both directions, carrying a uniform charge along its length. Due to its infinite nature and uniform charge distribution, each small segment of the line contributes to generating an electric field around it.

In practice, this is a useful model because it allows us to make certain simplifications when calculating the electric fields produced by similarly shaped objects. For example, the field produced by such a line of charge at any point in space depends only on the perpendicular distance from the line, making the problem simpler to solve.
  • Symmetry: The infinite length ensures that the electric field lines are symmetric about the line.
  • Field Direction: The electric field at any point due to the line is directed radially outwards (or inwards, if the charge is negative) along the perpendicular direction to the line.
  • Constant Field Strength: The field strength decreases with distance, inversely proportional to the distance from the line of charge.
Understanding the electric fields produced by infinite lines of charge is essential for solving various problems in electrostatics, particularly those involving cylindrical symmetry.
Linear Charge Density
Linear charge density, denoted by the symbol \( \lambda \), is the charge per unit length along a line. It represents how much charge is distributed along a line of charge and is one of the fundamental quantities for determining the electric field due to that line.

Mathematically, it is expressed as:\[ \lambda = \frac{Q}{L} \] where \( Q \) is the total charge distributed along the length \( L \). For an infinite line of charge, \( \lambda \) is constant throughout its length.

Linear charge density is crucial for defining the electric field generated by an infinite line of charge using the formula: \[ E = \frac{\lambda}{2\pi\epsilon_0 r} \]where \( r \) is the distance from the line. Note that the higher the linear charge density, the stronger the electric field produced near the line.
  • Units: Linear charge density is measured in coulombs per meter (C/m).
  • Relation to Field: Directly proportional to the electric field; higher \( \lambda \) means a higher electric field at a given distance.
  • Practical Uses: It's often used in problems related to wires and cables where the charge is distributed over a length.
Working with linear charge density helps in understanding the relationship between charge distribution and the resulting electric fields.
Permittivity of Free Space
The permittivity of free space, denoted as \( \epsilon_0 \), is a constant that describes how electric fields behave in a vacuum. It is a key factor in Coulomb's law and in determining the capacitance of capacitors in free space. Its role becomes evident when calculating the electric fields from various charge distributions.

In the context of the infinite line of charge, \( \epsilon_0 \) appears in the formula for calculating the electric field:\[ E = \frac{\lambda}{2\pi\epsilon_0 r} \]This constant effectively scales the field based on how charges interact in a vacuum environment.
  • Value: The permittivity of free space has a value of approximately \( 8.85 \times 10^{-12} \text{C}^2/\text{N} \cdot \text{m}^2 \).
  • Importance: It sets the scale for how strong the electric field is for a given charge configuration in free space.
  • Applications: It's a crucial parameter in defining the electric fields and potentials in vacuum conditions, and for understanding wave propagation in electromagnetism.
Understanding \( \epsilon_0 \) is essential for accurately describing electric phenomena in physics, particularly those that occur in vacuum or air-like conditions.

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Most popular questions from this chapter

A particle of charge \(6.3 \mu \mathrm{C}\) is at the center of a Gaussian cube \(92 \mathrm{~cm}\) on edge. (a) What is the net electric flux through the surface? (b) What is the net flux if the edge length is doubled?

An electron is shot directly toward the center of a large metal plate that has surface charge density \(-1.50 \times 10^{-6} \mathrm{C} / \mathrm{m}^{2}\). If the initial kinetic energy of the electron is \(3.93 \times 10^{-17} \mathrm{~J}\) and if the electron is to stop (due to electrostatic repulsion from the plate) just as it reaches the plate, how far from the plate must the launch point be?

A particle of charge \(+q\) is placed at one corner of a Gaussian cube. What multiple of \(q / \varepsilon_{0}\) gives the flux through (a) each cube face forming that corner and (b) each of the other cube faces?

The electric field in a certain region of Earth's atmosphere directed vertically down. At an altitude of \(300 \mathrm{~m}\) the field has mag nitude \(75.0 \mathrm{~N} / \mathrm{C} ;\) at an altitude of \(200 \mathrm{~m}\), the magnitude is \(210 \mathrm{~N} / \mathrm{C}\) Find the net amount of charge contained in a cube \(100 \mathrm{~m}\) on edg with horizontal faces at altitudes of 200 and \(300 \mathrm{~m}\).

A long, straight wire has fixed negative charge with a linear charge density of magnitude \(5.2 \mathrm{nC} / \mathrm{m}\). The wire is to be enclosed by a coaxial, thin-walled nonconducting cylindrical shell of radius \(1.2 \mathrm{~cm}\). The shell is to have positive charge on its outside surface with a surface charge density \(\sigma\) that makes the net external electric field zero. Calculate \(\boldsymbol{\sigma}\).

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