/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 27 A seed is on a turntable rotatin... [FREE SOLUTION] | 91Ó°ÊÓ

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A seed is on a turntable rotating at \(33 \frac{1}{3} \mathrm{rev} / \mathrm{min}, 6.0 \mathrm{~cm} \mathrm{from}\) the rotation axis. What are (a) the seed's acceleration and (b) the least coefficient of static friction to avoid slippage? (c) If the turntable had undergone constant angular acceleration from rest in \(0.25 \mathrm{~s}\), what is the least coefficient to avoid slippage?

Short Answer

Expert verified
(a) 0.73 m/s²; (b) 0.074; (c) 0.113.

Step by step solution

01

Calculate the seed's tangential speed

First, convert the turntable's speed from revolutions per minute to radians per second. The speed given is \(33 \frac{1}{3} \text{ rev/min}\), which is \(\frac{100}{3}\text{ rev/min}\). We need to convert this to rad/s: \[ \text{speed} = \left(\frac{100}{3} \right) \times \left(\frac{2\pi}{60}\right) \approx 3.49 \text{ rad/s} \]
02

Calculate the seed's centripetal acceleration

Use the formula for centripetal acceleration: \( a = r\omega^2 \), where \( \omega = 3.49 \text{ rad/s} \) and \( r = 0.06 \text{ m} \).\[ a = 0.06 \times (3.49)^2 \approx 0.73 \text{ m/s}^2 \]
03

Determine the least coefficient of static friction to prevent slippage

The required coefficient of static friction is found using \( \mu_s = \frac{a}{g} \), where \( g = 9.8 \text{ m/s}^2 \). \[ \mu_s = \frac{0.73}{9.8} \approx 0.074 \]
04

Calculate the angular acceleration for part (c)

If the turntable accelerates from rest to \(3.49 \text{ rad/s}\) in \(0.25 \, s\), use the formula \( \alpha = \frac{\Delta \omega}{\Delta t} \). \[ \alpha = \frac{3.49 - 0}{0.25} = 13.96 \text{ rad/s}^2 \]
05

Determine the total acceleration for part (c)

The total acceleration will be the vector sum of the tangential acceleration \(a_t = r\alpha\) and the centripetal acceleration \(a_c = r\omega^2\). Calculate \(a_t\):\[ a_t = 0.06 \times 13.96 = 0.8376 \text{ m/s}^2 \]The initial centripetal acceleration is zero since start from rest. The maximum centripetal acceleration is \(0.73 \text{ m/s}^2\) as previously calculated. The total acceleration is found using the Pythagorean theorem for these perpendicular components:\[ a = \sqrt{a_t^2 + a_c^2} = \sqrt{0.8376^2 + 0.73^2} \approx 1.11 \text{ m/s}^2 \]
06

Calculate the least coefficient of static friction during angular acceleration

Use the total acceleration from step 5 to calculate the least coefficient of static friction: \[ \mu_s = \frac{a}{g} = \frac{1.11}{9.8} \approx 0.113 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Static Friction and its Role
Static friction is the force that keeps an object in place when an external force is applied. In the context of a turntable, it's the friction between the surface of the turntable and the seed on top of it. This friction prevents the seed from slipping off as the turntable spins.

Static friction is different from kinetic friction. It's what you must overcome for motion to start, but once the object is moving, kinetic friction takes over. The maximum static friction force is proportional to the normal force, often the weight of the object in straightforward scenarios like ours. This proportionality is expressed with the coefficient of static friction, \( \mu_s \):
  • \( F_s = \mu_s \times F_N \)
  • Where \( F_s \) is the static friction force, and \( F_N \) is the normal force.
To find the least \( \mu_s \) required to keep the seed from slipping due to centripetal acceleration, you use the formula: \( \mu_s = \frac{a}{g}\), where \( a \) is the centripetal acceleration and \( g \) is the gravitational acceleration (approximately \( 9.8 \,\text{m/s}^2 \)).

Understanding static friction is crucial for problems like this because it allows us to determine the minimum grip needed to keep the seed in place on the rotating surface.
Understanding Angular Acceleration
Angular acceleration is the rate of change of angular velocity over time. In simpler terms, it's how quickly an object speeding up or slowing down its rotation. Angular acceleration is crucial when dealing with rotational motion, such as with our turntable example.

In mathematical terms, angular acceleration (\( \alpha \)) can be calculated by the change in angular velocity (\( \Delta \omega \)) over the change in time (\( \Delta t \)):
  • \( \alpha = \frac{\Delta \omega}{\Delta t} \)
Angular acceleration affects the tangential acceleration of an object on the rotating path. This can be calculated with the radius (\( r \)) of the rotation:
  • \( a_t = r \alpha \)
For instance, if the turntable undergoes angular acceleration, the seed experiences tangential acceleration along with centripetal acceleration. These accelerations are perpendicular to each other, and their combined effect is calculated using the Pythagorean theorem.
  • \( a = \sqrt{a_t^2 + a_c^2} \)
This combined acceleration influences the required static friction to prevent slippage. If there's greater angular acceleration, a higher static friction coefficient is necessary.
Insights into Turntable Physics
Turntable physics explores the fascinating dynamics involved when an object is placed on a rotating platform. In our particular example, the seed on the turntable experiences two primary forces: tangential and centripetal forces.

Turntables revolve around a central axis, which means objects on their surface follow a circular path. The speed of this rotation, initially given in revolutions per minute (rpm), must be converted into more precise scientific units such as radians per second for physics calculations.
  • Conversion formula: \( \text{speed} = \left( \frac{rpm \times 2\pi}{60} \right) \)
This conversion is crucial for calculating other parameters like angular velocity and acceleration. Within turntable physics:
  • **Centripetal force** keeps objects moving along a curved path. It is directed towards the center of the rotation.
  • **Tangential velocity** reflects how fast an object moves along the path at any given point. It's calculated from the linear speed.
  • **Angular dynamics** concern how rotational variables like velocity and acceleration affect and interact with objects on the rotating surface.
A comprehensive grasp of these principles is imperative in predicting and managing the real-world motion of objects, such as seeds on turntables or playground merry-go-rounds.

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Most popular questions from this chapter

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