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What fraction of the volume of an iceberg (density \(917 \mathrm{~kg} / \mathrm{m}^{3}\) ) would be visible if the iceberg floats (a) in the ocean (salt water, density \(1024 \mathrm{~kg} / \mathrm{m}^{3}\) ) and (b) in a river (fresh water, density \(1000 \mathrm{~kg} / \mathrm{m}^{3}\) )? (When salt water freezes to form ice, the salt is excluded. So, an iceberg could provide fresh water to a community.)

Short Answer

Expert verified
10.5% of the iceberg is visible in salt water, 8.3% in fresh water.

Step by step solution

01

Understanding the Problem

We need to find the visible fraction of the iceberg's volume above the water when it floats in both salt and fresh water. This involves calculating the buoyant force and applying Archimedes' principle.
02

Applying Archimedes' Principle

Archimedes' principle states that the buoyant force is equal to the weight of the displaced water. Therefore, the volume of displaced water multiplied by the density of the water will equal the weight of the iceberg.
03

Finding the Iceberg's Volume Under Water

Let \( V_t \) be the total volume of the iceberg, \( V_w \) be the volume of the iceberg that is submerged, and \( \rho_i \) and \( \rho_w \) be the densities of ice and water respectively. According to Archimedes', \( \rho_i V_t = \rho_w V_w \). Solving for \( V_w \), we have \( V_w = \frac{\rho_i}{\rho_w}V_t \).
04

Calculating Fraction Under Water for Salt Water

Substitute \( \rho_i = 917 \text{ kg/m}^3 \) and \( \rho_w = 1024 \text{ kg/m}^3 \) into \( V_w = \frac{\rho_i}{\rho_w}V_t \). So, \( V_w = \frac{917}{1024}V_t \). The fraction of the iceberg under salt water is \( \frac{917}{1024} \approx 0.895 \).
05

Calculating Fraction Above Water for Salt Water

The fraction of the iceberg above water (visible fraction) in salt water is \( 1 - 0.895 = 0.105 \).
06

Calculating Fraction Under Water for Fresh Water

Now repeat the calculation for fresh water: substitute \( \rho_w = 1000 \text{ kg/m}^3 \) into \( V_w = \frac{917}{1000}V_t \). This gives \( V_w = \frac{917}{1000} \approx 0.917 \).
07

Calculating Fraction Above Water for Fresh Water

The fraction of the iceberg above water (visible fraction) in fresh water is \( 1 - 0.917 = 0.083 \).
08

Final Calculations and Interpretation

Hence, approximately 10.5% of the iceberg's volume is visible in salt water and 8.3% in fresh water.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Buoyant Force
When an object is submerged in a fluid, a force acts upon it pushing it up, countering gravity. This is known as the buoyant force. In simple terms, the buoyant force is what allows objects to float, and it's all due to the pressure difference exerted by the fluid on different parts of the submerged body. Think of how a ball pushes back up when you try to push it underwater.
This force can be calculated using Archimedes' principle. Archimedes taught us that the buoyant force is equal to the weight of the fluid that the object displaces. When you place an object in water, it pushes some of the water out of the way. The volume of this displaced water determines the buoyant force.
Key points about buoyant force include:
  • It acts in the upward direction.
  • The magnitude of the buoyant force is equal to the weight of the displaced fluid.
  • It's what makes objects float or sink depending on their density relative to the fluid.
This is why understanding the concept of buoyant force is essential in determining how objects behave in fluids, like our iceberg example.
Density of Water
Density is a measure of how much mass exists per unit volume. In the context of our iceberg example, the density of the water plays a crucial role due to the nature of the buoyant force.
Water density varies depending on its salinity. Saltwater is denser than freshwater because it contains dissolved salts. This means that more mass is packed into the same volume compared to freshwater.
Let's consider how this affects the iceberg:
  • Saltwater has a density of approximately \(1024 \: \mathrm{kg/m}^3\), while freshwater is \(1000 \: \mathrm{kg/m}^3\).
  • This higher density of saltwater offers more buoyant force per unit volume displaced than freshwater. As a result, an iceberg displaces a smaller volume of saltwater to balance its weight compared to freshwater.
This difference in densities is why icebergs appear to float higher in saltwater than in freshwater.
Fraction of Submerged Volume
The fraction of an object's volume submerged refers to the proportion of the object that is beneath the surface of the liquid. It depends on both the object's density and the density of the fluid it's in. For an iceberg floating in water, this is a practical application of how buoyant force and density work together.
Using Archimedes' principle, you can determine how much of the iceberg is submerged in either saltwater or freshwater. By calculating the ratio of the density of ice to the density of the water, we find out what fraction of the iceberg remains below the water's surface.
Let's break it down further using our iceberg example:
  • For saltwater, the submerged volume fraction is calculated as \( \frac{917}{1024} \approx 0.895 \), meaning 89.5% of the iceberg is immersed.
  • In freshwater, it is \( \frac{917}{1000} \approx 0.917 \), indicating 91.7% of the iceberg is submerged.
The result is that more of the iceberg stays below the surface in freshwater compared to saltwater. Thus, even small differences in fluid density can significantly impact the visibility and stability of floating objects.

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Most popular questions from this chapter

A piston of cross-sectional area \(a\) is used in a hydraulic press to exert a small force of magnitude \(f\) on the enclosed liquid. A connecting pipe leads to a larger piston of cross-sectional area \(A\) (Fig. 14-31). (a) What force magnitude \(F\) will the larger piston sustain without moving? (b) If the piston diameters are \(3.50 \mathrm{~cm}\) and \(60.0 \mathrm{~cm}\), what force magnitude on the large piston will balance a \(20.0 \mathrm{~N}\) force on the small piston?

Blood pressure in Argentinosaurus. (a) If this long-necked, gigantic sauropod had a head height of \(18 \mathrm{~m}\) and a heart height of \(8.0 \mathrm{~m}\), what (hydrostatic) gauge pressure in its blood was required at the heart such that the blood pressure at the brain was 80 torr (just enough to perfuse the brain with blood)? Assume the blood had a density of \(1.06 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\). (b) What was the blood pressure (in torr or \(\mathrm{mm} \mathrm{Hg}\) ) at the feet?

A spring of spring constant \(3.75 \times 10^{4} \mathrm{~N} / \mathrm{m}\) is between a rigid beam and the output piston of a hydraulic lever. An empty container with negligible mass sits on the input piston. The input piston has area \(A_{i}\), and the output piston has area \(18.0 A_{2}\). Initially the spring is at its rest length. How many kilograms of sand must be (slowly) poured into the container to compress the spring by \(5.00 \mathrm{~cm}\) ?

Calculate the hydrostatic difference in blood pressure between the brain and the foot in a person of height \(1.50 \mathrm{~m}\). The density of blood is \(1.06 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\).

Giraffe bending to drink. In a giraffe with its head \(1.8 \mathrm{~m}\) above its heart, and its heart \(2.0 \mathrm{~m}\) above its feet, the (hydrostatic) gauge pressure in the blood at its heart is 250 torr. Assume that the giraffe stands upright and the blood density is \(1.06 \times 10^{3} \mathrm{~kg} / \mathrm{m}^{3}\).In torr (or \(\mathrm{mm} \mathrm{Hg}\) ), find the (gauge) blood pressure (a) at the brain (the pressure is enough to perfuse the brain with blood, to keep the giraffe from fainting) and (b) at the feet (the pressure must be countered by tight-fitting skin acting like a pressure stocking). (c) If the giraffe were to lower its head to drink from a pond without splaying its legs and moving slowly, what would be the increase in the blood pressure in the brain? (Such action would probably be lethal.)

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