Chapter 21: Problem 6
Three particles are fixed on an \(x\) axis. Particle 1 of charge \(q_{1}\) is at \(x=-a\), and particle 2 of charge \(q_{2}\) is at \(x=+a\). If their net electrostatic force on particle 3 of charge \(+Q\) is to be zero, what must be the ratio \(q_{1} / q_{2}\) when particle 3 is at (a) \(x=+0.750 a\) and (b) \(x=+1.50 a\) ?
Short Answer
Step by step solution
Understanding the Problem
Electrostatic Force Equation
Force Equation for Particle 3 at x=+0.750a
Solve for Ratio at x=+0.750a
Force Equation for Particle 3 at x=+1.50a
Solve for Ratio at x=+1.50a
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coulomb's Law
- \( F \) is the magnitude of the force between the charges
- \( k \) is Coulomb's constant, approximately \( 8.99 \times 10^9 \text{ N m}^2/\text{C}^2 \)
- \( q_1 \) and \( q_2 \) are the magnitudes of the two charges
- \( r \) is the distance between the centers of the two charges
Charge Distribution
- The magnitude of each charge
- The relative distance between each pair
- The positions along the axis, denoted by distance measurements from a reference point
Equilibrium of Forces
- Calculate the force each neighboring charge exerts on particle 3 using Coulomb's Law.
- Set these forces equal, since they must cancel each other.
- Solve the resulting equation to determine the required condition for equilibrium, like the charge ratio \( \frac{q_1}{q_2} \).