/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 44 A Texas cockroach of mass \(0.20... [FREE SOLUTION] | 91Ó°ÊÓ

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A Texas cockroach of mass \(0.20 \mathrm{~kg}\) runs counterclockwise around the rim of a lazy Susan (a circular disk mounted on a vertical axle) that has radius \(18 \mathrm{~cm}\), rotational inertia \(5.0 \times 10^{-3} \mathrm{~kg} \cdot \mathrm{m}^{2}\), and frictionless bearings. The cockroach's speed (relative to the ground) is \(2.0 \mathrm{~m} / \mathrm{s}\), and the lazy Susan turns clockwise with angular speed \(\omega_{0}=2.8 \mathrm{rad} / \mathrm{s}\). The cockroach finds a bread crumb on the rim and, of course, stops. (a) What is the angular speed of the lazy Susan after the cockroach stops? (b) Is mechanical energy conserved as it stops?

Short Answer

Expert verified
(a) 11.6 rad/s (counterclockwise); (b) No, mechanical energy is not conserved.

Step by step solution

01

Understand the Conservation of Angular Momentum

In this problem, we'll apply the principle of conservation of angular momentum. Initially, both the cockroach and the lazy Susan are in motion. The cockroach is moving counterclockwise, while the disk is rotating clockwise. Since there are no external torques acting on the system, the total angular momentum must remain constant.
02

Calculate Initial Angular Momentum of the Cockroach

The cockroach moves at a speed of \(2.0 \text{ m/s}\) along a path with radius \(0.18 \text{ m}\). Therefore, its angular momentum is: \[ L_{c} = m v r = (0.20 \text{ kg})(2.0 \text{ m/s})(0.18 \text{ m}) = 0.072 \text{ kg} \cdot \text{m}^2/\text{s} \] This is counterclockwise, thus in the positive direction.
03

Calculate Initial Angular Momentum of the Lazy Susan

The initial angular momentum of the lazy Susan is \[ L_{ls,0} = I_{ls} \omega_{0} = (5.0 \times 10^{-3} \text{ kg} \cdot \text{m}^2)(2.8 \text{ rad/s}) = 0.014 \text{ kg} \cdot \text{m}^2/\text{s} \] This is clockwise, thus in the negative direction.
04

Formulate Total Initial Angular Momentum

The total initial angular momentum of the system combines both clockwise and counterclockwise contributions: \[ L_{i} = L_{c} - L_{ls,0} = 0.072 - 0.014 = 0.058 \text{ kg} \cdot \text{m}^2/\text{s} \]
05

Calculate Final Angular Momentum

After the cockroach stops, it no longer contributes any angular momentum. Therefore, the system's final angular momentum has only the lazy Susan's contribution: \[ L_{f} = I_{ls} \omega_{f} \] Conservation of angular momentum gives \[ L_{i} = L_{f} \] \[ 0.058 = (5.0 \times 10^{-3}) \omega_{f} \] Thus, \[ \omega_{f} = \frac{0.058}{5.0 \times 10^{-3}} = 11.6 \text{ rad/s} \] The lazy Susan spins counterclockwise at this new rate.
06

Determine if Mechanical Energy is Conserved

The initial kinetic energy combines both objects' movements: \[ KE_{i} = \frac{1}{2} m v^2 + \frac{1}{2} I_{ls} \omega_{0}^2 = \frac{1}{2}(0.20)(2.0)^2 + \frac{1}{2}(5.0 \times 10^{-3})(2.8)^2 \] \[ = 0.4 + 0.0196 = 0.4196 \text{ J} \] The final kinetic energy is only due to the lazy Susan: \[ KE_{f} = \frac{1}{2} I_{ls} \omega_{f}^2 = \frac{1}{2}(5.0 \times 10^{-3})(11.6)^2 = 0.3368 \text{ J} \] Since \( KE_{i} eq KE_{f} \), mechanical energy is not conserved.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conservation of Angular Momentum
The principle of conservation of angular momentum is a fundamental concept in rotational dynamics. It states that if no external torques act on a system, then the total angular momentum of the system remains constant. In our exercise involving a cockroach running on a lazy Susan (a rotating platform), both the cockroach and the lazy Susan contribute to the system's angular momentum. The cockroach runs counterclockwise, and the lazy Susan rotates clockwise. This opposing motion is key to applying the conservation law. Since there are no external influences altering this motion, the initial total angular momentum (sum of cockroach and lazy Susan) equals the final total after the cockroach stops. This principle helps us calculate the new angular speed of the lazy Susan, illustrating how internal redistribution of mass and speed affects motion without changing the entire system's angular momentum.
Rotational Inertia
Rotational inertia, also known as the moment of inertia, is the property of a body that determines how much it resists rotational acceleration around an axis. It depends both on the mass of the object and the distribution of that mass relative to the axis.For instance, in this problem, the lazy Susan has a given rotational inertia of \(5.0 \times 10^{-3} \text{ kg} \cdot \text{m}^2\). This value indicates how hard it is to change its rotational speed. The cockroach, being further from the axis of rotation, contributes rotational inertia as it moves, albeit indirectly, since it's not part of the lazy Susan itself.Rotational inertia plays a crucial role when analyzing how forces and mass distribution affect the rotation. A larger moment of inertia means the object is harder to spin, just like how the lazy Susan's inertia impacts its reaction to the moving cockroach.
Mechanical Energy Conservation
Mechanical energy conservation considers the total kinetic and potential energy in a system. For a system to conserve mechanical energy, these forms must remain constant over time in the absence of external work. In the given exercise, we examine whether mechanical energy is conserved as the cockroach stops on the lazy Susan. Initially, the system has kinetic energy from both the spinning lazy Susan and the cockroach's linear motion. When the cockroach halts, only the lazy Susan continues to rotate. Calculating both the initial and final kinetic energies reveals that the total mechanical energy decreases. This discrepancy indicates energy loss, perhaps transformed into other forms, such as heat due to internal friction or deformation. Hence, mechanical energy is not conserved despite angular momentum conservation, showcasing how different energy types behave under specific conditions.

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