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Two waves are generated on a string of length \(4.0 \mathrm{~m}\) to produce a three-loop standing wave with an amplitude of \(1.0 \mathrm{~cm}\). The wave speed is \(100 \mathrm{~m} / \mathrm{s}\). Let the equation for one of the waves be of the form \(y(x, t)=y_{m} \sin (k x+\omega t)\). In the equation for the other wave, what are (a) \(y_{m}\), (b) \(k\), (c) \(\omega\), and (d) the sign in front of \(\omega\) ?

Short Answer

Expert verified
(a) 0.5 cm, (b) \(\frac{3\pi}{4}\), (c) 75\pi, (d) Negative.

Step by step solution

01

Analyze given information

We know a standing wave is formed by the superposition of two traveling waves. The standing wave has a length of 4 m, an amplitude of 1 cm, and a wave speed of 100 m/s. It forms 3 loops, meaning it has three half-wavelengths, allowing us to find the wavelength.
02

Calculate the wavelength

Since there are 3 loops, the string length is equal to three half-wavelengths. Thus, \[ 3 \left( \frac{\lambda}{2} \right) = 4 \text{ m} \] Solving for \( \lambda \) gives: \[ \lambda = \frac{4 \times 2}{3} = \frac{8}{3} \text{ m} \].
03

Determine wave number \(k\)

The wave number \(k\) is given by the expression: \[ k = \frac{2\pi}{\lambda} \] Substituting \( \lambda = \frac{8}{3} \text{ m}\): \[ k = \frac{2\pi}{8/3} = \frac{3\pi}{4} \].
04

Determine angular frequency \(\omega\)

The angular frequency \(\omega\) is related to the wave speed \(v\) by the equation: \[ \omega = v \cdot k \] Substituting \(v = 100 \text{ m/s}\) and \(k = \frac{3\pi}{4}\): \[ \omega = 100 \times \frac{3\pi}{4} = 75\pi \].
05

Determine amplitude \(y_m\)

For the standing wave resultant from two identical waves traveling in opposite directions, the amplitude of each wave is equal to half the total amplitude of the standing wave. Given amplitude is 1 cm, therefore, \[ y_{m} = \frac{1.0}{2} = 0.5 \text{ cm} \].
06

Determine sign in front of \(\omega\) in second wave

For one wave propagating in the positive direction, the other must propagate in the negative direction for a standing wave to result. Thus, the sign in front of \(\omega\) for the equation of the other wave will be negative.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Wave Speed
Wave speed is a fundamental concept in understanding how waves move through a medium, such as a string. The wave speed determines how quickly the crests and troughs of the wave travel along this medium. In the context of standing waves, like those formed on a string, the wave speed is crucial in calculating other wave characteristics, such as wavelength and frequency. For example, in our exercise, the given wave speed is 100 m/s, which is a measure of how fast the wave propagates across the 4-meter string.

To find the wave speed mathematically, we use the formula:
  • Wave speed \[ v = f \lambda \]where \(f\) is the frequency, and \(\lambda\) is the wavelength.
  • Alternatively, it can also be determined by the product of wave number \(k\) and angular frequency \(\omega\), \[ v = \frac{\omega}{k} \]
Knowing the wave speed helps in analyzing the dynamics of wave motion, and it affects how quickly and how often the standing wave patterns will shift on a string.
Wave Number
The wave number, represented as \(k\), is another important parameter for analyzing wave behavior, particularly in standing wave phenomena. It describes the number of wave cycles in a unit distance and is directly related to the wavelength \(\lambda\). In simple terms, the wave number tells us how tightly the wave is compressed.

Mathematically, wave number \(k\) can be defined using the formula:
  • Wave number \[ k = \frac{2\pi}{\lambda} \]in radians per meter.
For our standing wave with a calculated wavelength of \(\frac{8}{3}\) meters, substituting into this equation gives the wave number as \(\frac{3\pi}{4}\).

The wave number is significant because it helps identify the spatial characteristics of the wave oscillations, crucial for understanding wave interference and resonance patterns in standing waves.
Angular Frequency
Angular frequency \(\omega\) is a measure of how fast the wave oscillates as it propagates through a medium. It is expressed in radians per second and is closely tied to both the wave speed and the wave number. For traveling waves, this concept is critical in predicting the temporal oscillation behavior of particles within the medium.

The relationship between angular frequency \(\omega\) and wave speed \(v\) with wave number \(k\) is given by:
  • Angular frequency \[ \omega = v \times k \]
In our wave exercise, using this formula and known values \(v = 100\) m/s and \(k = \frac{3\pi}{4}\), we calculated the angular frequency to be \(75\pi\).

This frequency helps describe how rapidly the energy is transferred through the wave, which is essential for analyzing standing wave patterns and their resulting characteristic frequencies.
Wavelength
Wavelength \(\lambda\) is the distance between successive crests or troughs of a wave. It's a fundamental measure of the wave's size and is crucial in determining other wave parameters, such as frequency and wave number.

In the case of standing waves, understanding the wavelength is key to visualizing how these waves form, especially in confined mediums like strings. Here's how you can determine the wavelength in a standing wave:
  • For a string with 3 loops, as given in the exercise, the total length relates to wavelength as:\[ 3 \left( \frac{\lambda}{2} \right) = 4 \, \text{m} \]
  • Solving this provides the wavelength \[ \lambda = \frac{8}{3} \text{ m} \]
The wavelength reflects how the wave pattern fits within the boundary conditions of the string, thus determining how many half-waves or loops are formed.

Understanding the wavelength is vital for predicting how standing waves appear and behave on different mediums, which is a foundational concept in wave phenomena.

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Most popular questions from this chapter

Two sinusoidal waves of the same frequency are to be sent in the same direction along a taut string. One wave has an amplitude of \(5.50 \mathrm{~mm}\), the other \(12.0 \mathrm{~mm}\). (a) What phase difference \(\phi_{1}\) between the two waves results in the smallest amplitude of the resultant wave? (b) What is that smallest amplitude? (c) What phase difference \(\phi_{2}\) results in the largest amplitude of the resultant wave? (d) What is that largest amplitude? (e) What is the resultant amplitude if the phase angle is \(\left(\phi_{1}-\phi_{2}\right) / 2 ?\)

The following two waves are sent in opposite directions on a horizontal string so as to create a standing wave in a vertical plane: $$ \begin{aligned} &y_{1}(x, t)=(6.00 \mathrm{~mm}) \sin (12.0 \pi x-300 \pi t) \\ &y_{2}(x, t)=(6.00 \mathrm{~mm}) \sin (12.0 \pi x+300 \pi t) \end{aligned} $$ with \(x\) in meters and \(t\) in seconds. An antinode is located at point \(A\). In the time interval that point takes to move from maximum upward displacement to maximum downward displacement, how far does each wave move along the string?

What phase difference between two identical traveling waves, moving in the same direction along a stretched string, results in the combined wave having an amplitude \(0.852\) times that of the common amplitude of the two combining waves? Express your answer in (a) degrees, (b) radians, and (c) wavelengths.

A string has mass \(2.00 \mathrm{~g}\), wave speed \(120 \mathrm{~m} / \mathrm{s}\), and tension \(7.00\) N. (a) What is its length? (b) What is the lowest resonant frequency of this string?

A string fixed at both ends is \(7.50 \mathrm{~m}\) long and has a mass of \(0.120 \mathrm{~kg}\). It is subjected to a tension of \(96.0 \mathrm{~N}\) and set oscillating. (a) What is the speed of the waves on the string? (b) What is the longest possible wavelength for a standing wave? (c) Give the frequency of that wave.

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