/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 13 As a result of a temperature ris... [FREE SOLUTION] | 91Ó°ÊÓ

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As a result of a temperature rise of \(64^{\circ}\), a bar with a crack at its center buckles upward (Fig. 18-29). The fixed distance \(L_{0}\) is \(3.77 \mathrm{~m}\) and the coefficient of linear expansion of the bar is \(25 \times 10^{-6 / C}\). Find the rise \(x\) of the center.

Short Answer

Expert verified
The center rise \(x\) is approximately 11.16 cm.

Step by step solution

01

Understand the Problem

Given a bar with a crack at its center, it buckles upward when the temperature rises. The problem provides the original length \(L_0 = 3.77 \text{ m}\), a temperature change of \(64^{\circ} C\), and a coefficient of linear expansion \(\alpha = 25 \times 10^{-6} / ^{\circ}C\). We must determine how much the center of the bar rises, denoted as \(x\).
02

Calculate the Length Change

The change in length \(\Delta L\) due to the temperature change is given by the formula: \(\Delta L = \alpha L_0 \Delta T\). Substitute the known values: \[ \Delta L = (25 \times 10^{-6} / ^{\circ}C)(3.77 \text{ m})(64^{\circ} C) \approx 0.00604 \text{ m} \].
03

Relate Length Change to Rise

When the bar buckles, it forms an arc. The arc length \(L\) is \(L_0 + \Delta L\) and the change in length \(2x\) is due to the curve shape.Apply Pythagorean theorem to the triangle with base \(L_0 / 2\) and height \(x\): \( L = 2\sqrt{x^2 + (L_0/2)^2} \).
04

Solve for Height Rise \(x\)

The new length can be set as:\[ L_0 + \Delta L = 2\sqrt{x^2 + (L_0/2)^2} \].Substitute \(L_0 + \Delta L = 3.77604\), then solve for \(x\): \[ 3.77604 = 2\sqrt{x^2 + (3.77/2)^2} \]\[ 1.88802 = \sqrt{x^2 + 1.885^2} \]\[ 1.88802^2 = x^2 + 1.885^2 \]\[ 3.5645 = x^2 + 3.552025 \]\[ x^2 = 3.5645 - 3.552025 \]\[ x^2 = 0.012475 \]\[ x = \sqrt{0.012475} \approx 0.1116 \text{ m} \].
05

