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An electric dipole consisting of charges of magnitude \(1.50 \mathrm{nC}\) separated by \(6.20 \mu \mathrm{m}\) is in an electric field of strength \(300 \mathrm{~N} / \mathrm{C}\). What are (a) the magnitude of the electric dipole moment and (b) the difference between the potential energies for dipole orientations parallel and perpendicular to \(\vec{E}\) ?

Short Answer

Expert verified
(a) 9.30 x 10^{-15} C·m, (b) 2.79 x 10^{-12} J

Step by step solution

01

Calculate the Electric Dipole Moment

The electric dipole moment \( p \) is defined as the product of the charge \( q \) and the separation distance \( d \). In this scenario, \( q = 1.50 \times 10^{-9} \text{ C} \) and \( d = 6.20 \times 10^{-6} \text{ m} \). Thus, we calculate it as follows:\[ p = q \, d = 1.50 \times 10^{-9} \, \text{C} \times 6.20 \times 10^{-6} \, \text{m} = 9.30 \times 10^{-15} \text{ C} \cdot \text{m} \]
02

Potential Energy Difference Formula

The potential energy difference \( \Delta U \) between parallel and perpendicular orientations of a dipole in an electric field is given by the formula \( \Delta U = pE(\cos\theta_1 - \cos\theta_2) \). For parallel orientation, \( \theta_1 = 0^\circ \) and for perpendicular orientation, \( \theta_2 = 90^\circ \).
03

Evaluate Cosine Values

In the expression \( \cos\theta_1 = \cos(0^\circ) = 1 \) and \( \cos\theta_2 = \cos(90^\circ) = 0 \). Substitute these into the potential energy difference formula.
04

Calculate the Potential Energy Difference

Substitute the values into the equation from Step 2:\[ \Delta U = 9.30 \times 10^{-15} \, \text{C} \cdot \text{m} \times 300 \, \text{N/C} \times (1 - 0) \]\[ \Delta U = 2.79 \times 10^{-12} \, \text{J} \]
05

Finalize Answers

Having calculated the necessary quantities, the electric dipole moment is \( 9.30 \times 10^{-15} \, \text{C} \cdot \text{m} \) and the potential energy difference is \( 2.79 \times 10^{-12} \, \text{J} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electric Field
An electric field is an invisible force field surrounding electric charges. This field exerts force on other charges present within it. It's represented by the symbol \( E \) and measured in Newtons per Coulomb (N/C). The direction of the electric field is the direction in which a positive charge would move if placed within the field. In this exercise, the electric field strength is given as \( 300 \, \text{N/C} \). This means for every Coulomb of charge, there is a force of 300 Newtons acting upon it. Electric fields can cause charges to experience forces, creating potential energy differences and influencing orientations of dipoles.

Consider an electric dipole in this field; it consists of two equal but opposite charges. The electric field will exert opposite forces on these charges due to their difference in polarity. If aligned properly, the dipole experiences a torque, making it rotate to align with the field. The dipole's ability to turn in the electric field makes it possible to calculate the potential energy changes as its orientation changes.
Potential Energy Difference
When an electric dipole is placed in an electric field, it experiences changes in potential energy depending on its orientation. The potential energy of the dipole is lowest when it's aligned with the electric field and highest when it's perpendicular. This difference arises because the torque exerted by the field on the dipole depends on the angle between the dipole moment and the field.

The potential energy difference \( \Delta U \) between parallel and perpendicular orientations of a dipole in an electric field can be determined using the formula: \[ \Delta U = pE(\cos \theta_1 - \cos \theta_2) \]where \( p \) is the dipole moment, \( E \) is the electric field, and \( \theta_1 \) and \( \theta_2 \) are the angles corresponding to different orientations. For example, parallel orientation implies \( \theta_1 = 0^\circ \) and perpendicular \( \theta_2 = 90^\circ \), thus \( \cos 0^\circ = 1 \) and \( \cos 90^\circ = 0 \). This formula helps quantify the energy involved as the dipole transitions between these two states.
Dipole Orientation
The orientation of a dipole within an electric field is crucial for understanding the dipole's potential energy. A dipole consists of two oppositely charged points separated by a distance. These charges create a dipole moment represented by \( \vec{p} \), which has a magnitude equal to the product of the charge and the separation distance, and a direction from the negative to the positive charge.

Understanding dipole orientation- **Parallel to Electric Field**: When the dipole moment aligns with the electric field vector, the dipole has minimum potential energy. This is a stable orientation because it corresponds to the lowest energy state in the field.- **Perpendicular to Electric Field**: The dipole moment forms a right angle to the electric field. Here, it reaches maximum potential energy, which is a less stable orientation.

These orientations determine how much work is needed to position the dipole differently within the field. The torque trying to align it with the field line illustrates the physical principles at work, showing why substances with permanent dipoles like water align in external fields.

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Most popular questions from this chapter

At some instant the velocity components of an electron moving between two charged parallel plates are \(v_{x}=2.5 \times 10^{5} \mathrm{~m} / \mathrm{s}\) and \(v_{y}=5.0 \times 10^{3} \mathrm{~m} / \mathrm{s}\). Suppose the electric field between the plates is uniform and given by \(\vec{E}=(120 \mathrm{~N} / \mathrm{C}) \hat{\mathrm{j}}\). In unit-vector notation, what are (a) the electron's acceleration in that field and (b) the electron's velocity when its \(x\) coordinate has changed by \(2.0 \mathrm{~cm}\) ?

Density, density, density. (a) A charge \(-300 e\) is uniformly distributed along a circular arc of radius \(4.00 \mathrm{~cm}\), which subtends an angle of \(40^{\circ}\). What is the linear charge density along the arc? (b) A charge \(-300 e\) is uniformly distributed over one face of a circular disk of radius \(2.00 \mathrm{~cm}\). What is the surface charge density over that face? (c) A charge \(-300 e\) is uniformly distributed over the surface of a sphere of radius \(4.00 \mathrm{~cm}\). What is the surface charge density over that surface? (d) A charge \(-300 e\) is uniformly spread through the volume of a sphere of radius \(2.00 \mathrm{~cm}\). What is the volume charge density in that sphere?

An electron enters a region of uniform electric field with an initial velocity of \(30 \mathrm{~km} / \mathrm{s}\) in the same direction as the electric field, which has magnitude \(E=50 \mathrm{~N} / \mathrm{C}\). (a) What is the speed of the electron \(1.5 \mathrm{~ns}\) after entering this region? (b) How far does the electron travel during the \(1.5 \mathrm{~ns}\) interval?

A uniform electric field exists in a region between two oppositely charged plates. An electron is released from rest at the surface of the negatively charged plate and strikes the surface of the opposite plate, \(3.0 \mathrm{~cm}\) away, in a time \(1.5 \times 10^{-8} \mathrm{~s}\). Just as the electron strikes the second plate, what are its (a) momentum magnitude and (b) kinetic energy? (c) What is the magnitude of the electric field \(\vec{E}\) ?

An electric dipole consists of charges \(+2 e\) and \(-2 e\) separated by \(0.85 \mathrm{~nm}\). It is in an electric field of strength \(3.4 \times 10^{6} \mathrm{~N} / \mathrm{C}\). Calculate the magnitude of the torque on the dipole when the dipole moment is (a) parallel to, (b) perpendicular to, and (c) antiparallel to the electric field.

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