Chapter 18: Problem 5
Nonmetric version: (a) How long does a \(2.0 \times 10^{5} \mathrm{Btw} / \mathrm{h}\) water heater take to raise the temperature of 65 gal of water from \(70^{\circ} \mathrm{F}\) to \(100^{\circ} \mathrm{F}\) ? Metric version: (b) How long does a \(59 \mathrm{~kW}\) water heater take to raise the temperature of \(246 \mathrm{~L}\) of water from \(21^{\circ} \mathrm{C}\) to \(38^{\circ} \mathrm{C}\) ?
Short Answer
Step by step solution
Understand the Problem
Gather the Required Formulas
Calculate for Nonmetric Version
Calculate for Metric Version
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Heat transfer
- Conduction: Heat moves through a material or between materials that are in direct contact.
- Convection: Heat causes fluid (such as water or air) to move, carrying the heat with it.
- Radiation: Heat is transferred through electromagnetic waves without needing a medium.
Specific heat capacity
- In metric units, the specific heat capacity for water is approximately 4.186 kJ/(kg°C).
- In Imperial units, it is about 1 Btu/(lb°F).
Energy conversion
The power of the water heater (P) is pivotal in determining how quickly the heat energy is supplied. For instance, in the exercise:
- The nonmetric version of the heater has a power of 2.0 × 10 \( ^5 \) Btu/h.
- The metric system uses a power rating of 59 kW.
Water heating calculations
- Nonmetric: From 70°F to 100°F, giving a \( \Delta T = 30^ \circ F \).
- Metric: From 21°C to 38°C, so \( \Delta T = 17^ \circ C \).