Round the Final Answer

Converting the result to centimeters gives \(x \approx 11.16 \text{ cm}\), which can be rounded depending on the required precision.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Coefficient of Linear Expansion
The Coefficient of Linear Expansion, often represented by the Greek letter \( \alpha \), is a measure of how much a given material expands per unit of length as the temperature increases. This coefficient is a crucial factor when dealing with thermal expansion, especially in structures that are temperature-sensitive or subjected to wide temperature variations.
The mathematical expression for linear expansion is given by:
\[ \Delta L = \alpha L_0 \Delta T \]
Here, \( \Delta L \) is the change in length, \( L_0 \) is the original length, and \( \Delta T \) is the temperature change. The coefficient of linear expansion \( \alpha \) has units of inverse degrees Celsius \(( / ^\circ C)\), reflecting how much unit length of the material expands per degree increase in temperature. In the context of this exercise, the bar has an \( \alpha \) value of \( 25 \times 10^{-6} / ^\circ C \), indicating moderate expansion per temperature unit.
Pythagorean Theorem
Often taught in mathematics, the Pythagorean Theorem is a fundamental principle in geometry that applies to right-angled triangles. It states that in such a triangle, the square of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the other two sides. Mathematically, this can be expressed as:
\[ c^2 = a^2 + b^2 \]
In this exercise, where the bar is experiencing buckling, the theorem helps to relate the change in the bar's geometry. When the bar bows upwards, it forms a curve that can be approximated as an arc. By envisioning half of this arc forming a right triangle, one can use the Pythagorean theorem. The hypotenuse is the effective new length of the bar section, while the legs are the height rise \( x \) and half the original length of the bar \(( L_0 / 2 )\). This creates a right triangle with:
\[ (L_0 + \Delta L)^2 = x^2 + (L_0/2)^2 \]
Thus, allowing us to solve for the height of the rise \( x \).
Temperature Change
Temperature Change, denoted as \( \Delta T \), refers to the difference in temperature causing physical or chemical changes in an object. In the context of materials and structures, this change can cause expansion or contraction, necessitating precise calculations to prevent potential damage or faults such as buckling or breaking.
The formula \( \Delta T = T_{ ext{final}} - T_{ ext{initial}} \) allows us to quantify this change. In our exercise, the temperature increased by \( 64^{\circ}C \), directly leading to the thermal expansion of the bar. As this change interacts with the Coefficient of Linear Expansion, it directly results in the bar's length change \( \Delta L \), contributing to the upward buckling observed.
Buckling
Buckling is a fundamental engineering concept that refers to the sudden bending or bulging of structural components subjected to compressive forces or stress, such as those caused by thermal expansion. In the context of a bar, like the one in this exercise, buckling occurs when the bar's length changes due to a temperature increase, causing it to deviate from its original shape.
When a structural element like our bar expands but is not free to elongate due to fixed constraints, such as being fixed at both ends, it results in an upward movement or buckling. This phenomenon can lead to significant structural issues if not correctly anticipated or accommodated, making understanding and predicting the effects of buckling essential in structural engineering.
In this scenario, calculations involving the coefficient of linear expansion and the Pythagorean theorem enable us to predict how much the bar will buckle or rise, ensuring structures remain safe and functional despite temperature fluctuations.

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Most popular questions from this chapter

Ice has formed on a shallow pond, and a steady state has been reached, with the air above the ice at \(-5.0^{\circ} \mathrm{C}\) and the bottom of the pond at \(4.0^{\circ} \mathrm{C}\). If the total depth of ice \(+\) water is \(2.0 \mathrm{~m}\), how thick is the ice? (Assume that the thermal conductivities of ice and water are \(0.40\) and \(0.12 \mathrm{cal} / \mathrm{m} \cdot \mathrm{C}^{\circ} \cdot \mathrm{s}\), respectively. \()\)

How much water remains unfrozen after \(50.2 \mathrm{~kJ}\) is transferred as heat from \(240 \mathrm{~g}\) of liquid water initially at its freezing point?

In a solar water heater, energy from the Sun is gathered by water that circulates through tubes in a rooftop collector. The solar radiation enters the collector through a transparent cover and warms the water in the tubes; this water is pumped into a holding tank. Assume that the efficiency of the overall system is \(25 \%\) (that is, \(80 \%\) of the incident solar energy is lost from the system). What collector area is necessary to raise the temperature of 200 L of water in the tank from \(20^{\circ} \mathrm{C}\) to \(40^{\circ} \mathrm{C}\) in \(1.0 \mathrm{~h}\) when the intensity of incident sunlight is \(750 \mathrm{~W} / \mathrm{m}^{2} ?\)

(a) Two \(40 \mathrm{~g}\) ice cubes are dropped into \(200 \mathrm{~g}\) of water in a thermally insulated container. If the water is initially at \(25^{\circ} \mathrm{C}\), and the ice comes directly from a freezer at \(-15^{\circ} \mathrm{C}\), what is the final temperature at thermal equilibrium? (b) What is the final temperature if only one ice cube is used?

A \(150 \mathrm{~g}\) copper bowl contains \(260 \mathrm{~g}\) of water, both at \(20.0^{\circ} \mathrm{C}\) A very hot \(300 \mathrm{~g}\) copper cylinder is dropped into the water, causing the water to boil, with \(5.00 \mathrm{~g}\) being converted to steam. The final temperature of the system is \(100^{\circ} \mathrm{C}\). Neglect energy transfers with the environment. (a) How much energy (in calories) is transferred to the water as heat? (b) How much to the bowl? (c) What is the original temperature of the cylinder?

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