/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 60 A thin rod of length \(0.75 \mat... [FREE SOLUTION] | 91Ó°ÊÓ

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A thin rod of length \(0.75 \mathrm{~m}\) and mass \(0.42 \mathrm{~kg}\) is suspended freely from one end. It is pulled to one side and then allowed to swing like a pendulum, passing through its lowest position with angular speed \(3.5\) rad/s. Neglecting friction and air resistance, find (a) the rod's kinetic energy at its lowest position and (b) how far above that position the center of mass rises.

Short Answer

Expert verified
(a) Kinetic energy = 0.483 J, (b) Center of mass rises 0.117 m.

Step by step solution

01

Find the moment of inertia of the rod

The moment of inertia \(I\) of a thin rod suspended from one end is given by \(I = \frac{1}{3} m L^2\), where \(m\) is the mass of the rod and \(L\) is its length. Substituting the given values, \(m = 0.42 \text{ kg}\) and \(L = 0.75 \text{ m}\), we get:\[I = \frac{1}{3} \times 0.42 \times (0.75)^2 = 0.07875 \, \text{kg} \cdot \text{m}^2\]
02

Calculate the kinetic energy at the lowest position

The kinetic energy \(KE\) of the pendulum at its lowest position is given by \(KE = \frac{1}{2} I \omega^2\), where \(\omega\) is the angular speed. Using \(I = 0.07875 \text{ kg} \cdot \text{m}^2\) and \(\omega = 3.5 \text{ rad/s}\), we calculate:\[KE = \frac{1}{2} \times 0.07875 \times (3.5)^2 = 0.4828125 \, \text{J}\]
03

Determine the height the center of mass rises

Using conservation of energy, the maximum potential energy when the center of mass rises is equal to the kinetic energy at the lowest position: \(mgh = KE\). Solving for \(h\), we have:\[h = \frac{KE}{mg} = \frac{0.4828125}{0.42 \times 9.8} = 0.11744 \, \text{m}\]Thus, the center of mass rises approximately \(0.117 \text{ m}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Moment of Inertia
Moment of inertia sounds complicated, but it's quite simple once you get the hang of it. It's like the rotational equivalent of mass in linear motion. Think of it as how much an object resists spinning. The larger the moment of inertia, the harder it is to change its rotational speed.
In the context of our pendulum, a rod, suspended from one end has a moment of inertia calculated by the formula:
  • \( I = \frac{1}{3} m L^2 \)
  • Here, \( m \) is the mass and \( L \) is the length of the rod.
For our exercise, we substitute the given values: length \( L = 0.75 \) meters and mass \( m = 0.42 \) kg into the equation. This results in a moment of inertia \( I = 0.07875 \text{ kg} \cdot \text{m}^2 \).
Understanding moment of inertia helps us see why heavier or longer objects take more energy to rotate. Try imagining why a long stick is harder to twirl compared to a small bat. It's all about distribution of mass relative to the pivot point.
Kinetic Energy
Kinetic energy is simply the energy of motion. Whenever an object is moving, it has kinetic energy. The faster it moves, or the more massive it is, the more kinetic energy it has.
When dealing with rotational motion, such as our pendulum, kinetic energy is calculated using the formula:
  • \( KE = \frac{1}{2} I \omega^2 \)
  • \( \omega \) is the angular velocity.
In our exercise, the rod's moment of inertia \( I = 0.07875 \text{ kg} \cdot \text{m}^2 \) and angular speed \( \omega = 3.5 \text{ rad/s} \). Plugging these values into the equation gives a kinetic energy of \( 0.4828125 \text{ J} \).
Here, think about kinetic energy as the ability of the rod to do work when moving. As the rod swings down to its lowest point, its potential energy gets converted into kinetic energy, making it swing faster.
Conservation of Energy
One of the most fundamental principles in physics is the conservation of energy, which states that energy cannot be created or destroyed, only transformed from one form to another. In a pendulum, this principle is beautifully illustrated.
As the pendulum swings, its energy shifts between potential energy and kinetic energy. At the highest points, it's all potential energy because it's not moving. At the lowest point, it's all kinetic energy because it's at its maximum speed.
For our exercise, The formula used is:
  • \( mgh = KE \)
  • Here, \( h \) is the height, \( m \) is the mass, and \( g \) is the acceleration due to gravity.
Conservation of energy tells us that the kinetic energy at the lowest point was once potential energy stored in the height the center of mass was lifted. By measuring the kinetic energy, we can find how high the center of mass rises: \( h = 0.11744 \text{ m} \).
This principle helps explain why a rollercoaster speeds up when descending and slows when climbing. It's the energy transformation at play – a never-ending transfer from one form to another, keeping the total energy constant.

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